One glucose molecule, \(\mathrm{C}_{6} \mathrm{H}_{12}
\mathrm{O}_{6}(\mathrm{s}),\) is converted to two lactic acid molecules,
\(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}(\mathrm{s})\)
during glycolysis. Given the combustion reactions of glucose and lactic acid,
determine the standard enthalpy for glycolysis.
$$\begin{array}{r}
\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{s})+6
\mathrm{O}_{2}(\mathrm{g}) \longrightarrow 6 \mathrm{CO}_{2}(\mathrm{g})+6
\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \\
\Delta H^{\circ}=-2808 \mathrm{kJ}
\end{array}$$
$$\begin{aligned}
\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) & \mathrm{COOH}(\mathrm{s})+3
\mathrm{O}_{2}(\mathrm{g}) \longrightarrow \\
3 \mathrm{CO}_{2}(\mathrm{g})+3 \mathrm{H}_{2} \mathrm{O}(1) & \Delta
H^{\circ}=-1344 \mathrm{kJ}
\end{aligned}$$