Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write a chemical equation to represent (a) the reduction of silica to elemental silicon by aluminum; (b) the preparation of potassium metasilicate by the high-temperature fusion of silica and potassium carbonate; (c) the reaction of \(\mathrm{Al}_{4} \mathrm{C}_{3}\) with water to produce methane.

Short Answer

Expert verified
(a) SiO2 + 2Al -> Si + Al2O3\n(b) SiO2 + K2CO3 -> K2SiO3 + CO2\n(c) Al4C3 + 12H2O -> 4Al(OH)3 + 3CH4

Step by step solution

01

Reduction of Silica to Elemental Silicon by Aluminum

In this reduction reaction, Silica (Silicon dioxide, SiO2) is reduced to elemental Silicon (Si) by Aluminum (Al). The aluminum gets oxidized to aluminum oxide (Al2O3). The balanced chemical equation for this process is: \n\(SiO_2 + 2Al \rightarrow Si + Al_2O_3\)
02

The preparation of Potassium Metasilicate

Here, Silica (SiO2) and Potassium Carbonate (K2CO3) undergoes high-temperature fusion to form Potassium Metasilicate (K2SiO3) and Carbon dioxide (CO2) as products. The balanced chemical equation for this reaction is: \n\(SiO_2 + K_2CO_3 \rightarrow K_2SiO_3 + CO_2\)
03

Reaction of Al4C3 with water

In this reaction, Aluminum carbide (Al4C3) reacts with water (H2O) to produce methane (CH4) and Aluminum hydroxide (Al(OH)3). The balanced equation for this reaction is: \n\(Al_4C_3 + 12H_2O \rightarrow 4Al(OH)_3 + 3CH_4\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reduction of Silica
The reduction of silica involves converting silica (SiO2), which is silicon dioxide, into pure elemental silicon (Si) with the aid of a reducing agent, which in this case is aluminum (Al). This process is commonly employed in metallurgy and the chemical industry. The chemical transformation can be expressed by writing a balanced chemical equation:
\[SiO_2 + 2Al \rightarrow Si + Al_2O_3\]
In this reaction, aluminum donates electrons to SiO2, reducing it to silicon. Consequently, the aluminum is oxidized, forming aluminum oxide (Al2O3). This type of reaction is crucial in the field of materials science, particularly in the production of silicon for electronic devices and semiconductors, as silicon is a fundamental material in these technologies. To fully understand this process, it's essential to grasp the principles of redox reactions, where one substance is reduced and another oxidized, maintaining the conservation of electrons.
Potassium Metasilicate Preparation
Potassium metasilicate (K2SiO3) can be prepared through the high-temperature fusion of silica (SiO2) and potassium carbonate (K2CO3). This chemical process is central to various industrial applications, including the manufacture of cleaning agents and detergents. The balanced chemical equation for this preparation is:
\[SiO_2 + K_2CO_3 \rightarrow K_2SiO_3 + CO_2\]
Here, under high temperatures, silica reacts with potassium carbonate to form potassium metasilicate and carbon dioxide gas. This preparation is a prime example of a solid-state reaction, a type of reaction where the reactants and the products are in solid forms. Understanding this reaction requires familiarity with the behaviors of ionic compounds when subjected to heat, as well as the effect of temperature on the reactivity of chemical species.
Aluminum Carbide Reaction with Water
Aluminum carbide (Al4C3), when introduced to water (H2O), undergoes a hydrolysis reaction, producing methane (CH4) and aluminum hydroxide (Al(OH)3). The equation representing this reaction is:
\[Al_4C_3 + 12H_2O \rightarrow 4Al(OH)_3 + 3CH_4\]
This reaction is exothermic, releasing energy in the form of heat. It serves as an interesting example of how certain compounds react with water to release gases. Aluminum carbide's reaction with water also has implications in the field of waste management and recycling, as it provides a method of generating hydrocarbons from metal wastes. To appreciate the intricacies of this process, one should have a solid foundation in hydrolysis reactions and the properties of carbides, particularly their reactivity with water and the formation of hydroxides and hydrocarbons.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write plausible chemical equations for the (a) dissolving of lead(II) oxide in nitric acid; (b) heating of \(\operatorname{snCO}_{3}(\mathrm{s}) ;\) (c) reduction of lead(II) oxide by carbon; (d) reduction of \(\mathrm{Fe}^{3+}(\mathrm{aq})\) to \(\mathrm{Fe}^{2+}(\mathrm{aq})\) by \(\mathrm{Sn}^{2+}(\mathrm{aq});\) (e) formation of lead(II) sulfate during high-temperature roasting of lead(II) sulfide.

An analysis of a Solvay-process plant shows that for every \(1.00 \mathrm{kg}\) of \(\mathrm{NaCl}\) consumed, \(1.03 \mathrm{kg}\) of \(\mathrm{NaHCO}_{3}\) are obtained. The quantity of \(\mathrm{NH}_{3}\) consumed in the overall process is \(1.5 \mathrm{kg}.\) (a) What is the percent efficiency of this process for converting NaCl to \(\mathrm{NaHCO}_{3} ?\) (b) Why is so little \(\mathrm{NH}_{3}\) required?

The first electrolytic process to produce sodium metal used molten NaOH as the electrolyte. Write probable half-equations and an overall equation for this electrolysis.

A chemical that should exist as a crystalline solid is seen to be a mixture of a solid and liquid in a container on a storeroom shelf. Give a plausible reason for that observation. Should the chemical be discarded or is it still useful for some purposes?

When a \(0.200 \mathrm{g}\) sample of \(\mathrm{Mg}\) is heated in air, \(0.315 \mathrm{g}\) of product is obtained. Assume that all the Mg appears in the product. (a) If the product were pure \(\mathrm{MgO}\), what mass should have been obtained? (b) Show that the 0.315 g product could be a mixture of \(\mathrm{Mg} \mathrm{O}\) and \(\mathrm{Mg}_{3} \mathrm{N}_{2}.\) (c) What is the mass percent of \(\mathrm{MgO}\) in the \(\mathrm{MgO}-\mathrm{Mg}_{3} \mathrm{N}_{2}\) mixed product?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free