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What are the steps in balancing nuclear equations?

Short Answer

Expert verified
The steps in balancing nuclear equations are identifying the type of nuclear reaction, balancing nucleons, balancing charges, and verifying atomic and mass numbers on both sides.

Step by step solution

01

Identify the type of nuclear reaction

Based on the given nuclear equation, identify if it is a type of alpha decay, beta decay, gamma decay, positron emission, or electron capture. This information is crucial to predict what the product of the nuclear reaction will be.
02

Balance the nucleons

Nucleons are particles in the atomic nucleus and include protons and neutrons. Both sides of the equation should have the same total number of nucleons. This is based on the law of conservation of mass where the total number of nucleons before the reaction equals the total number after the reaction.
03

Balance the charges

Charges have to be balanced in the equation. This is based on the law of conservation of charge, where the net charge before the reaction must be equal to the net charge after the reaction. This requires that the sum of the proton numbers (atomic numbers) of the reactants equals the sum of the proton numbers of the products.
04

Cross check the Atomic and Mass Numbers

The atomic numbers and mass numbers in both sides of the equation should be checked and verified to ensure that they are equal. If the totals on both sides match, then the equation is balanced.

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Most popular questions from this chapter

The quantity of a radioactive material is often measured by its activity (measured in curies or millicuries) rather than by its mass. In a brain scan procedure, a 70 -kg patient is injected with \(20.0 \mathrm{mCi}\) of \({ }^{99 \mathrm{~m}} \mathrm{Tc}\) which decays by emitting \(\gamma\) -ray photons with a halflife of \(6.0 \mathrm{~h}\). Given that the \(\mathrm{RBE}\) of these photons is 0.98 and only two-thirds of the photons are absorbed by the body, calculate the rem dose received by the patient. Assume all of the \({ }^{99 \mathrm{~m}}\) Tc nuclei decay while in the body. The energy of a gamma photon is \(2.29 \times 10^{-14} \mathrm{~J}\).

In each pair of isotopes shown, indicate which one you would expect to be radioactive: (a) \({ }_{10}^{20} \mathrm{Ne}\) and \({ }_{10}^{17} \mathrm{Ne},(\mathrm{b}){ }_{20}^{40} \mathrm{Ca}\) and \({ }_{20}^{45} \mathrm{Ca},(\mathrm{c}){ }_{44}^{95} \mathrm{Mo}\) and \({ }_{43}^{92} \mathrm{Tc},(\mathrm{d}){ }_{80}^{195} \mathrm{Hg}\) and \({ }^{196} \mathrm{Hg},\) (e) \({ }^{209} \mathrm{Bi}\) and \({ }_{96}^{242} \mathrm{Cm}\)

Each molecule of hemoglobin, the oxygen carrier in blood, contains four Fe atoms. Explain how you would use the radioactive \({ }_{26}^{59} \mathrm{Fe}\left(t_{\frac{1}{2}}=46\right.\) days) to show that the iron in a certain food is converted into hemoglobin.

Consider the decay series \(\mathrm{A} \longrightarrow \mathrm{B} \longrightarrow \mathrm{C} \longrightarrow \mathrm{D}\) where \(A, B,\) and \(C\) are radioactive isotopes with halflives of \(4.50 \mathrm{~s}, 15.0\) days, and \(1.00 \mathrm{~s},\) respectively, and \(\mathrm{D}\) is nonradioactive. Starting with 1.00 mole of A, and none of \(\mathrm{B}, \mathrm{C},\) or \(\mathrm{D},\) calculate the number of moles of \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) left after 30 days.

Why is strontium-90 a particularly dangerous isotope for humans?

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