Chapter 6: Problem 29
\(\mathrm{Kr}(\mathrm{g})\) in a 18.5 L cylinder exerts a pressure of \(11.2 \mathrm{atm}\) at \(28.2^{\circ} \mathrm{C} .\) How many grams of gas are present?
Short Answer
Expert verified
The mass of the Krypton gas in the cylinder is 73.24 grams.
Step by step solution
01
Identify Given Values
The values given in the problem are Pressure(P) = 11.2 atm, Volume(V) = 18.5 L, Temperature(T) = \(28.2^{\circ} \mathrm{C}\) (which needs to be converted to Kelvin by adding 273.15), and the gas constant(R) = 0.0821 L.atm/K.mol.
02
Convert Temperature to Kelvin
The temperature is given in degrees Celsius but the ideal gas law requires temperature to be in Kelvin. Therefore, convert the temperature to Kelvin by adding 273.15 to the Celsius temperature. This gives \(T = 28.2 + 273.15 = 301.35 \mathrm{K}\).
03
Substitute values into the Ideal gas law
Substitute the values of the pressure, volume, gas constant, and temperature into the ideal gas law (\(PV = nRT\)). This gives \(11.2 \mathrm{atm} * 18.5 \mathrm{L} = n * 0.0821 * 301.35 \mathrm{K}\). Solve for n.
04
Solve for n
Solve the equation for n, the number of moles. \( n = \frac{11.2 \mathrm{atm} * 18.5 \mathrm{L}}{0.0821 * 301.35 \mathrm{K}} = 0.873 \mathrm{moles}\).
05
Convert moles to grams
Convert the number of moles to grams using the molar mass of Krypton, which is 83.8 g/mol. This gives \(\mathrm{Mass} = 0.873 \mathrm{moles} * 83.8 \mathrm{g/mol} = 73.24 \mathrm{g}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Krypton gas calculations
When dealing with gases under varying conditions, the Ideal Gas Law is a fundamental concept. This law can help us understand and find particular properties of a gas's state under specific temperature, pressure, and volume. The Ideal Gas Law equation is written as:
- \( PV = nRT \) where:
- \( P \) is the pressure (in atmospheres, atm)
- \( V \) is the volume (in liters, L)
- \( n \) is the number of moles of the gas
- \( R \) is the ideal gas constant \( (0.0821 \, \text{L atm K}^{-1} \text{mol}^{-1}) \)
- \( T \) is the temperature (in Kelvin, K)
Mole-to-gram conversion
After finding the number of moles of Krypton gas using the Ideal Gas Law, the next step is to convert moles into grams. The ability to switch between moles and grams is a handy skill in chemistry. This requires using the molar mass of the substance, which for Krypton, is 83.8 grams per mole.Here's how you can convert moles to grams:
- Identify the molar mass of the substance. For Krypton, it's \(83.8\, \text{g/mol}\).
- Use the formula: \[ \text{Mass (g)} = \text{Number of moles} \times \text{Molar mass (g/mol)} \]
- In the exercise, this calculation was: \[ \text{Mass} = 0.873\, \text{moles} \times 83.8\, \text{g/mol} = 73.24\, \text{g} \]
Temperature conversion to Kelvin
When using the Ideal Gas Law, it's essential to have the temperature in Kelvin. Kelvin is the absolute temperature scale in scientific measurements and ensures accurate calculations. Here's how you convert from Celsius to Kelvin:
- Start with the temperature in Celsius. In our problem, it was \(28.2^{\circ} \text{C}\).
- Add 273.15 to the Celsius temperature to convert directly to Kelvin. This gives us \(301.35\, \text{K}\).