Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write the Arrhenius equation and define all terms.

Short Answer

Expert verified
The Arrhenius equation is given by \(k = Ae^{-Ea/RT}\), where 'k' is the rate constant, 'A' is the pre-exponential factor, 'Ea' is the activation energy, 'R' is the Universal gas constant, and 'T' is the absolute temperature.

Step by step solution

01

Write the Arrhenius Equation

Firstly, write down the Arrhenius equation itself. It is \(k = Ae^{-Ea/RT}\), in which k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the universal gas constant, and T is the temperature.
02

Define 'k'

'k' denotes the rate constant. It is the proportionality factor in the rate equation that indicates the relationship between the rate of a chemical reaction and the concentrations of reactants.
03

Define 'A'

'A' stands for the pre-exponential factor, also known as the frequency factor. It basically provides a measure of the frequency of the collisions in the correct orientation.
04

Define 'Ea'

'Ea' stands for the activation energy measured in J/mol. It is the minimum energy required to initiate a chemical reaction.
05

Define 'R'

'R' is the universal gas constant. In this equation it is usually given the value of 8.314 J/(mol • K).
06

Define 'T'

'T' represents the absolute temperature measured in Kelvin.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

As we know, methane burns readily in oxygen in a highly exothermic reaction. Yet a mixture of methane and oxygen gas can be kept indefinitely without any apparent change. Explain.

Consider the zero-order reaction \(\mathrm{A} \longrightarrow\) product. (a) Write the rate law for the reaction. (b) What are the units for the rate constant? (c) Plot the rate of the reaction versus [A].

A flask contains a mixture of compounds \(A\) and \(B\). Both compounds decompose by first-order kinetics. The half-lives are 50.0 min for \(A\) and 18.0 min for \(B\). If the concentrations of \(\mathrm{A}\) and \(\mathrm{B}\) are equal initially, how long will it take for the concentration of \(\mathrm{A}\) to be four times that of \(\mathrm{B} ?\)

Variation of the rate constant with temperature for the first-order reaction $$ 2 \mathrm{~N}_{2} \mathrm{O}_{5}(g) \longrightarrow 2 \mathrm{~N}_{2} \mathrm{O}_{4}(g)+\mathrm{O}_{2}(g) $$ is given in the following table. Determine graphically the activation energy for the reaction. $$ \begin{array}{lc} \mathrm{T}(\mathrm{K}) & \mathrm{k}\left(\mathrm{s}^{-1}\right) \\ \hline 273 & 7.87 \times 10^{3} \\ 298 & 3.46 \times 10^{5} \\ 318 & 4.98 \times 10^{6} \\ 338 & 4.87 \times 10^{7} \end{array} $$

A quantity of \(6 \mathrm{~g}\) of granulated \(\mathrm{Zn}\) is added to a solution of \(2 M \mathrm{HCl}\) in a beaker at room temperature. Hydrogen gas is generated. For each of the following changes (at constant volume of the acid) state whether the rate of hydrogen gas evolution will be increased, decreased, or unchanged: (a) \(6 \mathrm{~g}\) of powdered \(\mathrm{Zn}\) is used; \((\mathrm{b}) 4 \mathrm{~g}\) of granulated \(\mathrm{Zn}\) is used; \((\mathrm{c})\) \(2 M\) acetic acid is used instead of \(2 M \mathrm{HCl} ;\) d) temperature is raised to \(40^{\circ} \mathrm{C}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free