In chemistry, the concentration of solutions is a fundamental concept representing the amount of solute dissolved in a given volume of solvent. For this exercise, calculating the concentration is essential to determining the acid dissociation constant \(K_a\).When you're given the mass of a compound such as sodium lactate, \(\text{NaCH}_3\text{CH}_2\text{COO}\), converting this mass to moles is the first step. Utilizing the molar mass, you can calculate the moles:
- Molar mass of sodium lactate = 112 g/mol
- Mass = 1 g
- Moles = \( \frac{1 \, \text{g}}{112 \, \text{g/mol}} = 0.00893 \, \text{mol} \)
Since the solution's volume is 100 mL (or 0.1 L), the molarity \(M\) of sodium lactate is then calculated as:\[M = \frac{0.00893 \, \text{mol}}{0.1 \, \text{L}} = 0.0893 \, \text{M}\]These concentration values are essential for plugging into the \(K_a\) expression \(K_a = \frac{[H_3O^+][A^-]}{[HA]}\), where \([A^-]\) and \([HA]\) reflect the concentrations of the lactate ion and lactic acid respectively. By understanding and calculating these concentrations, one can further analyze and understand the behaviors of acidic and basic solutions.