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What is the difference between the following symbols in chemical equations: \(\longrightarrow\) and \(\rightleftharpoons ?\)

Short Answer

Expert verified
In chemistry, the symbol \(\longrightarrow\) is used to denote a complete or irreversible reaction where reactants convert entirely into the products with no reverse reaction. On the other hand, the symbol \(\rightleftharpoons\) represents equilibrium reactions, where reactants and products convert into each other at the same rate, resulting in unchanging concentrations.

Step by step solution

01

Explaining the meaning of the symbol \(\longrightarrow\)

In chemical equations, the symbol \(\longrightarrow\) is used to denote a complete or irreversible reaction. These reactions are ones where reactants convert entirely into products, and there's no reverse reaction.
02

Explaining the meaning of the symbol \(\rightleftharpoons\)

The symbol \(\rightleftharpoons\) thoughtfully represents equilibrium reactions. These are reactions in which the conversion from reactants to products and products to reactants occur simultaneously. Thus, an equilibrium state is defined as a dynamic state where the concentrations of reactants and products are unchanging.
03

Contrasting the two symbols

These two symbols - \(\longrightarrow\) and \(\rightleftharpoons\) - represent significantly different scenarios in chemical reactions. The first one, \(\longrightarrow\), depicts a one-way, complete transformation of reactants into products. In contrast, the second symbol, \(\rightleftharpoons\), illustrates a dynamic state of balance between reactants and products.

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Most popular questions from this chapter

Calculate the molarity of each of the following solutions: (a) \(29.0 \mathrm{~g}\) of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) in \(545 \mathrm{~mL}\) of solution, (b) \(15.4 \mathrm{~g}\) of sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) in \(74.0 \mathrm{~mL}\) of solution, (c) \(9.00 \mathrm{~g}\) of sodium chloride \((\mathrm{NaCl})\) in \(86.4 \mathrm{~mL}\) of solution.

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