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Write the condensed structural formulas for the organic compounds: (a) octane (b) heptanoic acid (c) 3-hexanol (d) 2 -chlorobutane

Short Answer

Expert verified
The condensed structural formulas are: (a) Octane: \(C_8H_{18}\), (b) Heptanoic Acid: \(C_7H_{14}O_2\), (c) 3-Hexanol: \(C_6H_{13}OH\), (d) 2 -Chlorobutane: \(C_4H_9Cl\)

Step by step solution

01

Octane

The prefix 'oct' refers to eight carbon atoms, and the 'ane' indicates that it's an alkane. Therefore, the condensed structural formula will be \(C_8H_{18}\)
02

Heptanoic Acid

The prefix 'hept' implies a chain of seven carbon atoms, and 'anoic acid' indicates that it's a carboxylic acid. Therefore, the condensed structural formula will be \(C_7H_{14}O_2\)
03

3-Hexanol

The prefix 'hex' signifies six carbon atoms, and the 'ol' suffix denotes an alcohol. The '3' in the front refers to the position of the hydroxy group (-OH) on the third carbon atom. Therefore, the condensed structural formula will be \(C_6H_{13}OH\)
04

2-Chlorobutane

The prefix 'but' denotes four carbon atoms, 'ane' signifies that it's an alkane, and '2-Chloro' indicates there is a Chlorine atom attached on the second carbon. Therefore, the condensed structural formula will be \(C_4H_9Cl\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Organic Compounds
Organic compounds are mainly composed of carbon atoms and are considered the backbone of chemistry, particularly in biological systems. These compounds typically consist of carbon atoms bonded with hydrogen, oxygen, nitrogen, and other elements. A crucial feature of organic compounds is their ability to form large and complex structures.
One reason these compounds can be so versatile is because carbon atoms can form four covalent bonds, allowing for a variety of structures and shapes. This results in the formation of different chains, rings, and networks.
Understanding organic compounds is essential in many fields, such as pharmaceuticals, petrochemicals, and biochemistry. They serve as the basis for life on earth, present in DNA, proteins, drugs, and more.
Naming Conventions
Naming conventions in organic chemistry help us identify and communicate the structure of different compounds efficiently. The International Union of Pure and Applied Chemistry (IUPAC) rules standardize these names to avoid confusion.
The name of an organic compound provides information about the number of carbon atoms, the type of bonds, and any functional groups present in the molecule. For instance:
  • The "oct" in octane indicates eight carbon atoms linked together, while "ane" implies that these are single bonds.
  • "Heptanoic acid" implies seven carbons with a carboxylic acid group (-COOH).
  • "3-Hexanol" tells us there are six carbons, and the `ol` shows there is an alcohol group on the third carbon.
  • "2-Chlorobutane" suggests four carbon atoms with a chlorine atom on the second carbon.
Using these conventions, even intricate molecular structures can be accurately represented through names.
Functional Groups
Functional groups are specific groups of atoms within molecules that determine the characteristics and chemical reactivity of those molecules. They are the focal point of chemical reactions and play a key role in classifying and naming organic compounds.
For example:
  • The hydroxyl group (-OH) in alcohols like 3-hexanol makes the compound capable of forming hydrogen bonds, affecting its solubility in water.
  • The carboxyl group (-COOH) in carboxylic acids, such as heptanoic acid, is highly polar and acidic, influencing the compound's behavior in chemical reactions.
  • A chlorine atom as in 2-chlorobutane, serves as a halogen functional group, altering the compound's reactivity and solubility.
Recognizing functional groups is critical for predicting the physical and chemical properties of organic compounds.
Hydrocarbons
Hydrocarbons are the simplest type of organic compounds, consisting only of carbon and hydrogen atoms. They are fundamental in understanding organic chemistry because they form the basic structure that other functional groups modify.
These compounds can be classified into different types, such as alkanes, alkenes, and alkynes:
  • Alkanes are saturated hydrocarbons containing only single bonds between carbon atoms. Octane, for example, is an alkane with the formula \(C_8H_{18}\).
  • Alkenes have at least one double bond, affecting their reactivity and physical properties.
  • Alkynes contain one or more triple bonds, and are less common than alkanes and alkenes.
Understanding the differences between these types of hydrocarbons is important for predicting their behavior and uses, such as their role as fuels or precursors to other organic compounds.

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Most popular questions from this chapter

Write formulas for the compounds: (a) aluminum sulfate; (b) ammonium dichromate; (c) silicon tetrafluoride; (d) iron(III) oxide; (e) tricarbon disulfide; (f) cobalt(II) nitrate; (g) strontium nitrite; (h) hydrobromic acid; (i) iodic acid; (j) phosphorus dichloride trifluoride.

Selenium, an element used in the manufacture of photoelectric cells and solar energy devices, forms two oxides. One has \(28.8 \%\) O, by mass, and the other, 37.8\% O. What are the formulas of these oxides? Propose acceptable names for them.

Liquid ethyl mercaptan, \(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{S},\) has a density of \(0.84 \mathrm{g} / \mathrm{mL} .\) Assuming that the combustion of this compound produces only \(\mathrm{CO}_{2}, \mathrm{H}_{2} \mathrm{O},\) and \(\mathrm{SO}_{2},\) what masses of each of these three products would be produced in the combustion of \(3.15 \mathrm{mL}\) of ethyl mercaptan?

A hydrate of copper(II) sulfate, when heated, goes through the succession of changes suggested by the photograph. In this photograph, (a) is the original fully hydrated copper(II) sulfate; (b) is the product obtained by heating the original hydrate to \(140^{\circ} \mathrm{C}\) (c) is the product obtained by further heating to \(400^{\circ} \mathrm{C}\) and (d) is the product obtained at \(1000^{\circ} \mathrm{C}\) A \(2.574 \mathrm{g}\) sample of \(\mathrm{CuSO}_{4} \cdot x \mathrm{H}_{2} \mathrm{O}\) was heated to \(140^{\circ} \mathrm{C},\) cooled, and reweighed. The resulting solid was reheated to \(400^{\circ} \mathrm{C},\) cooled, and reweighed. Finally, this solid was heated to \(1000^{\circ} \mathrm{C},\) cooled, and reweighed for the last time. $$ \text {Original sample } \quad \quad\quad\quad\quad \text {\(2.574 \mathrm{g}\) } $$ $$ \text {After heating to \(140^{\circ} \mathrm{C}\) } \quad \quad\quad\quad\quad \text {\(1.833 \mathrm{g}\) } $$ $$ \text {After reheating to \(400^{\circ} \mathrm{C}\)} \quad \quad\quad\quad\quad \text {\(1.647 \mathrm{g}\) } $$ $$ \text {After reheating to \(1000^{\circ} \mathrm{C}\)} \quad \quad\quad\quad\quad \text {\(0.812 \mathrm{g}\)} $$ (a) Assuming that all the water of hydration is driven off at \(400^{\circ} \mathrm{C},\) what is the formula of the original hydrate? (b) What is the formula of the hydrate obtained when the original hydrate is heated to only \(140^{\circ} \mathrm{C} ?\) (c) The black residue obtained at \(1000^{\circ} \mathrm{C}\) is an oxide of copper. What is its percent composition and empirical formula?

Dimethylhydrazine is a carbon-hydrogen-nitrogen compound used in rocket fuels. When burned in an excess of oxygen, a \(0.312 \mathrm{g}\) sample yields \(0.458 \mathrm{g} \mathrm{CO}_{2}\) and \(0.374 \mathrm{g} \mathrm{H}_{2} \mathrm{O}\). The nitrogen content of a \(0.486 \mathrm{g}\) sample is converted to \(0.226 \mathrm{g} \mathrm{N}_{2} .\) What is the empirical formula of dimethylhydrazine?

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