Chapter 25: Problem 69
An ester forms from a carboxylic acid and an alcohol. $$\mathrm{RCO}_{2} \mathrm{H}+\mathrm{HOR}^{\prime} \longrightarrow \mathrm{RCO}_{2} \mathrm{R}^{\prime}+\mathrm{H}_{2} \mathrm{O}.$$ This reaction is superficially similar to the reaction of an acid with a base such as sodium hydroxide. The mechanism of the reaction can be followed by using the tracer \(^{18} \mathrm{O}\). This isotope is not radioactive, but other physical measurements can be used to detect its presence. When the esterifcation reaction is carried out with the alcohol containing oxygen-18 atoms, no oxygen-18 beyond its naturally occurring abundance is found in the water produced. How does this result affect the perception that this reaction is like an acid-base reaction?
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