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Three different sets of data of \([\mathrm{A}]\) versus time are giv the following table for the reaction \(A \longrightarrow\) prod [Hint: There are several ways of arriving at answer each of the following six questions. $$\begin{array}{cccccc} \hline \text { I } & & \text { II } & & \text { III } & \\ \hline \begin{array}{c} \text { Time, } \\ \text { s } \end{array} & \text { [A], M } & \begin{array}{c} \text { Time, } \\ \text { s } \end{array} & \text { [A], M } & \begin{array}{c} \text { Time, } \\ \text { s } \end{array} & \text { [A], M } \\ \hline 0 & 1.00 & 0 & 1.00 & 0 & 1.00 \\ 25 & 0.78 & 25 & 0.75 & 25 & 0.80 \\ 50 & 0.61 & 50 & 0.50 & 50 & 0.67 \\ 75 & 0.47 & 75 & 0.25 & 75 & 0.57 \\ 100 & 0.37 & 100 & 0.00 & 100 & 0.50 \\ 150 & 0.22 & & & 150 & 0.40 \\ 200 & 0.14 & & & 200 & 0.33 \\ 250 & 0.08 & & & 250 & 0.29 \\ \hline \end{array}$$ What is the approximate half-life of the first-order reaction?

Short Answer

Expert verified
The approximate half-life of the first-order reaction is 75 seconds.

Step by step solution

01

Identify Presented Data

The concentration-time data is presented in three sets (I, II, and III). All sets start with the initial concentration of \([A]\) as 1.00 M. We are interested in Set I, as it corresponds to the first-order kinetic reaction in this exercise.
02

Locate Half of Initial Concentration

Half of the initial concentration is 1.00 M / 2 = 0.50 M. In Set I, the given concentration closest to 0.5M is 0.47M. This concentration is observed at time 75 s.
03

Determine the Half-Life

As the half-life is defined by the time it takes for concentration to decrease to half of its initial value, by inspection of the data, the half-life is approximately the same as the time when [A] became approximately 0.50M. Therefore, the half-life for this reaction is about 75 s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics involves the study of how quickly chemical reactions occur. It provides insights into the speed of a reaction and the factors affecting this speed.
In kinetic studies, changes in the concentration of reactants and products over time are monitored to figure out the rate at which a reaction proceeds.
  • Different reactions happen at different speeds. Some are incredibly fast, like explosions, while others are slow, like rusting.
  • Understanding kinetics helps in optimizing conditions to speed up desirable reactions, such as in industrial manufacturing, or to slow down unwanted reactions, like food spoiling.
By examining the concentration-time data, as given in the table, we can determine the rate law of a reaction, which tells us how the concentrations of reactants influence the rate. It plays a crucial role in determining the half-life of reactions.
First-Order Reaction
In chemical kinetics, a first-order reaction has a rate that depends linearly on one concentration term.
In other words, the rate of reaction is directly proportional to the concentration of a single reactant.
If the concentration of the reactant decreases by half, the rate of the reaction also decreases by half.
  • The rate law for a first-order reaction is written as: \[ ext{Rate} = k[A] \] where \( k \) is the rate constant, and \([A]\) is the concentration of the reactant.
  • First-order reactions are characterized by having a constant half-life, irrespective of the initial concentration.
In the exercise, set I shows the concentration of \([ ext{A} ]\) decreasing gradually. By demonstrating that the half-life remains consistent, we can verify that the reaction is first-order.
Concentration-Time Data
Concentration-time data is crucial in kinetics as it records how the concentration of reactants changes over time.
Looking at this data helps to decide the reaction order and the reaction rate law.
For the given exercise, the data sets expose how the concentration of substance \([ ext{A} ]\) changes at certain time intervals.
  • To determine the half-life, which is the time it takes for the concentration to decrease to half its original value, we identify the time at which the concentration reaches half of its initial value.
  • In set I from the exercise, the concentration data reveals that \([ ext{A} ]\) falls from 1.00M to approximately 0.50M around 75 seconds, indicating the half-life.
Examining concentration-time data not only helps in calculating half-lives but also in comprehending the overall mechanism of the reaction.

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Most popular questions from this chapter

The following data were obtained for the dimerization of 1,3 -butadiene, \(2 \mathrm{C}_{4} \mathrm{H}_{6}(\mathrm{g}) \longrightarrow \mathrm{C}_{8} \mathrm{H}_{12}(\mathrm{g}),\) at 600 K: \(t=0 \min ,\left[\mathrm{C}_{4} \mathrm{H}_{6}\right]=0.0169 \mathrm{M} ; 12.18 \mathrm{min}, 0.0144 \mathrm{M} ; 24.55 \mathrm{min}, 0.0124 \mathrm{M} ; 42.50 \mathrm{min}, 0.0103 \mathrm{M}, 68.05 \min , 0.00845 \mathrm{M}.\) (a) What is the order of this reaction? (b) What is the value of the rate constant, \(k ?\) (c) At what time would \(\left[\mathrm{C}_{4} \mathrm{H}_{6}\right]=0.00423 \mathrm{M} ?\) (d) At what time would \(\left[\mathrm{C}_{4} \mathrm{H}_{6}\right]=0.0050 \mathrm{M} ?\)

A reaction is \(50 \%\) complete in 30.0 min. How long after its start will the reaction be \(75 \%\) complete if it is (a) first order; (b) zero order?

The following first-order reaction occurs in \(\mathrm{CCl}_{4}(1)\) at \(45^{\circ} \mathrm{C}: \mathrm{N}_{2} \mathrm{O}_{5} \longrightarrow \mathrm{N}_{2} \mathrm{O}_{4}+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) .\) The rate constant is \(k=6.2 \times 10^{-4} \mathrm{s}^{-1} .\) An \(80.0 \mathrm{g}\) sample of \(\mathrm{N}_{2} \mathrm{O}_{5}\) in \(\mathrm{CCl}_{4}(\mathrm{l})\) is allowed to decompose at \(45^{\circ} \mathrm{C}.\) (a) How long does it take for the quantity of \(\mathrm{N}_{2} \mathrm{O}_{5}\) to be reduced to \(2.5 \mathrm{g} ?\) (b) How many liters of \(\mathrm{O}_{2},\) measured at \(745 \mathrm{mmHg}\) and \(45^{\circ} \mathrm{C},\) are produced up to this point?

Certain gas-phase reactions on a heterogeneous catalyst are first order at low gas pressures and zero order at high pressures. Can you suggest a reason for this?

The first-order reaction \(A \longrightarrow\) products has a halflife, \(t_{1 / 2},\) of 46.2 min at \(25^{\circ} \mathrm{C}\) and \(2.6 \mathrm{min}\) at \(102^{\circ} \mathrm{C}.\) (a) Calculate the activation energy of this reaction. (b) At what temperature would the half-life be 10.0 min?

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