Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The three isomeric tribromobenzenes, I, II, and III, when nitrated, form three, two, and one mononitrotribromobenzenes, respectively. Assign correct structures to I, II, and III.

Short Answer

Expert verified
The structures of isomeric tribromobenzenes I, II, and III are 1,2,3-tribromobenzene, 1,2,4-tribromobenzene, and 1,3,5-tribromobenzene, respectively.

Step by step solution

01

Understand the concept of isomers and nitration

Isomers are compounds with the same molecular formula but different structural arrangements. In this case, tribromobenzenes will have the same molecular formula with different positions for bromine atoms. Nitration is a chemical process that introduces a nitro group into a molecule. For benzene ring, nitration will occur at positions ortho, meta or para relative to bromine atoms.
02

Derive possible isomers of tribromobenzenes

The three possible isomers for tribromobenzenes, based on the positions of bromine atoms, are 1,2,3-tribromobenzene (with bromine atoms at adjacent positions), 1,2,4-tribromobenzene (with a bromine atom at an ortho and para to another), and 1,3,5-tribromobenzene (bromine atoms occupy alternate positions).
03

Determine the possible nitration sites for each isomer and match with the information given

The 1,2,3-tribromobenzene can be nitrated at three different positions while 1,2,4-tribromobenzene can be nitrated at two positions, and 1,3,5-tribromobenzene can only be nitrated at one unique position. Matching this information with the given exercise, tribromobenzenes I, II, and III can be identified as 1,2,3-tribromobenzene, 1,2,4-tribromobenzene, and 1,3,5-tribromobenzene, respectively.
04

Establish and verify the structures of the isomers

Draw the structures of I, II, and III, and verify by cross-checking with nitration sites. Isomer I (1,2,3-tribromobenzene) has three possible nitration spots making it yield three products. Isomer II (1,2,4-tribromobenzene) has two possible nitration sites producing two products. Isomer III (1,3,5-tribromobenzene) has one unique nitration spot producing one product.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Isomers
In the world of chemistry, isomers play an essential role. They are compounds that share the same molecular formula but differ in the arrangement of their atoms. Even though they have the same number of each atom, their structures diverge, leading to different chemical properties.
For example, tribromobenzenes are all composed of the same types and numbers of atoms, specifically three bromine atoms attached to a benzene ring. However, the location of these bromine atoms around the benzene ring varies, creating different isomers.
It’s like dressing up differently using the same pieces of clothing! Each "outfit" or arrangement offers unique characteristics, impacting how the isomer reacts in various chemical processes.
Some common traits of chemical isomers include:
  • Identical molecular formulas but different chemical structures
  • Distinct chemical and physical properties
  • Possible varied reactivity towards the same chemical reactions
Nitration Process
Nitration is a key chemical process utilized to introduce nitro groups (\(-NO_2\)) into organic compounds. It's a fundamental reaction in organic chemistry, especially when modifying aromatic compounds like benzene rings. How does it work? Primarily through a process called electrophilic aromatic substitution.
During nitration, a strong nitrating agent, often a mix of nitric acid (\(HNO_3\)) and sulfuric acid (\(H_2SO_4\)), replaces a hydrogen atom in an aromatic ring with a nitro group. This is achieved under controlled conditions to yield desired products.
Key points about the nitration process include:
  • Important for synthesizing compounds with nitro functionalities
  • Conducted under acidic conditions
  • Relevant in producing pharmaceuticals, dyes, and explosives
For tribromobenzenes, the position of bromine atoms significantly influences where the nitro group will attach.
Tribromobenzene Structures
Tribromobenzene refers to a benzene molecule substituted with three bromine atoms. The structure is defined by the specific positions of these bromine atoms on the benzene ring. These positions create three distinct structural isomers: 1,2,3-, 1,2,4-, and 1,3,5-tribromobenzene.
Let's break them down:
  • 1,2,3-tribromobenzene: Bromine atoms are consecutive on the ring, providing the highest symmetry among the isomers.
  • 1,2,4-tribromobenzene: Offers a unique arrangement, with bromine atoms occupying two adjacent and one opposite position on the benzene ring.
  • 1,3,5-tribromobenzene: This arrangement positions the bromine atoms alternately across the ring for another symmetric form.
Each structure impacts the compound's reactivity and possible nitration sites. Understanding these differences aids in predicting chemical behavior and product formation.
Nitration Sites
Nitration sites on a molecule refer to specific positions where a nitro group \((-NO_2)\) can attach during a nitration reaction. The exact locations depend significantly on other existing groups within the molecule.
In tribromobenzenes, bromine's positioning directs the possible nitration sites. The bromine atoms themselves can direct electrophiles, like the nitronium ion (\(NO_2^+\)), to specific positions on the benzene ring:
  • Ortho: The postion immediately adjacent to a bromine.
  • Meta: One carbon away from the bromine.
  • Para: Directly opposite the bromine atom.
Understanding these concepts helps in determining how many mononitrotribromobenzene products can form, as seen in the given exercise. The structural arrangement of bromine influences the ease and number of possible nitration products.
Mononitrotribromobenzene
Mononitrotribromobenzenes are the resulting products after the nitration of tribromobenzene isomers. In simpler terms, they are tribromobenzene molecules that have been modified by adding one nitro group (\(-NO_2\)) through the nitration process.
The fascinating part is that each tribromobenzene isomer will yield a different number of mononitro products due to the specific nitration sites available.
  • 1,2,3-tribromobenzene: Can form three different mononitro products due to its three unique sites available for nitration.
  • 1,2,4-tribromobenzene: Produces two variations based on its two available sites for nitration.
  • 1,3,5-tribromobenzene: Can only produce one mononitro compound owing to its one distinct nitration site.
These variations in product formation perfectly illustrate how structural isomerism influences chemical reactivity, helping chemists predict and control chemical reactions efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the name and structure of the benzene derivatives described below. (a) Formula: \(\mathrm{C}_{8} \mathrm{H}_{10} ;\) forms three monochlorination products when treated with \(\mathrm{Cl}_{2}\) and \(\mathrm{FeCl}_{3}\) (b) Formula: \(\mathrm{C}_{9} \mathrm{H}_{12}\); forms one monochlorination product when treated with \(\mathrm{Cl}_{2}\) and \(\mathrm{FeCl}_{3}\) (c) Formula: \(\mathrm{C}_{9} \mathrm{H}_{12}\); forms four monochlorination products when treated with \(\mathrm{Cl}_{2}\) and \(\mathrm{FeCl}_{3}\)

Would you expect a polymer to be formed by the reaction of terephthalic acid with ethyl alcohol in place of ethylene glycol? With glycerol in place of ethylene glycol? Explain.

Explain the important distinctions between each pair of terms: (a) nucleophilic substitution and electrophilic aromatic substitution; (b) addition and elimination; (c) \(S_{N} 1\) and \(S_{N} 2 ;\) (d) E1 and E2

Which of the following is the strongest nucleophile for an \(S_{N} 2\) reaction? (a) \(\mathrm{H}_{2} \mathrm{O} ;\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH};\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-} ;\) (d) \(\mathrm{CH}_{3} \mathrm{CO}_{2}{^-} ;\) (e) \(\mathrm{CH}_{3} \mathrm{S}^{-}\)

Predict and name the product(s) obtained from the following reaction. Write out the mechanism for the reaction and use curved arrows to show the movement of electrons. $$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}=\mathrm{CH}_{2} \stackrel{\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{H}_{2} \mathrm{O}}{\longrightarrow}$$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free