Question

Predict the product(s) of the reaction of: (a) HCl with 2-chloro-1-propene (b) HCN with \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}\) (c) HCl with CH \(_{3} \mathrm{CH}=\mathrm{C}\left(\mathrm{CH}_{3}\right)_{2}\)

Short answer

The products of the reactions are (a) \(\mathrm{CH}_{3}\mathrm{CHCl-CH}_{2}\mathrm{Cl},\) (b) \(\mathrm{CH}_{3}\mathrm{CH}-\mathrm{CH}_{2}\mathrm{CN},\) and (c) \(\mathrm{CH}_{3}\mathrm{CHCl-CH}(\mathrm{CH}_{3})_{2}\).

Step-by-step solution

Reaction of HCl with 2-chloro-1-propene

In this reaction, we have HCl reacting with 2-chloro-1-propene: \( \mathrm{HCl + CH}_{3}\mathrm{CH=CCl} \rightarrow ? \) Following Markovnikov's rule, the hydrogen atom from HCl will attach to the carbon atom in the double bond that is carrying more hydrogen atoms already. Here it's the middle carbon atom. The Cl from the HCl will attach to the other carbon atom in the double bond that originally carried the Cl in the reactant. The product is: \( \mathrm{CH}_{3}\mathrm{CHCl-CH}_{2}\mathrm{Cl} \)

Reaction of HCN with \(\mathrm{CH}_{3} \mathrm{CH=CH}_{2}\)

Here we have HCN reacting with propene: \( \mathrm{HCN} + \mathrm{CH}_{3}\mathrm{CH=CH}_{2} \rightarrow ? \) H-CN bond polarizes and C (carrying a partial positive charge) attacks the carbon atom of the double bond that has fewer hydrogen atoms bonded to it, due to electron-releasing effect of hydrogens, making it more rich in electrons. Thus C of CN attaches to the terminal carbon. The product is: \( \mathrm{CH}_{3}\mathrm{CH}-\mathrm{CH}_{2}\mathrm{CN} \)

Reaction of HCl with \(\mathrm{CH}_{3} \mathrm{CH=CH}(\mathrm{CH}_{3})_{2}\)

In this final reaction, we have HCl reacting with 4,4-dimethyl-2-pentene: \( \mathrm{HCl} + \mathrm{CH}_{3}\mathrm{CH=CH}(\mathrm{CH}_{3})_{2} \rightarrow ? \) Following Markovnikov's rule, the hydrogen from HCl will attach to the central carbon atom in the double bond that is carrying more hydrogen atoms. Hence, Cl attaches to the carbon atom next to the central carbon atom. The product is: \( \mathrm{CH}_{3}\mathrm{CHCl-CH}(\mathrm{CH}_{3})_{2} \)

Key concepts

Markovnikov's Rule

Markovnikov's Rule is a principle that governs the outcome of addition reactions involving unsaturated compounds like alkenes and alkynes.

When an unsymmetrical alkene reacts with a hydrogen halide such as hydrochloric acid, Markovnikov's Rule helps predict which carbon atom of the double bond will connect to the hydrogen atom and which will connect to the halide (like chlorine).

According to Markovnikov's Rule, the hydrogen atom attaches to the carbon with the most hydrogen atoms already attached, leading to the more stable carbocation intermediate. The halide will then bond with the less substituted carbon atom. This rule is key in determining the major product in chemical reactions of alkenes like those presented in the exercise.

Chemical Reactions of Alkenes

Alkenes are hydrocarbons with at least one carbon-carbon double bond, which is the reactive site for many reactions. Chemical reactions of alkenes commonly involve addition reactions, where atoms or groups of atoms are added across the double bond.

Examples of these reactions include halogenation, hydrohalogenation, and hydration. In the presence of a halogen like chlorine or bromine, alkenes form dihalides. With hydrogen halides (HCl, HBr, etc.), alkenes form alkyl halides, following the Markovnikov's Rule. These reactions are vital in synthesizing a variety of organic compounds and are applied using the exercise's context.

Hydrochloric Acid Reactions

Hydrochloric acid (HCl) is known for its role in acid-base reactions, but it also participates in addition reactions with alkenes.

In these reactions, HCl provides a hydrogen atom and a chloride anion; following Markovnikov's Rule, the hydrogen atom bonds with the more substituted carbon of the alkene, while the chloride ion bonds with the other carbon atom at the double bond. This typically results in the formation of an alkyl chloride through hydrochlorination. The identification of products, as shown in the exercise, is foundational for students learning organic chemistry.

Hydrogen Cyanide Reactions

Hydrogen cyanide (HCN) is a polar molecule that can add across the double bonds in alkenes, leading to the formation of nitriles. In the reaction with alkenes, the carbon in the CN group attaches to the carbon with the most available electrons (usually the least substituted carbon), contrary to Markovnikov's Rule. This is because of the unique polarity of the H-CN bond.

The reaction between HCN and an alkene is an important synthetic process for generating carbon-nitrogen bonds, which are key structural features in many organic molecules. Understanding this reaction allows students to predict and explain the outcome of HCN additions to alkenes, as shown in the exercise.