Question

Predict the products of the following reactions. Assume that \([\mathrm{O}]\) represents \(\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) in \(\mathrm{H}_{2} \mathrm{SO}_{4}:\) (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}_{2} \mathrm{OH} \stackrel{[\mathrm{O}]}{\longrightarrow}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}+\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCOOH} \frac{\mathrm{H}^{+}}{\Delta}\) (c) 3 -methyl- 2 -butanol \(+\mathrm{NaCl} \stackrel{\mathrm{H}_{2} \mathrm{SO}_{4}}{\longrightarrow}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} \frac{\mathrm{H}_{2} \mathrm{SO}_{4}}{\Delta}\)

Short answer

The predicted products are: (a) \( (CH_3)_2CHCHO \), (b) \( CH_3CH_2OOC(CH_3)_2CH_2 \), (c) 3-chloro-2-methylbutane, and (d) \( CH_3CHOCH_2CH_3 \).

Step-by-step solution

Identify the Type of Each Reaction and the Functional Groups

In (a), the reagent Na2Cr2O7 in H2SO4 is involved; this is an oxidizing agent. The molecule has a primary alcohol group. In (b), the presence of \( H^+ \) suggests an acid-catalyzed reaction and the two of the molecules contain a primary alcohol group and a carboxylic acid group. In (c), the presence of \( H_2SO_4 \) and sodium chloride (NaCl) suggests this may be a substitution reaction involving 3 -methyl- 2 -butanol. Lastly, in (d), \( H_2SO_4 \) indicates a dehydration reaction, and the molecule is a primary alcohol.

Predict the Products

For (a), oxidation of a primary alcohol results in an aldehyde. Therefore, the product will be \( (CH_3)_2CHCHO \). For (b), the acid-catalyzed reaction will result in esterification, yielding \( CH_3CH_2OOC(CH_3)_2CH_2 \) (an ester). For (c), the substitution reaction in acidic conditions with an alcohol would yield an alkyl halide, therefore the product is 3-chloro-2-methylbutane. For (d), the dehydration of an alcohol in acidic condition would usually produce an alkene, but in this case since it's a primary alcohol, an ether is produced, with the product being \( CH_3CHOCH_2CH_3 \).

Verify the Results

Make sure the reactions correspond to the rules for the reaction type. Oxidation of a primary alcohol yields an aldehyde, esterification between a carboxylic acid and an alcohol produces an ester, substitution of an alcohol in acidic conditions yields an alkyl halide, and dehydration of a primary alcohol yields an ether.

Key concepts

Oxidation Reactions

Oxidation reactions in organic chemistry often refer to the conversion of alcohols to aldehydes, ketones, or carboxylic acids, through the addition of oxygen or removal of hydrogen. In the provided example, the oxidizing agent used is sodium dichromate ( $a_2Cr_2O_7$ ) in the presence of sulfuric acid ( $H_2SO_4$ ). Such agents are strong and will facilitate the oxidation of the alcohol group to a carbonyl group.

• Primary alcohols are typically oxidized to aldehydes under controlled conditions and to carboxylic acids under more severe conditions.
• In our reaction, $(CH_3)_2CHCH_2OH$ is oxidized to $(CH_3)_2CHCHO$.

This reflects the transformation from a primary alcohol to an aldehyde by replacing the hydroxyl group with an oxygen double-bonded to carbon. Keep in mind, oxidation increases the carbon's oxidation state, and such reactions are critical in organic synthesis for building more complex molecules.

Esterification

Esterification is a fundamental reaction in organic chemistry, resulting in the formation of esters. In this process, a carboxylic acid reacts with an alcohol in the presence of an acid catalyst, often sulfuric acid.

• The $H^+$ acts as a catalyst, facilitating the reaction by protonating the carbonyl oxygen, making it more electrophilic.
• In our example, $CH_3CH_2OH$ (ethanol) reacts with $ (CH_3)_2CHCOOH$ (isobutyric acid) under these conditions to form $CH_3CH_2OOC(CH_3)_2CH$.

This esterification reaction involves the exchange of the hydroxyl group of the acid with the alkoxy group of the alcohol, producing an ester and water. Esterification is pivotal in industries related to perfumes, flavorings, and plastics due to the pleasant aromas and the structural functionalities of esters.

Substitution Reactions

Substitution reactions in organic chemistry typically involve replacing one functional group in a molecule with another. The example provided involves an alcohol reacting with sodium chloride in the presence of sulfuric acid, leading to a nucleophilic substitution.

• This reaction transforms 3-methyl-2-butanol to 3-chloro-2-methylbutane, where the -OH group is substituted by a chloride ion.
• In this reaction, the sulfuric acid protonates the hydroxyl group, making it a better leaving group, thus facilitating the nucleophilic attack by the chloride ion.

Substitution reactions are very important as they allow chemists to modify the molecular structure of compounds, altering their reactivity and properties. They play a crucial role in the synthesis of complex organic compounds in pharmaceuticals and materials science.

Dehydration Reactions

Dehydration reactions involve the elimination of water from a compound, often leading to the formation of a double bond or, in some specific cases, an ether.

• Alcohols, when treated with strong acids like sulfuric acid, can undergo dehydration.
• In this exercise, $CH_3CH_2CH_2OH$ (propanol) in the presence of sulfuric acid leads to the formation of an ether (diethyl ether), instead of the more common alkene.

Typically, primary alcohols can undergo either dehydration to form alkenes or ethereal formation. The acid acts by protonating the hydroxyl group, allowing it to leave and form a carbocation intermediate, which then takes part in a further chemical change, like forming an ether. Understanding dehydration reactions helps in synthesizing new compounds and understanding mechanisms involved in different transformations.