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Calcium will reduce \(\mathrm{MgO}(\mathrm{s})\) to \(\mathrm{Mg}(\mathrm{s})\) at all temperatures from 0 to \(2000^{\circ} \mathrm{C}\). Use this fact, together with the melting point ( \(839^{\circ} \mathrm{C}\) ) and boiling point \(\left(1484^{\circ} \mathrm{C}\right)\) of calcium, to sketch a plausible graph of \(\Delta G^{\circ}\) as a function of temperature for the reaction \(2 \mathrm{Ca}(\mathrm{s})+\) \(\mathrm{O}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{CaO}(\mathrm{s})\).

Short Answer

Expert verified
The graph begins with \(\Delta G^{\circ}\) at a negative value at 0°C. There are two points where \(\Delta G^{\circ}\) is zero, which are at the melting point (839°C) and boiling point (1484°C) of Calcium. Otherwise, the \(\Delta G^{\circ}\) is negative from 0 to 2000°C, indicating that the reaction is spontaneous over this entire temperature range.

Step by step solution

01

Identify Reaction Spontaneity

Given that Calcium reduces Magnesium Oxide to Magnesium at all temperatures from 0 to 2000°C, it means the reaction is spontaneous at this temperature range. Hence, \(\Delta G^{\circ}\) is negative throughout this range.
02

Consider the Phase Changes of Calcium

Calcium has a melting point of \(839^{\circ} \mathrm{C}\) and a boiling point of \(1484^{\circ} \mathrm{C}\). At these temperatures, \(\Delta G^{\circ}\) is zero as phase changes are equilibrium processes where Gibbs free energy change is zero.
03

Sketch the \(\Delta G^{\circ}\) vs Temperature Graph

The graph starts with negative \(\Delta G^{\circ}\) at 0°C indicating spontaneous reaction, it then moves to zero at \(839^{\circ} \mathrm{C}\) due to melting point, goes negative again as temperature increases, then to zero at boiling point \(1484^{\circ} \mathrm{C}\), and then again goes negative showing the reaction is still spontaneous at temperature above boiling point of Calcium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is the branch of physics that deals with heat, work, and energy. It's essential to understand how different types of energy transfer and transform. One of the main ideas in thermodynamics is the concept of Gibbs Free Energy (\( \Delta G \)). This tells us whether a process will occur spontaneously. In simpler terms, it helps us understand if a reaction can happen on its own without outside help. Gibbs Free Energy combines enthalpy (\( H \)), temperature (\( T \)), and entropy (\( S \)) into a single value. It's calculated with the formula:\[ \Delta G = \Delta H - T\Delta S \]- **Enthalpy (\( \Delta H \))**: This represents the heat absorbed or released during a reaction.- **Entropy (\( \Delta S \))**: This describes the disorder or randomness in a system.- **Temperature (\( T \))**: It is the measure of the heat in a system measured in Kelvin.In thermodynamics, a negative \( \Delta G \) value means the reaction can occur spontaneously, releasing energy. Positive \( \Delta G \) values mean it needs energy to proceed. By understanding these principles, you can predict how reactions will behave under different conditions.
Spontaneity of Reactions
Spontaneity in chemical reactions hints at whether a reaction can occur on its own. If a reaction is spontaneous, it means it can proceed without needing an external energy source. The Gibbs Free Energy (\( \Delta G \)) is an essential tool to verify this. Here's what the values indicate:
  • **Negative \( \Delta G \)**: This implies a spontaneous reaction. The system releases energy, making it favorable at the given temperature.
  • **Zero \( \Delta G \)**: The system is at equilibrium. There is no net change as the forces driving the reaction balance out.
  • **Positive \( \Delta G \)**: This shows non-spontaneity. The reaction needs outside energy to occur.
Looking at the original exercise, since calcium reduces magnesium oxide at temperatures up to 2000°C, \( \Delta G \) remains negative, signaling spontaneity. Even at phase transition points like the melting and boiling of calcium, the general negativity of \( \Delta G \) across the temperature range confirms that the reaction is favorable.
Phase Transitions
Phase transitions are changes between solid, liquid, and gas phases. Understanding these transitions is vital when examining reactions over broad temperature ranges. Phase transitions are crucial in determining reactions' spontaneity and energy behavior. When substances switch phases at their melting or boiling points, there's a temporary equilibrium in energy terms. This means that the Gibbs Free Energy (\( \Delta G \)) at these points is zero. The system does not release or absorb extra energy overall because the change is balanced. For calcium:
  • At **839°C**, calcium transitions from solid to liquid. The \( \Delta G \) value touches zero, indicating equilibrium.
  • At **1484°C**, calcium changes from liquid to vapor. Again \( \Delta G \) equals zero, showing a balance during this transition.
After these phases, the reaction might revert to being spontaneous, depending on surrounding conditions. Therefore, understanding these transitions helps predict the shifts in reaction spontaneity as temperature changes.

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Most popular questions from this chapter

Write plausible equations for the following reactions occurring in the hydrometallurgy of the coinage metals. (a) Copper is precipitated from a solution of copper(II) sulfate by treatment with \(\mathrm{H}_{2}(\mathrm{g})\) (b) Gold is precipitated from a solution of \(\mathrm{Au}^{+}\) by adding iron(II) sulfate. (c) Copper(II) chloride solution is reduced to copper(I) chloride when treated with \(\mathrm{SO}_{2}(\mathrm{g})\) in acidic solution.

Describe the chemical composition of the material called (a) pig iron; (b) ferromanganese alloy; (c) chromite ore; (d) brass; (e) aqua regia; (f) blister copper; (g) stainless steel.

Covalent bonding is involved in many transition metal compounds. Draw Lewis structures, showing any nonzero formal charges, for the following molecules or ions: (a) \(\mathrm{Hg}_{2}^{2+} ;\) (b) \(\mathrm{Mn}_{2} \mathrm{O}_{7} ;\) (c) \(\mathrm{OsO}_{4}\). [Hint: In (b), there is one \(\mathrm{Mn}-\mathrm{O}-\text { Mn linkage in the molecule. }\rfloor\)

What products are obtained when \(\mathrm{Mg}^{2+}(\mathrm{aq})\) and \(\mathrm{Cr}^{3+}(\mathrm{aq})\) are each treated with a limited amount of NaOH(aq)? With an excess of \(\mathrm{NaOH}(\) aq)? Why are the results different in these two cases?A certain steel is to be analyzed for \(\mathrm{Cr}\) and \(\mathrm{Mn}\). By suitable treatment, the Cr in the steel is oxidized to \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})\) and the \(\mathrm{Mn}\) to \(\mathrm{MnO}_{4}(\mathrm{aq}) . \mathrm{A} 10.000 \mathrm{g}\) sample of steel is used to produce \(250.0 \mathrm{mL}\) of a solution containing \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})\) and \(\mathrm{MnO}_{4}^{-}(\mathrm{aq}) . \mathrm{A} 10.00 \mathrm{mL}\) portion of this solution is added to \(\mathrm{BaCl}_{2}(\mathrm{aq}),\) and by proper adjustment of the \(\mathrm{pH}\), the chromium is completely precipitated as \(\mathrm{BaCrO}_{4}(\mathrm{s}) ; 0.549 \mathrm{g}\) is obtained. A second \(10.00 \mathrm{mL}\) portion of the solution requires exactly \(15.95 \mathrm{mL}\) of \(0.0750 \mathrm{M} \mathrm{Fe}^{2+}(\mathrm{aq})\) for its titration in acidic solution. Calculate the \(\%\) Cr and \% \(\mathrm{Mn}\) in the steel sample. [Hint: In the titration \(\mathrm{MnO}_{4}^{-}(\mathrm{aq})\) is reduced to \(\mathrm{Mn}^{2+}(\mathrm{aq})\) and \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})\) is reduced to \(\left.\mathrm{Cr}^{3+}(\mathrm{aq}) ; \text { the } \mathrm{Fe}^{2+}(\mathrm{aq}) \text { is oxidized to } \mathrm{Fe}^{3+}(\mathrm{aq}) \cdot\right]\)

To separate \(\mathrm{Fe}^{3+}\) and \(\mathrm{Ni}^{2+}\) from an aqueous solution containing both ions, with one cation forming a precipitate and the other remaining in solution, add to the solution (a) \(\mathrm{NaOH}(\mathrm{aq}) ;\) (b) \(\mathrm{H}_{2} \mathrm{S}(\mathrm{g})\) (c) \(\mathrm{HCl}(\mathrm{aq}) ;(\mathrm{d}) \mathrm{NH}_{3}(\mathrm{aq})\)

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