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The number of unpaired electrons in the complex ion \(\left[\operatorname{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) is (a) \(5 ;(\mathrm{b}) 4 ;(\mathrm{c}) 3 ;(\mathrm{d}) 2 ;(\mathrm{e}) 1\).

Short Answer

Expert verified
The correct answer is (b) 4. The metal atom Chromium (Cr) in the complex ion \(\left[\operatorname{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) has 4 unpaired electrons.

Step by step solution

01

Identify the Metal

The complex ion in this problem is \(\left[\operatorname{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\). The metal atom in this complex ion, upon which its properties depend, is Chromium (Cr).
02

Determine the Electron Configuration

To solve this problem, knowledge of the electron configuration of Chromium is necessary. The electron configuration of Cr is \([Ar] 3d^5 4s^1\) in its ground state. However, when it loses 2 electrons to form \(\operatorname{Cr}^{2+}\), it loses 1 electron from the 4s orbital and one from the 3d orbital, making the configuration \([Ar] 3d^4\). Therefore, Chromium (Cr) in this complex ion has 4 unpaired electrons.
03

Match Answer Choice

According to the options provided, the number of unpaired electrons in the complex ion is either a) 5, b) 4, c) 3, d) 2, or e) 1. Thus, after determining that the number of unpaired electrons in Chromium in the complex ion is 4, we can see that the correct answer is (b) 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metal Electron Configuration
Understanding metal electron configuration is essential, especially when dealing with transition metals like Chromium. Electron configurations tell us how electrons are distributed in an atom's orbitals, which influences the atom's reactivity and interactions. For transition metals, their electron configurations involve filling of the
  • d orbitals
  • s orbitals
These two orbital types play a significant role in their chemical behavior.
Chromium (Cr) is a transition metal with an unusual electron configuration:
  • In its ground state, it is written as \[ \text{[Ar]} \ 3d^5 \ 4s^1 \]
  • This differs from the expected \[ \text{[Ar]} \ 3d^4 \ 4s^2 \] configuration due to electron stability considerations and the exchange energy that arises when orbitals are half-filled.
Additionally, when Chromium forms an ion like \[ \operatorname{Cr}^{2+} \], it involves losing electrons. Typically, electrons are lost from the s orbital first, followed by the d orbitals. Thus, the \[ \operatorname{Cr}^{2+} \] ion has the configuration \[ \text{[Ar]} \ 3d^4 \]. Each unpaired electron in this configuration contributes to the magnetic properties and reactivity of the complex.
Transition Metal Chemistry
Transition metal chemistry is fascinating due to its rich interplay of properties stemming from d electron configurations. Transition metals like Chromium have partially filled d orbitals, which have several important implications:
  • Variable Oxidation States: Transition metals can exhibit multiple oxidation states, making them incredibly versatile in forming compounds. For example, Chromium can exist in several oxidation states like +2, +3, and +6.
  • Magnetism: The presence of unpaired electrons gives many transition metals magnetic properties. Unpaired 3d electrons in \[ \operatorname{Cr}^{2+} \] contribute to its paramagnetism.
  • Color: Transition metals often form colorful compounds, which occur due to d-d electronic transitions. These colors are influenced by the specific ligands surrounding the metal ion.
Complexes like \[ \left[\operatorname{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+} \] exemplify how transition metals interact with ligands, becoming integral parts of coordination compounds.
Coordination Chemistry
Coordination chemistry involves the study of compounds formed between metal ions and ligands, which are ions or molecules that donate electron pairs to the metal. In the coordination complex \[ \left[\operatorname{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+} \], ammonia (\( \mathrm{NH}_{3} \)) acts as the ligand, donating its lone pair of electrons to the central Chromium ion.

Several key principles govern coordination chemistry:
  • Coordination Number: This refers to the number of ligand atoms directly bonded to the central metal ion. For \[ \left[\operatorname{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+} \], the coordination number is 6.
  • Ligand Geometry: The arrangement of ligands around a central metal ion determines the geometry of the complex. A coordination number of 6 typically results in an octahedral geometry.
  • Electron Pair Donation: Ligands provide electron pairs to fill the metal’s coordination sphere, affecting its electronic structure and stability.
Understanding coordination chemistry is crucial for explaining the physical and chemical properties of metal complexes, such as solubility, reactivity, and color.

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Most popular questions from this chapter

The compound \(\mathrm{CoCl}_{2} \cdot 2 \mathrm{H}_{2} \mathrm{O} \cdot 4 \mathrm{NH}_{3}\) may be one of the hydrate isomers \(\left[\mathrm{CoCl}\left(\mathrm{H}_{2} \mathrm{O}\right)\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl} \cdot \mathrm{H}_{2} \mathrm{O}\) or \(\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2} .\) A \(0.10 \mathrm{M}\) aqueous solution of the compound is found to have a freezing point of \(-0.56^{\circ} \mathrm{C} .\) Determine the correct formula of the compound. The freezing-point depression constant for water is \(1.86 \mathrm{mol}\) \(\mathrm{kg}^{-1}\) \(^{\circ} \mathrm{C}\), and for aqueous solutions, molarity and molality can be taken as approximately equal.

Write equations to represent the following observations. (a) A quantity of \(\mathrm{CuCl}_{2}(\mathrm{s})\) is dissolved in concentrated HCl(aq) and produces a yellow solution. The solution is diluted to twice its volume with water and assumes a green color. On dilution to ten times its original volume, the solution becomes pale blue. (b) When chromium metal is dissolved in \(\mathrm{HCl}(\mathrm{aq}), \mathrm{a}\) blue solution is produced that quickly turns green. Later the green solution becomes blue-green and then violet.

The coordination number of \(\mathrm{Pt}\) in the complex ion \(\left[\mathrm{PtCl}_{2}(\mathrm{en})_{2}\right]^{2+}\) is \((\mathrm{a}) 2 ;(\mathrm{b}) 3 ;(\mathrm{c}) 4 ;(\mathrm{d}) 5 ;(\mathrm{e}) 6\).

Describe how the crystal field theory explains the fact that so many transition metal compounds are colored.

Without performing detailed calculations, show why you would expect the concentrations of the various ammine-aqua complex ions to be negligible compared with that of \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) in a solution having a total \(\mathrm{Cu}(\mathrm{II})\) concentration of \(0.10 \mathrm{M}\) and a total concentration of \(\mathrm{NH}_{3}\) of \(1.0 \mathrm{M}\). Under what conditions would the concentrations of these ammine-aqua complex ions (such as \(\left.\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3} \mathrm{NH}_{3}\right]^{2+}\right)\) become more significant relative to the concentration of \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+} ?\) Explain.

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