Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Arrange the following substances ( 1 mole each) in order of increasing entropy at \(25^{\circ} \mathrm{C}:\) (a) \(\mathrm{Ne}(g)\), (b) \(\mathrm{SO}_{2}(g),\) (c) \(\mathrm{Na}(s)\) (d) \(\mathrm{NaCl}(s)\) (e) \(\mathrm{H}_{2}(g)\). Give the reasons for your arrangement.

Short Answer

Expert verified
The substances arranged in order of increasing entropy at \(25^{\circ} \mathrm{C}\) are \(\mathrm{Na}(s)\), \(\mathrm{NaCl}(s)\), \(\mathrm{Ne}(g)\), \(\mathrm{H}_{2}(g)\), and \(\mathrm{SO}_{2}(g)\). This is based on their phases of matter and level of molecular complexity.

Step by step solution

01

Order based on phase

Consider the phase of matter. Generally, gases have more entropy than solids because molecules in a gas can move freely and randomly fill their container, while molecules in a solid are fixed in a lattice. Therefore, placing \(\mathrm{Na}(s)\) and \(\mathrm{NaCl}(s)\) at the lower end of the scale, \(\mathrm{Ne}(g)\), \(\mathrm{SO}_{2}(g)\) and \(\mathrm{H}_{2}(g)\) go towards the higher end.
02

Order within the same phase

Among the gases, distinguish them based on molecular complexity. More complex molecules have more entropy due to the higher number of possible configurations or arrangements of their atoms. \(\mathrm{SO}_{2}(g)\) is a more complex molecule than \(\mathrm{H}_{2}(g)\) and \(\mathrm{Ne}(g)\) are, so it will have more entropy. Among the two remaining gases, \(\mathrm{H}_{2}(g)\) has two atoms while neon is a monatomic gas, so \(\mathrm{H}_{2}(g)\) will have slightly more entropy.
03

Final Order

The final order of substances in increasing entropy would therefore be: \(\mathrm{Na}(s)\) < \(\mathrm{NaCl}(s)\) < \(\mathrm{Ne}(g)\) < \(\mathrm{H}_{2}(g)\) < \(\mathrm{SO}_{2}(g)\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Complexity
Understanding the concept of molecular complexity is crucial when exploring entropy, which is a measure of a system's disorder. Entropy can be thought of as the number of ways a system can be arranged. The more complex a molecule is, the greater its entropy, as there are more possible configurations for its atoms.

Consider the example of sulfur dioxide (\textbf{SO}\(_2\)), hydrogen (\textbf{H}\(_2\)), and neon (\textbf{Ne}). Each of these substances has a different level of molecular complexity. Sulfur dioxide, with its three atoms and multiple vibrational modes, has a higher molecular complexity compared to the simpler diatomic hydrogen or the monatomic neon.

As a result, \textbf{SO}\(_2\) has more ways to store energy within its structure, resulting in higher entropy. This is important when arranging substances in order of increasing entropy; the more complex the molecular structure, the higher the position on the scale.
States of Matter
When discussing entropy, it's essential to differentiate between the states of matter: solids, liquids, and gases. In the context of the exercise, we focus on solids and gases, where the behavior of particles differs greatly.

Molecules in a solid are closely packed and organized in a fixed lattice, which restricts their motion and limits the entropy. In contrast, gases are composed of molecules that move freely and randomly, which allows for a higher number of accessible microstates, resulting in greater entropy.

Therefore, when arranging substances by entropy, a solid such as sodium (\textbf{Na}) or sodium chloride (\textbf{NaCl}) would be placed at the lower end, while gases like neon (\textbf{Ne}), hydrogen (\textbf{H}\(_2\)), and sulfur dioxide (\textbf{SO}\(_2\)) rank higher, based on their ability to disperse and occupy a volume with less restriction.
Thermodynamics
The field of thermodynamics provides a framework for understanding energy transfer within systems, and entropy is a cornerstone concept within this domain. It thereby connects molecular complexity and the states of matter through the second law of thermodynamics, which states that the total entropy of an isolated system can never decrease over time.

This law ensures that systems tend to move towards a state of greater disorder or randomness, which is why, given the chance, substances transform from solids to gases. The exercise illustrates this fundamental thermodynamic principle by arranging substances in the order of increasing entropy.

In practice, not only the state of matter (solid, liquid, or gas) determines entropy but also temperature, pressure, and intrinsic molecular properties. These factors collectively dictate how energy is distributed within a system, shaping the system's entropy profile. Therefore, accurate predictions on entropy order require consideration of all these interrelated thermodynamic elements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For a reaction with a negative \(\Delta G^{\circ}\) value, which of the following statements is false? (a) The equilibrium constant \(K\) is greater than one, (b) the reaction is spontaneous when all the reactants and products are in their standard states, and (c) the reaction is always exothermic.

For each pair of substances listed here, choose the one having the larger standard entropy value at \(25^{\circ} \mathrm{C}\). The same molar amount is used in the comparison. Explain the basis for your choice. (a) \(\operatorname{Li}(s)\) or \(\operatorname{Li}(l)\) (b) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)\) or \(\mathrm{CH}_{3} \mathrm{OCH}_{3}(l)\) (c) \(\operatorname{Ar}(g)\) or \(\operatorname{Xe}(g)\) (d) \(\mathrm{CO}(g)\) or \(\mathrm{CO}_{2}(g)\) (e) \(\mathrm{O}_{2}(g)\) or \(\mathrm{O}_{3}(g)\) (f) \(\mathrm{NO}_{2}(g)\) or \(\mathrm{N}_{2} \mathrm{O}_{4}(g)\)

Consider the following reaction at \(25^{\circ} \mathrm{C}\) : $$ \mathrm{Fe}(\mathrm{OH})_{2}(s) \rightleftharpoons \mathrm{Fe}^{2+}(a q)+2 \mathrm{OH}^{-}(a q) $$ Calculate \(\Delta G^{\circ}\) for the reaction. \(K_{\mathrm{sp}}\) for \(\mathrm{Fe}(\mathrm{OH})_{2}\) is \(1.6 \times 10^{-14}\).

Without consulting Appendix \(2,\) predict whether the entropy change is positive or negative for each of the following reactions. Give reasons for your predictions. (a) \(2 \mathrm{KClO}_{4}(s) \longrightarrow 2 \mathrm{KClO}_{3}(s)+\mathrm{O}_{2}(g)\) (b) \(\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)\) (c) \(2 \mathrm{Na}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NaOH}(a q)+\mathrm{H}_{2}(g)\) (d) \(\mathrm{N}_{2}(g) \longrightarrow 2 \mathrm{~N}(g)\)

Under what conditions does a substance have a standard entropy of zero? Can a substance ever have a negative standard entropy?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free