Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A common reference electrode consists of a silver wire coated with AgCl(s) and immersed in 1MKCl AgCl(s)+eAg(s)+Cl(1M)E=0.2223V (a) What is Ecell  when this electrode is a cathode in combination with a standard zinc electrode as an anode? (b) Cite several reasons why this electrode should be easier to use than a standard hydrogen electrode. (c) By comparing the potential of this silver-silver chloride electrode with that of the silver-silver ion electrode, determine Ksp for AgCl.

Short Answer

Expert verified
a) The standard cell potential (Ecell ) of the Ag/AgCl and Zn/Zn++ cell is 0.9823V.\nb) The Ag/AgCl electrode is easier to use than a standard hydrogen electrode due to its safety (no dangerous gases involved), stability of potential, consistency in various temperatures, and wide application range.\nc) To calculate Ksp, we could use the Nernst equation with the cell and standard electrode potentials of the Ag/Ag+ and Ag/AgCl half-cells. However, without those specific experimental values, the exact Ksp can't be computed in this case.

Step by step solution

01

Calculating Standard Cell Potential, Ecell 

The standard cell potential (Ecell ) of a galvanic cell can be calculated using the equation: Ecell =Ecathode Eanode . Given that the standard reduction potential (E) of AgCl is 0.2223 V and that of Zn/Zn++ is -0.76 V, we can substitute these values into the formula to find Ecell .
02

Identifying Advantages of Ag/AgCl Electrode Over Standard Hydrogen Electrode

There are multiple reasons why the Ag/AgCl electrode is easier to use than a standard hydrogen electrode. First, it is much easier to handle physically, as it doesn't involve the handling of a dangerous gas such as hydrogen. Additionally, it maintains a stable potential over an extended period and is consistent in various temperatures. It also has a wide range of applications, as it can be used in both laboratory and industrial settings.
03

Calculating the Solubility Product Constant (Ksp) for AgCl

The solubility product constant, Ksp, can be found using the Nernst equation, which relates the reduction potential of a redox reaction to the standard electrode potential, the temperature, and the reaction quotient. We'll need to know the standard electrode potential for the Ag/Ag+ half-cell and the experimental cell potential. Once we have these, we can rearrange the Nernst equation and solve for Ksp.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Silver-Silver Chloride Electrode
The Silver-Silver Chloride (Ag/AgCl) electrode is a common reference electrode used in electrochemistry. It consists of a silver wire coated with solid silver chloride (AgCl), immersed in a solution of potassium chloride (KCl). This setup creates a stable environment where the electrode potential remains constant. Typically, the standard electrode potential (E) for the Ag/AgCl electrode is 0.2223 V.

The Ag/AgCl electrode is preferred over other reference electrodes, such as the standard hydrogen electrode, because it is safer and more convenient. No handling of gases like hydrogen is necessary, which simplifies experimental setups and improves safety. Additionally, the Ag/AgCl electrode provides a stable reference potential, making it useful for various electrochemical measurements in both research and industry. Its durability and ease of use further solidify its status as a reliable tool in many applications.
Standard Cell Potential
The Standard Cell Potential is a critical concept in electrochemistry. It is used to determine how much voltage a galvanic cell can produce under standard conditions when all reactants and products are at their standard states, often at 1 M concentration and 1 atm pressure. To find this potential, you use the equation: Ecell=EcathodeEanode.

For example, in a cell with a Silver-Silver Chloride electrode as the cathode and a zinc electrode as the anode, the standard potentials are given for each: 0.2223 V for the Ag/AgCl electrode and -0.76 V for the Zn/Zn++ electrode, respectively. By substituting these values into the equation, you can calculate the standard cell potential for the entire electrochemical cell. This potential is an essential factor for determining the feasibility and direction of a chemical reaction within the cell.
Solubility Product Constant (Ksp)
The Solubility Product Constant, often abbreviated as Ksp, is a crucial parameter in chemistry, especially when dealing with sparingly soluble compounds like silver chloride (AgCl). It quantifies the extent to which a compound dissociates into its constituent ions in solution. For a compound like AgCl, which dissociates into Ag+ and Cl- ions, the formula for Ksp is: Ksp=[Ag+][Cl]

To find Ksp for AgCl, you can use the Nernst equation, which connects the cell potential with the activities of the reactants and products. When comparing the potential of the Ag/AgCl electrode with a silver-silver ion electrode, the Nernst equation reveals the relationship between the electrode potential and Ksp. Through this approach, you can calculate the solubility product, thereby gaining insight into the solubility characteristics of AgCl under specific conditions. Understanding Ksp is critical for applications in qualitative analysis, and predicting the formation of precipitates in chemical reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Of the following statements concerning electrochemical cells, the correct ones are: (a) The cathode is the negative electrode in both voltaic and electrolytic cells. (b) The function of a salt bridge is to permit the migration of electrons between the half-cell compartments of an electrochemical cell. (c) The anode is the negative electrode in a voltaic cell. (d) Electrons leave the cell from either the cathode or the anode, depending on what electrodes are used. (e) Reduction occurs at the cathode in both voltaic and electrolytic cells. (f) If electric current is drawn from a voltaic cell long enough, the cell becomes an electrolytic cell. (g) The cell reaction is an oxidationreduction reaction.

You prepare 1.00L of a buffer solution that is 1.00M NaH2PO4 and 1.00MNa2HPO4. The solution is divided in half between the two compartments of an electrolytic cell. Both electrodes used are Pt. Assume that the only electrolysis is that of water. If 1.25 A of current is passed for 212 min, what will be the pH in each cell compartment at the end of the electrolysis?

Your task is to determine E for the reduction of CO2(g) to C3H8(g) in two different ways and to explain why each gives the same result. (a) Consider a fuel cell in which the cell reaction corresponds to the complete combustion of propane gas. Write the half-cell reactions and the overall reaction. Determine ΔG and Ecell  for the reaction, then obtain ECO2/C3H8 (b) Without considering the oxidation that occurs simultaneously, obtain ECO2/C3H8 directly from tabulated thermodynamic data for the reduction half-reaction.

A test for completeness of electrodeposition of Cu from a solution of Cu2+(aq) is to add NH3(aq). A blue color signifies the formation of the complex ion [Cu(NH3)4]2+(Kf=1.1×1013). Let 250.0mL of 0.1000MCuSO4( aq ) be electrolyzed with a 3.512A current for 1368 s. At this time, add a sufficient quantity of NH3( aq ) to complex any remaining Cu2+ and to maintain a free [NH3]=0.10M. If [Cu(NH3)4]2+ is detectable at concentrations as low as 1×105M should the blue color appear?

The value of Ecell  for the reaction Zn(s)+ Pb2+(aq)Zn2+(aq)+Pb(s) is 0.66V. This means that for the reaction Zn(s)+Pb2+(0.01M) Zn2+(0.10M)+Pb(s),Ecell  equals (a)0.72V (b) 0.69V; (c) 0.66V; (d) 0.63V

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free