The solubility of \(\mathrm{Cl}_{2}(\mathrm{g})\) in water is \(6.4 \mathrm{g}
\mathrm{L}^{-1}\) at \(25^{\circ} \mathrm{C}\)
Some of this chlorine is present as \(\mathrm{Cl}_{2},\) and some is found as
HOCl or Cl^- For the hydrolysis reaction
$$\begin{array}{c}\mathrm{Cl}_{2}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(1)
\longrightarrow \\
\mathrm{HOCl}(\mathrm{aq})+\mathrm{H}_{3}
\mathrm{O}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq}) \\\K_{c}=4.4 \times
10^{-4}\end{array}$$
For a saturated solution of \(\mathrm{Cl}_{2}\) in water, calculate
\(\left[\mathrm{Cl}_{2}\right],[\mathrm{HOCl}],\left[\mathrm{H}_{3}
\mathrm{O}^{+}\right],\) and \(\left[\mathrm{Cl}^{-}\right]\).