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Solution (a) is \(100.0 \mathrm{mL}\) of \(0.100 \mathrm{M} \mathrm{HCl}\) and solution (b) is \(150.0 \mathrm{mL}\) of \(0.100 \mathrm{M} \mathrm{NaCH}_{3} \mathrm{COO}\). A few drops of thymol blue indicator are added to each solution. What is the color of each solution? What is the color of the solution obtained when these two solutions are mixed?

Short Answer

Expert verified
Solution (a) will turn the thymol blue red. Solution (b) will turn the thymol blue blue. When the two solutions are mixed, the thymol blue will turn yellow/green.

Step by step solution

01

Identify the nature of solutions

First identify the nature of solutions. Here, solution (a) is hydrochloric acid (HCl), therefore it's acidic. Solution (b) is sodium acetate (NaCH3COO), a salt of a strong base and weak acid, so it is slightly basic.
02

Determine the color of the indicator in each solution

Thymol blue changes color based on the pH of the solution it is in. In acidic solutions (pH < 2.8), it is red. In neutral solutions (pH = 7), it is yellow/green and in basic solutions (pH > 8.2) it is blue. So, solution (a) will turn the thymol blue red because it's acidic. Solution (b), being slightly basic, will turn the thymol blue blue.
03

Determine the color of indicator when solutions are mixed

When these two solutions are mixed, they will neutralize each other as an acid reacts with a base to make a salt and water. The pH of the resulting solution will be about 7, which is neutral. So, upon mixing, the thymol blue will become yellow/green.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thymol Blue Indicator
Thymol blue is a pH indicator used in chemistry to determine the acidity or basicity of a solution. It changes color at different pH levels, allowing scientists to estimate the pH of the solution visually.

Thymol blue is particularly useful across certain pH ranges with specific color transitions:
  • In strongly acidic solutions with a pH below 2.8, thymol blue appears red.
  • In neutral solutions, roughly around a pH of 7, it shifts to a yellow/green color.
  • In basic environments with a pH above 8.2, thymol blue takes on a blue hue.
This visual guide can be extremely helpful when conducting experiments, as it provides a quick and simple way to gauge the pH without using electronic equipment.

It's important to note that thymol blue is one of many pH indicators available, each with its own range and color changes. Selecting the right indicator depends on the expected pH change in the experiment.
pH Scale
The pH scale is a numerical scale that ranges from 0 to 14 and is used to specify how acidic or basic a water-based solution is. "pH" stands for "potential of hydrogen" and reflects the concentration of hydrogen ions in the solution.

Here's a simple breakdown of the scale:
  • Solutions with a pH less than 7 are considered acidic. The lower the pH, the stronger the acid.
  • A pH of exactly 7 is neutral, meaning the solution is neither acidic nor basic. Pure water is a common example of a neutral solution.
  • Solutions with a pH greater than 7 are basic (also known as alkaline). The higher the pH, the stronger the base.
The pH scale is logarithmic, meaning each whole number increase on the scale represents a tenfold increase in basicity, and conversely, each decrease represents a tenfold increase in acidity.

The pH value is a crucial element in chemistry because it influences the behavior of molecules, the rate of chemical reactions, and biological processes.
Neutralization Reaction
A neutralization reaction is a chemical reaction that occurs when an acid and a base interact to form a salt and water. This type of reaction is critical in maintaining pH balance in various chemical processes.

During a neutralization reaction, the hydrogen ions (\( ext{H}^+ \)) from the acid react with hydroxide ions (\( ext{OH}^- \)) from the base, resulting in the formation of water (\( ext{H}_2 ext{O} \)). The general equation for a neutralization reaction can be written as:
\[ ext{Acid} + ext{Base} ightarrow ext{Salt} + ext{Water} \]
In the specific case of the original exercise with hydrochloric acid (\( ext{HCl} \)) and sodium acetate (\( ext{NaCH}_3 ext{COO} \)), they react to produce sodium chloride (\( ext{NaCl} \)) and acetic acid (\( ext{CH}_3 ext{COOH} \)). However, what is notable in solution is the dominant reaction between the hydrogen and hydroxide ions forming water, leading to a neutral pH level of around 7.

Neutralization reactions are not just laboratory exercises but are fundamental to many real-world applications, such as antacid tablets neutralizing stomach acid or wastewater treatment processes adjusting industrial effluent pH levels.

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Most popular questions from this chapter

Phenol red indicator changes from yellow to red in the pH range from 6.6 to \(8.0 .\) Without making detailed calculations, state what color the indicator will assume in each of the following solutions: (a) \(0.10 \mathrm{M} \mathrm{KOH}\) (b) \(0.10 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH} ;\) (c) \(0.10 \mathrm{M} \mathrm{NH}_{4} \mathrm{NO}_{3} ;\) (d) \(0.10 \mathrm{M}\) HBr; (e) \(0.10 \mathrm{M} \mathrm{NaCN} ;\) (f) \(0.10 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH}-0.10 \mathrm{M}\) \(\mathrm{NaCH}_{3} \mathrm{COO}\).

The Henderson-Hasselbalch equation can be written as \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}-\log \left(\frac{1}{\alpha}-1\right)\) where \(\alpha=\frac{\left[\mathrm{A}^{-}\right]}{\left[\mathrm{A}^{-}\right]+[\mathrm{HA}]}\) Thus, the degree of ionization \((\alpha)\) of an acid can be determined if both the \(\mathrm{pH}\) of the solution and the \(\mathrm{p} K_{\mathrm{a}}\) of the acid are known. (a) Use this equation to plot the pH versus the degree of ionization for the second ionization constant of phosphoric acid \(\left(K_{\mathrm{a}}=6.3 \times 10^{-8}\right)\) (b) If \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\) what is the degree of ionization? (c) If the solution had a pH of 6.0 what would the value of \(\alpha\) be?

The pH of a solution of \(19.5 \mathrm{g}\) of malonic acid in \(0.250 \mathrm{L}\) is \(1.47 .\) The pH of a \(0.300 \mathrm{M}\) solution of sodium hydrogen malonate is 4.26. What are the values of \(K_{\mathrm{a}_{1}}\) and \(K_{\mathrm{a}_{2}}\) for malonic acid?

In the titration of \(10.00 \mathrm{mL}\) of \(0.04050 \mathrm{M} \mathrm{HCl}\) with \(0.01120 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2}\) in the presence of the indicator 2,4-dinitrophenol, the solution changes from colorless to yellow when 17.90 mL of the base has been added. What is the approximate value of \(\mathrm{p} K_{\mathrm{HIn}}\) for 2,4 -dinitrophenol? Is this a good indicator for the titration?

You are asked to prepare a \(\mathrm{KH}_{2} \mathrm{PO}_{4}-\mathrm{Na}_{2} \mathrm{HPO}_{4}\) solu- tion that has the same \(\mathrm{pH}\) as human blood, 7.40 (a) What should be the ratio of concentrations \(\left[\mathrm{HPO}_{4}^{2-}\right] /\left[\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\right]\) in this solution? (b) Suppose you have to prepare \(1.00 \mathrm{L}\) of the solution described in part (a) and that this solution must be isotonic with blood (have the same osmotic pressure as blood). What masses of \(\mathrm{KH}_{2} \mathrm{PO}_{4}\) and of \(\mathrm{Na}_{2} \mathrm{HPO}_{4} \cdot 12 \mathrm{H}_{2} \mathrm{O}\) would you use? [Hint: Refer to the definition of isotonic on page \(580 .\) Recall that a solution of \(\mathrm{NaCl}\) with \(9.2 \mathrm{g} \mathrm{NaCl} / \mathrm{L}\) solution is isotonic with blood, and assume that \(\mathrm{NaCl}\) is completely ionized in aqueous solution.]

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