Chapter 14: Problem 39
What do we mean by the mechanism of a reaction?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 14: Problem 39
What do we mean by the mechanism of a reaction?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeA flask contains a mixture of compounds \(A\) and \(B\). Both compounds decompose by first-order kinetics. The half-lives are 50.0 min for \(A\) and 18.0 min for \(B\). If the concentrations of \(\mathrm{A}\) and \(\mathrm{B}\) are equal initially, how long will it take for the concentration of \(\mathrm{A}\) to be four times that of \(\mathrm{B} ?\)
For each of these pairs of reaction conditions, indicate which has the faster rate of formation of hydrogen gas: (a) sodium or potassium with water, (b) magnesium or iron with \(1.0 \mathrm{M} \mathrm{HCl}\), (c) magnesium rod or magnesium powder with \(1.0 \mathrm{M} \mathrm{HCl}\), (d) magnesium with \(0.10 M \mathrm{HCl}\) or magnesium with \(1.0 \mathrm{M} \mathrm{HCl}\).
Consider the reaction $$ \mathrm{A}+\mathrm{B} \longrightarrow \text { products } $$ From these data obtained at a certain temperature, determine the order of the reaction and calculate the rate constant: $$ \begin{array}{ccc} {[\mathrm{A}](\mathrm{M})} & {[\mathrm{B}](M)} & \text { Rate }(M / \mathrm{s}) \\ \hline 1.50 & 1.50 & 3.20 \times 10^{-1} \\ 1.50 & 2.50 & 3.20 \times 10^{-1} \\ 3.00 & 1.50 & 6.40 \times 10^{-1} \end{array} $$
The thermal decomposition of phosphine \(\left(\mathrm{PH}_{3}\right)\) into phosphorus and molecular hydrogen is a first-order reaction: $$ 4 \mathrm{PH}_{3}(g) \longrightarrow \mathrm{P}_{4}(g)+6 \mathrm{H}_{2}(g) $$ The half-life of the reaction is 35.0 s at \(680^{\circ} \mathrm{C}\). Calculate (a) the first-order rates constant for the reaction and (b) the time required for 95 percent of the phosphine to decompose.
The thermal decomposition of \(\mathrm{N}_{2} \mathrm{O}_{5}\) obeys firstorder kinetics. At \(45^{\circ} \mathrm{C}\), a plot of \(\ln \left[\mathrm{N}_{2} \mathrm{O}_{5}\right]\) versus \(t\) gives a slope of \(-6.18 \times 10^{-4} \mathrm{~min}^{-1}\). What is the half-life of the reaction?
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