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In your own words, define or explain these terms or symbols. (a) \(\stackrel{\Delta}{\longrightarrow}\) (b) (aq) (c) stoichiometric coefficient (d) overall equation

Short Answer

Expert verified
The symbol \(\stackrel{\Delta}{\longrightarrow}\) signifies a chemical reaction that has been heated. The term (aq) refers to an aqueous substance, or something dissolved in water. A stoichiometric coefficient illustrates the number of molecules (or atoms) in a reaction, used to balance equations. An overall equation gives a summarized snapshot of a chemical reaction, presenting reactants, products, and their stoichiometric relationships.

Step by step solution

01

Explanation of \(\stackrel{\Delta}{\longrightarrow}\)

The symbol \(\stackrel{\Delta}{\longrightarrow}\) is used in chemistry to indicate a chemical reaction that has been heated. The triangle (delta) itself is a Greek letter used to represent 'heat' in the context of chemical reactions.
02

Explanation of (aq)

The term (aq) is an abbreviation for 'aqueous', stemming from the Latin word for water. It is used in chemical equations to denote a substance that is dissolved in water.
03

Explanation of Stoichiometric Coefficient

In chemical equations, stoichiometric coefficients represent the number of molecules (or atoms) involved in the reaction. They are the numerals written in front of a chemical formula to balance the equation.
04

Explanation of Overall Equation

An overall equation represents a chemical reaction by indicating the reactants, products, and their stoichiometric relationships. This describes what changes occur during the reaction. It is the 'big picture' that summarizes the details of the chemical reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reaction Heating
When studying chemical reactions, understanding the factors that influence the reaction rate and completion is essential. One such factor is heat, often indicated in chemical equations with a Greek letter delta (\textdelta) perching above the arrow, like this: \( \stackrel{\Delta}{\longrightarrow} \). This symbol tells you that heat is applied to the system to initiate or speed up the reaction.

For example, consider the decomposition of calcium carbonate: \(\text{CaCO}_3 \stackrel{\Delta}{\longrightarrow} \text{CaO} + \text{CO}_2\). The reaction requires heating to proceed. In a classroom or lab setting, adding heat might involve using a Bunsen burner or hot plate. This application of heat provides the necessary energy to break chemical bonds in the reactants and form new bonds, resulting in the products. This concept is crucial because not all reactions happen spontaneously at room temperature; some require a thermal 'push' to get going.
Aqueous Solution
In chemistry, the phase or form in which a substance exists can impact its reactivity and behavior greatly. The term 'aqueous' refers to a substance that is dissolved in water, represented by the abbreviation (aq) in chemical equations. Water is a remarkable solvent due to its ability to dissolve many compounds, a property stemming from its polar nature.

For instance, when table salt (sodium chloride, NaCl) dissolves in water, the equation can be written as: \(\text{NaCl}(s) + \text{H}_2\text{O}(l) \rightarrow \text{Na}^{+}(aq) + \text{Cl}^{-}(aq)\). In this state, the ions are surrounded by water molecules, which allows them to move freely and conduct electricity—this is why salt solutions can carry a current. When dealing with chemical reactions in solution, it's crucial to consider the reactions' aqueous nature because it governs the reactivity and direction of the reaction, as many reactions can only take place in solution.
Stoichiometric Coefficients

Counting Molecules: The Role of Stoichiometric Coefficients

Stoichiometric coefficients are more than just numbers in front of chemical formulas; they represent the blueprint that governs the precise ratio of reactants and products in a chemical equation. Think of them as a recipe: just as a cake recipe requires a certain amount of each ingredient, a chemical reaction requires a specific quantity of reactants to form the desired amount of products.

These coefficients ensure the Law of Conservation of Mass is satisfied, meaning that atoms are neither created nor destroyed during a chemical reaction. For instance, in the simple synthesis of water, the stoichiometric coefficients show that two molecules of hydrogen gas react with one molecule of oxygen gas to form two molecules of water: \(\text{2H}_2\text{O} + \text{O}_2 \rightarrow \text{2H}_2\text{O}\). Balancing these coefficients is a fundamental skill in chemistry because it guarantees that the chemical equation accurately represents the reaction.
Balancing Chemical Equations

The Puzzle of Balancing Chemical Equations

Balancing chemical equations is a staple of any chemistry class, requiring students to manipulate stoichiometric coefficients to ensure that the number of atoms for each element is equal on both sides of the equation. It is similar to a puzzle where all pieces must fit perfectly.

To balance an equation, you'll need to consider each element separately and adjust the coefficients accordingly. This might involve some trial and error, but the fundamental principle is straightforward: the same amount of an element must be present in the reactants and the products. For example, balancing the combustion of methane (CH4) involves ensuring that the carbon (C) and hydrogen (H) atoms are equal on both sides: \(\text{CH}_4 + \text{2O}_2 \rightarrow \text{CO}_2 + \text{2H}_2\text{O}\). Mastering balancing equations is crucial for correctly predicting the outcomes of reactions and for practical applications, such as calculating reactant amounts needed for a given reaction or analyzing reaction yields.

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Most popular questions from this chapter

The manufacture of ethyl alcohol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) yields diethyl ether, \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}\) as a by-product. The complete combustion of a \(1.005 \mathrm{g}\) sample of the product of this process yields \(1.963 \mathrm{g} \mathrm{CO}_{2} .\) What must be the mass percents of \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\right),\) and of \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}\) in this sample?

Lithopone is a brilliant white pigment used in waterbased interior paints. It is a mixture of \(\mathrm{BaSO}_{4}\) and \(\mathrm{ZnS}\) produced by the reaction $$\mathrm{BaS}(\mathrm{aq})+\mathrm{ZnSO}_{4}(\mathrm{aq}) \longrightarrow \mathrm{ZnS}(\mathrm{s})+\mathrm{BaSO}_{4}(\mathrm{s})$$ How many grams of lithopone are produced in the reaction of \(315 \mathrm{mL}\) of \(0.275 \mathrm{M} \mathrm{ZnSO}_{4}\) and \(285 \mathrm{mL}\) of 0.315 M BaS?

Solid calcium carbonate, \(\mathrm{CaCO}_{3}(\mathrm{s}),\) reacts with \(\mathrm{HCl}(\mathrm{aq})\) to form \(\mathrm{H}_{2} \mathrm{O}, \mathrm{CaCl}_{2}(\mathrm{aq}),\) and \(\mathrm{CO}_{2}(\mathrm{g}) .\) If a \(45.0 \mathrm{g}\) sample of \(\mathrm{CaCO}_{3}(\mathrm{s})\) is added to \(1.25 \mathrm{L}\) of \(\mathrm{HCl}(\mathrm{aq})\) that is \(25.7 \% \mathrm{HCl}\) by mass \((d=1.13 \mathrm{g} / \mathrm{mL})\) what will be the molarity of \(\mathrm{HCl}\) in the solution after the reaction is completed? Assume that the solution volume remains constant.

How many grams of \(\mathrm{CO}_{2}\) are produced in the complete combustion of \(406 \mathrm{g}\) of a bottled gas that consists of \(72.7 \%\) propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) and \(27.3 \%\) butane \(\left(\mathrm{C}_{4} \mathrm{H}_{10}\right)\) by mass?

The following set of reactions is to be used as the basis of a method for producing nitric acid, \(\mathrm{HNO}_{3}\) Calculate the minimum masses of \(\mathrm{N}_{2}, \mathrm{H}_{2^{\prime}}\) and \(\mathrm{O}_{2}\) required per kilogram of \(\mathrm{HNO}_{3}\) $$\begin{array}{l} \mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{g}) \\ 4 \mathrm{NH}_{3}(\mathrm{g})+5 \mathrm{O}_{2}(\mathrm{g}) \longrightarrow 4 \mathrm{NO}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\ 2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NO}_{2}(\mathrm{g}) \\ 3 \mathrm{NO}_{2}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \longrightarrow 2 \mathrm{HNO}_{3}(\mathrm{aq})+\mathrm{NO}(\mathrm{g}) \end{array}$$

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