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Construct a concept map encompassing the ideas behind the first law of thermodynamics.

Short Answer

Expert verified
Constructing a concept map for the first law of thermodynamics includes the following steps: understanding the law, identifying the key concepts related to the law, constructing the map starting from the main concept, building upon this with branches/sub-branches for each related concept, and finally, reviewing the concept map to assure it represents all main ideas in a logical and comprehensible way.

Step by step solution

01

Understand the First Law of Thermodynamics

Before constructing the concept map, understand what the first law of thermodynamics says: Energy cannot be created or destroyed, only transferred or transformed. This is also known as the law of energy conservation.
02

Identify the Key Concepts

Identify the key concepts related to the first law of thermodynamics. These could include: Energy, System, Surroundings, Energy Transformations, Heat, Work, Internal Energy, Conservation of Energy, Energy Transfer and Examples of energy transfer and transformation in natural systems.
03

Start Building the Concept Map

Start from the main concept (First Law of Thermodynamics), then develop branches for each related concept identified in Step 2. Each branch should symbolize a link or relationship between the main concept and the related concept.
04

Add Details to Each Concept Branch

To each branch, add additional nodes or sub-branches that provide more detail to each concept. For instance, under the 'Energy Transfer' branch, you can add examples of energy transfer like 'Heat Transfer' and 'Work Done', under 'Energy Transformation' add examples of energy transformations like 'Chemical to Mechanical energy' or 'Potential energy to Kinetic energy'.
05

Connect and Review the Concept Map

Look for connections between the different branches and link them if necessary. And finally, review the constructed concept map to make sure all the main ideas about the first law of thermodynamics are represented in a logical and comprehensible way.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Conservation
When we speak about the phrase 'energy can neither be created nor destroyed,' we are referring to the principle of energy conservation. This is a cornerstone of the first law of thermodynamics and a fundamental concept in physics. In essence, it tells us that the total amount of energy in an isolated system remains constant over time. What this means for practical applications is that energy may change form, such as from kinetic energy to potential energy, but the total energy will remain the same.

For example, when a roller coaster climbs a hill, the electrical energy that powers the motors is transformed into potential energy. As the coaster descends, that potential energy converts back into kinetic energy. Throughout these processes, despite the transformations, the sum total of energy in the system does not increase or decrease, it merely shifts from one form to another.
Energy Transformations
Energy is constantly on the move and changing into various forms around us. These changes are known as energy transformations. In a classroom scenario, an overhead projector converts electrical energy into light and sound energy to display a video clip. In nature, plants convert sunlight (solar energy) into chemical energy through photosynthesis—a process vital to life on Earth. We encounter these transformations on a daily basis - when we eat food, for instance, our bodies convert the chemical energy stored in the food into kinetic energy and thermal energy that keeps us warm and allows us to perform activities.

Understanding these transformations is integral to grasping the practical implications of the first law of thermodynamics and is particularly important in areas such as renewable energy development, where maximizing the efficiency of these transformations is key to sustainable technology.
Thermodynamics Concept Map
Creating a thermodynamics concept map can be a powerful tool for visualizing and understanding the relationships between different concepts related to energy and its behaviors. The map starts with the first law of thermodynamics at the center, branching out to encompass various related concepts such as system and surroundings, types of energy (kinetic, potential, thermal), and forms of energy transfer (work, heat).

Adding examples to each branch infuses the abstract concepts with real-world scenarios. For instance, under energy transfer, illustrating how heat transfers from a hot object to a cold one could be a useful example. Likewise, showcasing an engine converting chemical energy into mechanical energy can concretely demonstrate energy transformation. When creating a concept map, the goal is to make complex relationships more manageable by structuring the information in a visually intuitive way.

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Most popular questions from this chapter

In each of the following processes, is any work done when the reaction is carried out at constant pressure in a vessel open to the atmosphere? If so, is work done by the reacting system or on it? (a) Neutralization of \(\mathrm{Ba}(\mathrm{OH})_{2}(\mathrm{aq})\) by \(\mathrm{HCl}(\mathrm{aq}) ;\) (b) conversion of gaseous nitrogen dioxide to gaseous dinitrogen tetroxide; (c) decomposition of calcium carbonate to calcium oxide and carbon dioxide gas.

In the Are You Wondering \(7-1\) box, the temperature variation of enthalpy is discussed, and the equation \(q_{P}=\) heat capacity \(\times\) temperature change \(=C_{P} \times \Delta T\) was introduced to show how enthalpy changes with temperature for a constant-pressure process. Strictly speaking, the heat capacity of a substance at constant pressure is the slope of the line representing the variation of enthalpy (H) with temperature, that is $$C_{P}=\frac{d H}{d T} \quad(\text { at constant pressure })$$ where \(C_{P}\) is the heat capacity of the substance in question. Heat capacity is an extensive quantity and heat capacities are usually quoted as molar heat capacities \(C_{P, \mathrm{m}},\) the heat capacity of one mole of substance; an intensive property. The heat capacity at constant pressure is used to estimate the change in enthalpy due to a change in temperature. For infinitesimal changes in temperature, $$d H=C_{p} d T \quad(\text { at constant pressure })$$ To evaluate the change in enthalpy for a particular temperature change, from \(T_{1}\) to \(T_{2}\), we write $$\int_{H\left(T_{1}\right)}^{H\left(T_{2}\right)} d H=H\left(T_{2}\right)-H\left(T_{1}\right)=\int_{T_{1}}^{T_{2}} C_{P} d T$$ If we assume that \(C_{P}\) is independent of temperature, then we recover equation (7.5) $$\Delta H=C_{P} \times \Delta T$$ On the other hand, we often find that the heat capacity is a function of temperature; a convenient empirical expression is $$C_{P, \mathrm{m}}=a+b T+\frac{c}{T^{2}}$$ What is the change in molar enthalpy of \(\mathrm{N}_{2}\) when it is heated from \(25.0^{\circ} \mathrm{C}\) to \(100.0^{\circ} \mathrm{C} ?\) The molar heat capacity of nitrogen is given by$$C_{P, \mathrm{m}}=28.58+3.77 \times 10^{-3} T-\frac{0.5 \times 10^{5}}{T^{2}} \mathrm{JK}^{-1} \mathrm{mol}^{-1}$$

A plausible final temperature when \(75.0 \mathrm{mL}\) of water at \(80.0^{\circ} \mathrm{C}\) is added to \(100.0 \mathrm{mL}\) of water at \(20^{\circ} \mathrm{C}\) is (a) \(28^{\circ} \mathrm{C} ;\) (b) \(40^{\circ} \mathrm{C} ;\) (c) \(46^{\circ} \mathrm{C} ;\) (d) \(50^{\circ} \mathrm{C}\)

Construct a concept map to show the interrelationships between path-dependent and pathindependent quantities in thermodynamics.

The heat of neutralization of \(\mathrm{HCl}(\text { aq) by } \mathrm{NaOH}(\mathrm{aq})\) is \(-55.84 \mathrm{kJ} / \mathrm{mol} \mathrm{H}_{2} \mathrm{O}\) produced. If \(50.00 \mathrm{mL}\) of \(1.05 \mathrm{M}\) \(\mathrm{NaOH}\) is added to \(25.00 \mathrm{mL}\) of \(1.86 \mathrm{M} \mathrm{HCl}\), with both solutions originally at \(24.72^{\circ} \mathrm{C},\) what will be the final solution temperature? (Assume that no heat is lost to the surrounding air and that the solution produced in the neutralization reaction has a density of \(1.02 \mathrm{g} / \mathrm{mL}\) and a specific heat of \(3.98 \mathrm{Jg}^{-1}\) \(^{\circ} \mathrm{C}^{-1}\).

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