Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A tabulation of formation constant data lists the following log \(K\) values for the formation of \(\left[\mathrm{CuCl}_{4}\right]^{2-}\): \(\log K_{1}=2.80, \quad \log K_{2}=1.60, \quad \log K_{3}=0.49, \quad\) and \(\log K_{4}=0.73 .\) What is the overall formation constant \(\beta_{4}=K_{\mathrm{f}}\) for \(\left[\mathrm{CuCl}_{4}\right]^{2-} ?\)

Short Answer

Expert verified
To find the short answer, follow the steps above: Convert the log \(K\) values to \(K\) values, calculate the overall formation constant, and compute using the provided constants. The resulting value for \(\beta_{4}\) is your short answer.

Step by step solution

01

Convert log \(K\) values to \(K\) values

As the logarithm base 10 of a number \(x\) is given by \(\log x\), to invert this operation and get \(x\), you would use the ten to the power operation. So the formation constants are: \(K_1 = 10^{log K_1}\), \(K_2 = 10^{log K_2}\), \(K_3 = 10^{log K_3}\), \(K_4 = 10^{log K_4}\)
02

Calculation of overall formation constant, \(\beta_{4}\)

Given that the overall formation constant is the product of the formation constants, \(\beta_{4}= K_{f}= K_1\times K_2\times K_3\times K_4\).
03

Substitute and Compute

Substitute the \(K\) values from step 1 into the formula from step 2 and calculate \(\beta_{4}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Formation
Complex formation occurs when a central metal ion such as copper combines with surrounding molecules or ions, called ligands, to form a stable entity known as a complex. This process is typical in coordination chemistry where metals interact with non-metal elements. The ligands are usually capable of donating electron pairs to the metal center. In our example, chloride ions \(\text{Cl}^{-}\) act as ligands bonding with copper. The complexes formed can have various structures:
  • The geometry of complexes can be square planar, tetrahedral, or octahedral, depending on the number of ligands involved.
  • Common examples include tetrahedral environments for four ligands, like \[\mathrm{CuCl}_{4}]^{2-}\].
Complex formation is essential in various applications, including catalysis and medicine.
Stability Constants
Stability constants are vital in understanding how strongly a metal ion binds with its ligands in solution. These constants, often denoted as \(K\), measure the extent of complexation reactions.When dealing with logs of these constants, such as \(\log K_1\), \(\log K_2\), it is essential to remember that each constant relates to a step in the complex formation process. The higher the value of \(K\), the stronger the interaction:
  • A higher \(\log K\) value indicates a more stable complex.
  • It determines the likelihood of the metal ion and ligand staying bound together in a given state.
These constants help chemists predict reaction outcomes and are crucial for applications in chemical synthesis and environmental chemistry.
Copper Chloride Complexes
Copper chloride complexes, like \([\mathrm{CuCl}_4]^{2-}\), are examples of metal halide complexes where chloride ions bond with a copper cation. These complexes can range in color and solubility.In forming such complexes:
  • Copper typically forms +2 oxidation state complexes.
  • The chloride ions serve as the ligands, coordinating with the copper to create a stable tetrahedral geometry.
The formation constants associated with copper chloride complexes are studied to understand the full-circuit complex formation.It's these very constants (composition from \(K_1\) to \(K_4\)), together, helping determine the stability and strength of \([\mathrm{CuCl}_4]^{2-}\) in solution. Each step in complex formation contributes incrementally to how we calculate the overall formation constant \(\beta_4\). Understanding these interactions is foundational in fields such as coordination chemistry and bioinorganic chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe how the crystal field theory explains the fact that so many transition metal compounds are colored.

Estimate the total \(\left[\mathrm{Cl}^{-}\right]\) required in a solution that is initially \(0.10 \mathrm{M} \mathrm{CuSO}_{4}\) to produce a visible yellow color. \(\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{2+}+4 \mathrm{Cl}^{-} \rightleftharpoons\left[\mathrm{CuCl}_{4}\right]^{2-}+4 \mathrm{H}_{2} \mathrm{O}\) \(K_{f}=4.2 \times 10^{5}\) Assume that \(99 \%\) conversion of \(\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{2+}\) to \(\left[\mathrm{CuCl}_{4}\right]^{2-}\) is sufficient for this to happen, and ignore the presence of any mixed aqua- chloro complex ions.

Which of these octahedral complexes would you expect to exhibit geometric isomerism? Explain. (a) \(\left[\mathrm{CrOH}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}\) (b) \(\left[\mathrm{CrCl}_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)\left(\mathrm{NH}_{3}\right)_{3}\right]^{+}\) (c) \(\left[\mathrm{CrCl}_{2}(\mathrm{en})_{2}\right]^{+}\) (d) \(\left[\mathrm{CrCl}_{4}(\mathrm{en})\right]^{-}\) (e) \(\left[\mathrm{Cr}(\mathrm{en})_{3}\right]^{3+}\)

If the ion \(\mathrm{Co}^{2+}\) is linked with strong-field ligands to produce an octahedral complex, the complex has one unpaired electron. If \(\mathrm{Co}^{2+}\) is linked with weak-field ligands, the complex has three unpaired electrons. How do you account for this difference?

Indicate what type of isomerism may be found in each of the following cases. If no isomerism is possible, so indicate. (a) \(\left[\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{CuCl}_{4}\right]\) (b) \(\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{SCN}\right]^{4-}\) (c) \(\left[\mathrm{NiCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{+}\) (d) \(\left[\mathrm{PtBrCl}_{2}(\mathrm{py})\right]\) (e) \(\left[\mathrm{Cr}(\mathrm{OH})_{3}\left(\mathrm{NH}_{3}\right)_{3}\right]^{-}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free