For reactions carried out under standard-state conditions, Equation (18.10)
takes the form \(\Delta G^{\circ}=\Delta H^{\circ}-\) \(T \Delta S^{\circ} .\)
(a) Assuming \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) are independent of
temperature, derive the equation $$\ln \frac{K_{2}}{K_{1}}=\frac{\Delta
H^{\circ}}{R}\left(\frac{T_{2}-T_{1}}{T_{1} T_{2}}\right)$$ where \(K_{1}\) and
\(K_{2}\) are the equilibrium constants at \(T_{1}\) and \(T_{2}\), respectively.
(b) Given that at \(25^{\circ} \mathrm{C} K_{\mathrm{c}}\) is \(4.63 \times
10^{-3}\) for the reaction $$ \mathrm{N}_{2} \mathrm{O}_{4}(g)
\rightleftharpoons 2 \mathrm{NO}_{2}(g) \quad \Delta H^{\circ}=58.0
\mathrm{~kJ} / \mathrm{mol} $$ calculate the equilibrium constant at
\(65^{\circ} \mathrm{C}\)