Radioactive decay and mass spectrometry are often used to date rocks after
they have cooled from a magma. \(^{87} \mathrm{Rb}\) has a half-life of \(4.8
\times 10^{10}\) years and follows the radioactive decay $$^{87} \mathrm{Rb}
\longrightarrow^{87} \mathrm{Sr}+\beta^{-}$$ A rock was dated by assaying the
product of this decay. The mass spectrum of a homogenized sample of rock
showed the \(^{87} \mathrm{Sr} /^{86} \mathrm{Sr}\) ratio to be \(2.25 .\) Assume
that the original \(^{87} \mathrm{Sr} /^{86} \mathrm{Sr}\) ratio was 0.700 when
the rock cooled. Chemical analysis of the rock gave \(15.5 \mathrm{ppm}\) Sr and
265.4 ppm \(\mathrm{Rb},\) using the average atomic masses from a periodic
table. The other isotope ratios were \(^{86} \mathrm{Sr} /^{88} \mathrm{Sr}=\)
0.119 and \(^{84} \mathrm{Sr} /^{88} \mathrm{Sr}=0.007 .\) The isotopic ratio
for \(^{87} \mathrm{Rb} /^{85} \mathrm{Rb}\) is 0.330. The isotopic masses are
as follows:Calculate the following:
(a) the average atomic mass of Sr in the rock
(b) the original concentration of \(\mathrm{Rb}\) in the rock in \(\mathrm{ppm}\)
(c) the percentage of rubidium- 87 decayed in the rock
(d) the time since the rock cooled.