Chapter 15: Problem 94
The equilibrium constant \(K_{\mathrm{c}}\) for the reaction \(2 \mathrm{NH}_{3}(g) \rightleftharpoons \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g)\) is 0.83 at \(375^{\circ} \mathrm{C} . \mathrm{A}\) 14.6-g sample of ammonia is placed in a 4.00 -L flask and heated to \(375^{\circ} \mathrm{C}\). Calculate the concentrations of all the gases when equilibrium is reached.
Short Answer
Step by step solution
Conversion of Mass to Moles
Calculation of Initial Concentrations
Set up the ICE Table
Solve for x using the Equilibrium Constant
Calculate the Equilibrium Concentrations
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
ICE Table
An ICE table was utilized in the textbook problem to assist in calculating the equilibrium concentrations of ammonia, nitrogen, and hydrogen. By applying stoichiometry, we can denote the interdependence of these concentrations; once the equilibrium constant is introduced, we have a solvable equation to find the unknown variables.
Le Chatelier's Principle
In the context of our textbook problem, if the system at equilibrium at 375°C for the reaction involving ammonia, nitrogen, and hydrogen were subjected to a change, like a pressure increase, Le Chatelier's Principle predicts the system's shift towards the side with fewer moles of gas to reduce pressure. Understanding this principle helps predict the behavior of the reaction under different conditions, which is invaluable for manipulating reactions to favor the desired outcome.
Stoichiometry
Why Stoichiometry Is Key in Equilibrium Calculations
Stoichiometry forms the foundation of chemical reactions. It involves the quantitative relationship between reactants and products in a reaction. This relationship follows the balanced chemical equation and dictates how much of one substance reacts with another to form products. For equilibrium calculations, stoichiometry tells us the proportionate amounts of reactants that convert to products, guiding us in setting up conversion factors that help calculate the extent of a reaction.In our exercise, the reaction of ammonia decomposing into nitrogen and hydrogen follows a clear stoichiometric pattern: for every 2 moles of ammonia that react, 1 mole of nitrogen and 3 moles of hydrogen are produced. This ratio is pivotal as it influences the coefficients used in the ICE table and is applied in calculating equilibrium concentrations.
Equilibrium Expression
The equilibrium constant for our ammonia reaction was given as 0.83, and the equilibrium expression for the reaction was used to solve for x, which represented the equilibrium concentration changes. Understanding how to craft and apply the equilibrium expression is crucial for solving equilibrium problems, as it embodies the quantitative aspects of the chemical equilibrium.