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In your own words, define or explain the following terms or symbols: (a) mmol; (b) HIn; (c) equivalence point of a titration; (d) titration curve.

Short Answer

Expert verified
A millimole (mmol) is \(10^{-3}\) moles. HIn is a symbol used to represent a type of weak acid indicator that changes color based on the pH of the solution. The equivalence point of a titration is the point at which the quantity of titrant added is exactly enough to neutralize/complex the analyte in the sample. A titration curve is a graph of pH (or some other indicator of reaction progress) against volume of added titrant, used to identify the equivalence point and pKa of a weak acid.

Step by step solution

01

Definition of mmol

mmol is a symbol used for millimole, a unit of chemical measurement that is equal to \(10^{-3}\) moles. Mole is the SI unit expressing the amount of substance. A millimole, therefore, is one thousandth of a mole.
02

Explanation of HIn

HIn, in the context of acid-base chemistry, commonly represents a weak acid indicator. HIn is in equilibrium with its ionized form (In-) in solution. Changes in pH can change the ratio of HIn to In-, causing the solution to change color.
03

Equivalence point of a titration

Equivalence point of a titration is the point at which the added titrant is chemically equivalent to the quantity of analyte (substance being analysed) in the sample. In other words, it's the point at which all the analyte has reacted with the titrant.
04

Titration Curve

A titration curve is a graphical representation of the pH of a solution as a function of the volume of the added titrating agent, or titrant. It can be used to find the equivalence point and is instrumental in identifying the pKa of a weak acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mmol Definition
Understanding quantities in chemistry is fundamental, and the millimole (mmol) is a key unit of measurement that students encounter. Essentially, a mmol is to a mole what a millimeter is to a meter—it's a thousand times smaller. To put it mathematically, one millimole equals \(10^{-3}\) moles.

In practical terms, if you were to compare moles to bricks in building a house, then having a mmol would be like having just one brick out of a thousand. This level of precision is important in experiments and reactions where using the exact amounts of substances is crucial to ensure accuracy and replicability. When working with reactions on a smaller scale, such as in a laboratory class, you'll commonly see mmol used to measure the amounts of reactants and products.
Acid-Base Indicators
Moving into the colorful world of chemical reactions, acid-base indicators serve as the traffic lights. These indicators, typically denoted by 'HIn', are substances that change color based on the pH level of the solution they are in.

Think of 'HIn' as a chameleon, with the 'H' representing the hydrogen ion that can be present or absent depending on the surroundings. In an acidic environment, you'll have more HIn (the acid form), because the hydrogen ions are abundant. In a basic environment, those hydrogen ions get used up, leaving you with In- (the base form), which often has a different color.

These changes make it visually easier to determine at what pH range a reaction is taking place, especially during titrations, and this visual cue helps scientists know when they are at or near the target pH without the need for electronic instruments.
Equivalence Point
The equivalence point is a term that often pops up during titration experiments, an Everest of a reaction where the climber—our titrant—has precisely reached the top, meeting the analyte in exact stoichiometric proportion.

In more simple terms, it's that critical juncture where the quantity of titrant added equals the amount of substance present in the sample – think of pouring lemonade into your tea until you can't taste the tea anymore because the flavors are perfectly balanced. This is crucial for determining concentrations of a substance within a sample or for understanding reaction stoichiometry. Knowing the equivalence point is like having a map; it guides you to where the reaction has achieved its ideal balance.
Titration Curve Analysis
Finally, let's talk about the roadmap of a chemical reaction, known as the titration curve. This graph serves as a visual story of the journey your titration has taken. It shows the changing pH of the solution as the titrant is added little by little.

A typical titration curve starts out with the pH on the y-axis and the volume of titrant added on the x-axis. As the titrant is added, you can watch the pH rise or fall, gradually at first, and then quite sharply around the equivalence point—this sharp part is often called the 'end point'. It's like watching the climax of a movie, where you can practically predict the ending just by seeing how drastic the events are turning.

By understanding and analyzing the titration curve, chemists can determine crucial information such as the pKa value of a weak acid, or the entire strength of an acid or base, helping them to predict and control the outcomes of their reactions.

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Most popular questions from this chapter

A 20.00 mL sample of \(\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{aq})\) requires \(18.67 \mathrm{mL}\) of \(0.1885 \mathrm{M} \mathrm{NaOH}\) for titration from the first to the second equivalence point. What is the molarity of the \(\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{aq}) ?\)

Sodium phosphate, \(\mathrm{Na}_{3} \mathrm{PO}_{4},\) is made commercially by first neutralizing phosphoric acid with sodium carbonate to obtain \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\). The \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\) is further neutralized to \(\mathrm{Na}_{3} \mathrm{PO}_{4}\) with \(\mathrm{NaOH}\) (a) Write net ionic equations for these reactions. (b) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) is a much cheaper base than is \(\mathrm{NaOH}\) Why do you suppose that \(\mathrm{NaOH}\) must be used as well as \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) to produce \(\mathrm{Na}_{3} \mathrm{PO}_{4} ?\)

Explain why the volume of \(0.100 \mathrm{M} \mathrm{NaOH}\) required to reach the equivalence point in the titration of \(25.00 \mathrm{mL}\) of \(0.100 \mathrm{M}\) HA is the same regardless of whether HA is a strong or a weak acid, yet the \(\mathrm{pH}\) at the equivalence point is not the same.

The \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}-\mathrm{HPO}_{4}^{2-}\) combination plays a role in maintaining the pH of blood. (a) Write equations to show how a solution containing these ions functions as a buffer. (b) Verify that this buffer is most effective at \(\mathrm{pH} 7.2\) (c) Calculate the \(\mathrm{pH}\) of a buffer solution in which \(\left[\mathrm{H}_{2} \mathrm{PO}_{4}\right]=0.050 \mathrm{M}\) and \(\left[\mathrm{HPO}_{4}^{2-}\right]=0.150 \mathrm{M} .[\)Hint: Focus on the second step of the phosphoric acid ionization.]

Calculate the pH at the points in the titration of \(25.00 \mathrm{mL}\) of \(0.160 \mathrm{M} \mathrm{HCl}\) when (a) \(10.00 \mathrm{mL}\) and \((\mathrm{b}) 15.00 \mathrm{mL}\) of 0.242 M KOH have been added.

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