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A voltaic cell, with \(E_{\text {cell }}=0.180 \mathrm{V},\) is constructed as follows: $$\mathrm{Ag}(\mathrm{s})\left|\mathrm{Ag}^{+}\left(\operatorname{satd} \mathrm{Ag}_{3} \mathrm{PO}_{4}\right) \| \mathrm{Ag}^{+}(0.140 \mathrm{M})\right| \mathrm{Ag}(\mathrm{s})$$ What is the \(K_{\mathrm{sp}}\) of \(\mathrm{Ag}_{3} \mathrm{PO}_{4} ?\)

Short Answer

Expert verified
To solve this problem, first use the Nernst equation to determine the concentration of Ag+ in the solution. Then use this concentration to calculate the solubility product constant (\(K_{\mathrm{sp}}\)) of \(\mathrm{Ag}_3 \mathrm{PO}_4\).

Step by step solution

01

Identify the relevant equations

The Nernst equation is given by: \[E_{\text {cell }}=E^{\circ}-\left(\frac{0.0592}{n}\right) \log Q\]The value of \(Q\) for the reaction is \([Ag^{+}]\). Since there is no information about the standard electrode potential \(E^{\circ}\) the equation simplifies to:\[E_{\text {cell }}=-\left(\frac{0.0592}{n}\right) \log Q\]or \[E_{\text {cell }}=\left(\frac{-0.0592}{n}\right) \log \left(\frac{1}{[Ag^{+}]}\right)\]
02

Calculate the concentration of Ag+

In the voltaic cell, the reduction potential is given as 0.180 V. Substituting this into the Nernst equation, we get:\[0.180 = \left(\frac{-0.0592}{n}\right) \log \left(\frac{1}{[Ag^{+}]}\right)\]Assuming a single-electron process (n=1), we can solve for [Ag+]. This leads to:\[\log \left(\frac{1}{[Ag^{+}]}\right) = \frac{0.180}{-0.0592}\]Calculate [Ag+] to get:\[[Ag^+] = 0.140 \, M\]
03

Calculate the Ksp

The equilibrium constant for the solubility of \(\mathrm{Ag}_3 \mathrm{PO}_4\) is:\[K_{\mathrm{sp}} = [Ag^+]^3[PO_4^{3-}]\]For a saturated solution of \(\mathrm{Ag}_3 \mathrm{PO}_4\), [Ag+] is three times the [PO4^3-]. This leads to \[K_{\mathrm{sp}} = [Ag^+]^3 \times \left(\frac{[Ag^+]}{3}\right)\]Substitute [Ag+] with the concentration calculated from Step 2 and solve for \(K_{\mathrm{sp}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nernst Equation
The Nernst equation is an essential element in understanding electrochemical cells and their potentials. This equation allows us to calculate the cell potential based on the concentrations of the ions involved. It is expressed as follows: \[E_{\text{cell}} = E^{\circ} - \left(\frac{0.0592}{n}\right) \log Q\]Here, \(E^{\circ}\) is the standard cell potential, \(n\) is the number of moles of electrons exchanged in the electrochemical reaction, and \(Q\) is the reaction quotient. In simpler terms, the Nernst Equation helps us understand how changes in concentration can affect the voltage generated by an electrochemical cell.
When we do not have the standard electrode potential \(E^{\circ}\) for a system, or when dealing with a system under non-standard conditions (like different concentrations), the Nernst equation becomes crucial for calculating the cell potential. It adjusts the potential for changes in ion concentrations.
The equation can also be rearranged, like in the problem, to solve for ion concentrations when potential data is available. This is integral in determining the extent of solubility of a species or the strength of an electrochemical cell.
Understanding the Nernst equation helps in configuring and predicting the behavior of real and practical electrochemical systems, such as batteries and sensors.
Solubility Product Constant
Solubility Product Constant, often abbreviated as \(K_{\text{sp}}\), is a vital concept when dealing with the solubility of sparingly soluble salts in solution. It is the product of the concentrations of the ions of a salt, each raised to the power of its stoichiometric coefficient in the balanced equation.
For example, for silver phosphate \(\text{Ag}_3\text{PO}_4\), which dissolves to form silver ions \(\text{Ag}^+\) and phosphate ions \(\text{PO}_4^{3-}\) in water, the \(K_{\text{sp}}\) expression is given by:\[K_{\text{sp}} = [Ag^+]^3[PO_4^{3-}]\]The value of \(K_{\text{sp}}\) provides a measure of the solubility. It signifies how much of the salt can dissolve in water to form a saturated solution. A high \(K_{\text{sp}}\) indicates greater solubility.
In the provided exercise, by linking the concentration of silver ions from the silver phosphate dissolution to the cell potential via the Nernst equation, we can determine \(K_{\text{sp}}\).
This calculation is crucial in analytical chemistry, environmental science, and various fields where solubility products govern the movement and reactivity of substances in liquid environments.
Electrochemistry
Electrochemistry is the branch of chemistry that studies the relationship between electricity and chemical reactions. It encompasses a range of phenomena from batteries to corrosion, to the electrolysis processes used in industry.
In the context of the voltaic cell mentioned, electrochemistry is at play in generating electric current from chemical reactions. Voltaic (or galvanic) cells use spontaneous redox reactions to generate an electric current.
These cells consist of two different electrodes immersed in electrolyte solutions, where oxidation and reduction occur. The two half-reactions are connected by a wire through which electrons can flow, generating a current.
  • Anode: The electrode where oxidation occurs. It gives off electrons to the external circuit.
  • Cathode: The electrode where reduction takes place. It receives electrons from the circuit.
Understanding electrochemistry is fundamental in designing batteries, understanding corrosion, and even biochemistry processes, where electron transfers are crucial.
Silver Phosphate (Ag3PO4)
Silver Phosphate \(\text{Ag}_3\text{PO}_4\) is a sparingly soluble ionic compound, often notable for its bright yellow color and use in photography and as an antimicrobial agent.
Silver phosphate dissolves in water forming silver ions \(\text{Ag}^+\) and phosphate ions \(\text{PO}_4^{3-}\). This dissolution is characterized by its solubility product \(K_{\text{sp}}\), which helps quantify its solubility in water:\[\text{Ag}_3\text{PO}_4 \rightleftharpoons 3\text{Ag}^+ + \text{PO}_4^{3-}\]\[K_{\text{sp}} = [Ag^+]^3[PO_4^{3-}]\]Silver phosphate's relatively low \(K_{\text{sp}}\) limits its solubility, which has implications in processes where low concentrations of silver ions are necessary.
In the context of electrochemistry, when used in voltaic cells, as shown in the exercise, the concentration of silver ions from the saturated solution of silver phosphate is a determinant factor in calculating the potential of the cell using the Nernst equation.
This establishes a relationship between the solubility of the compound and its electrolytic behavior, highlighting the interconnectedness in chemical principles.

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Most popular questions from this chapter

Silver tarnish is mainly \(\mathrm{Ag}_{2} \mathrm{S}\) : $$\begin{array}{r}\mathrm{Ag}_{2} \mathrm{S}(\mathrm{s})+2 \mathrm{e}^{-} \longrightarrow 2 \mathrm{Ag}(\mathrm{s})+\mathrm{S}^{2-}(\mathrm{aq}) \\\E^{\circ}=-0.691 \mathrm{V}\end{array}$$ A tarnished silver spoon is placed in contact with a commercially available metallic product in a glass baking dish. Boiling water, to which some \(\mathrm{NaHCO}_{3}\) has been added, is poured into the dish, and the product and spoon are completely covered. Within a short time, the removal of tarnish from the spoon begins. (a) What metal or metals are in the product? (b) What is the probable reaction that occurs? (c) What do you suppose is the function of the \(\mathrm{NaHCO}_{3} ?\) (d) An advertisement for the product appears to make two claims: (1) No chemicals are involved, and (2) the product will never need to be replaced. How valid are these claims? Explain.

Consider two cells involving two metals \(X\) and \(Y\) $$\begin{aligned} \mathrm{X}(\mathrm{s})\left|\mathrm{X}^{+}(\mathrm{aq})\right|\left|\mathrm{H}^{+}(\mathrm{aq}), \mathrm{H}_{2}(\mathrm{g}, 1 \mathrm{bar})\right| \mathrm{Pt}(\mathrm{s}) & \\\ \mathrm{X}(\mathrm{s})\left|\mathrm{X}^{+}(\mathrm{aq}) \| \mathrm{Y}^{2+}(\mathrm{aq})\right| \mathrm{Y}(\mathrm{s}) \end{aligned}$$ In the first cell electrons flow from the metal \(X\) to the standard hydrogen electrode. In the second cell electrons flow from metal \(X\) to metal Y. Is \(E_{x^{+} / x}^{\circ_{+}}\) greater orless than zero? Is \(E_{x^{+} / x}^{\circ}>E_{\mathrm{Y}^{2+}},_{\mathrm{Y}} ?\) Explain.

Of the following statements concerning electrochemical cells, the correct ones are: (a) The cathode is the negative electrode in both voltaic and electrolytic cells. (b) The function of a salt bridge is to permit the migration of electrons between the half-cell compartments of an electrochemical cell. (c) The anode is the negative electrode in a voltaic cell. (d) Electrons leave the cell from either the cathode or the anode, depending on what electrodes are used. (e) Reduction occurs at the cathode in both voltaic and electrolytic cells. (f) If electric current is drawn from a voltaic cell long enough, the cell becomes an electrolytic cell. (g) The cell reaction is an oxidationreduction reaction.

Describe in words how you would calculate the standard potential of the \(\mathrm{Fe}^{2+} / \mathrm{Fe}(\mathrm{s})\) couple from those of \(\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}\) and \(\mathrm{Fe}^{3+} / \mathrm{Fe}(\mathrm{s})\).

It is sometimes possible to separate two metal ions through electrolysis. One ion is reduced to the free metal at the cathode, and the other remains in solution. In which of these cases would you expect complete or nearly complete separation: (a) \(\mathrm{Cu}^{2+}\) and \(\mathrm{K}^{+} ;\) (b) \(\mathrm{Cu}^{2+}\) and \(\mathrm{Ag}^{+} ;\) (c) \(\mathrm{Pb}^{2+}\) and \(\mathrm{Sn}^{2+} ?\) Explain.

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