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If the plot of the reactant concentration versus time is linear, then the order of the reaction is (a) zero order; (b) first order; (c) second order; (d) third order.

Short Answer

Expert verified
The order of the reaction is zero.

Step by step solution

01

Understand the concept of order of reactions

The order of a reaction refers to the effect that the concentration of a reactant has on the rate of reaction. An nth order reaction means that the rate of reaction is proportional to the nth power of the concentration of that reactant. Here, we are specifically looking at a linear plot of reactant concentration versus time.
02

Define zero order reactions

Zero–order reactions are defined as reactions where the rate of reaction is independent of the concentration of the reactants. This means that the rate of reaction remains constant over time. So when we plot the concentration of a reactant against time, we get a linear decrease. Therefore, we can safely say that a reaction is of the zero order when the graph of concentration of reactants versus time is linear.
03

Answering the question

Based on the definitions and understandings of the order of reactions explained in the previous steps, it can be said conclusively that if the plot of the reactant concentration versus time is linear, then the order of the reaction is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Zero Order Reactions
Zero order reactions are a cornerstone of chemical kinetics, which stand apart because they progress at a constant rate regardless of the concentration of the reactants. In such reactions, the rate at which a reactant is consumed does not depend on its concentration; as a result, the concentration decreases linearly over time.

In practical terms, this means that even if you were to double or triple the amount of reactant, the reaction would not speed up. This constant rate is uniquely characteristic of zero order kinetics and holds true until one of the reactants is depleted. This atypical behavior occurs in certain conditions such as when a reactant is in large excess or when the reaction is facilitated by a surface or catalyst that is saturated with reactants.

Real-World Implications

Consider the implications for industrial processes or biological systems, where controlling the speed of reactions is crucial. In the manufacturing of a product, a zero order reaction would imply predictable production rates over time, a factor that could simplify planning and logistics.
Reaction Kinetics
At the heart of chemistry lies the study of reaction kinetics, which is concerned with the rates of chemical reactions and the mechanisms by which they occur. Factors such as concentration, temperature, pressure, and the presence of catalysts all influence how fast a reaction proceeds. By understanding the relationship between these variables, chemists can manipulate conditions to control reaction rates.

The order of the reaction plays a critical role in reaction kinetics. For instance, the order determines how changing the concentration of reactants will affect the rate. But it's not just about speed; kinetics also gives insight into the steps that make up the reaction mechanism—knowledge that is crucial for the development of new chemical processes and pharmaceuticals.

Practical Applications

The application of reaction kinetics is extensive, benefitting many industries by improving the efficiency of chemical processes. This fundamental concept also provides a framework for drug development, helping to predict the behavior of active compounds within the body.
Concentration Versus Time Graph
Concentration versus time graphs are visual tools used to represent how the concentration of a reactant changes as a reaction proceeds. The shape of these graphs varies depending on the order of the reaction. For instance, a zero order reaction yields a straight line that slopes downwards, indicating a constant rate of reaction. In contrast, graphs for first-order reactions curve, showing that the rate of reaction slows as the reactant concentration decreases over time.

These graphs are not just academic, they convey important kinetic information through their shape, slope, and concavity. They can, for example, suggest the presence of a rate-determining step or demonstrate the effects of a catalyst on reaction speed. By simply analyzing the slope of these curves, chemists can deduce the order of a reaction without the need for complex calculations.

Interpreting the Data

For students and chemists alike, interpreting these graphs is critical for understanding reaction dynamics. Such analysis forms the basis for controlling reactions in both research and industrial settings, making these graphs a simple yet powerful tool in the realm of reaction kinetics.

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Most popular questions from this chapter

The reaction \(A+B \longrightarrow\) products is first order in \(A\) first order in \(\mathrm{B},\) and second order overall. Consider that the starting concentrations of the reactants are \([\mathrm{A}]_{0}\) and [ \(\mathrm{B}]_{0},\) and that \(x\) represents the decrease in these concentrations at the time \(t .\) That is, \([\mathrm{A}]_{t}=[\mathrm{A}]_{0}-x\) and \([\mathrm{B}]_{t}=[\mathrm{B}]_{0}-x .\) Show that the integrated rate law for this reaction can be expressed as shown below. $$\ln \frac{[\mathrm{A}]_{0} \times[\mathrm{B}]_{t}}{[\mathrm{B}]_{0} \times[\mathrm{A}]_{t}}=\left([\mathrm{B}]_{0}-[\mathrm{A}]_{0}\right) \times k t$$

For the reaction \(\mathrm{A}+2 \mathrm{B} \longrightarrow \mathrm{C}+\mathrm{D},\) the rate law is rate of reaction \(=k[\mathrm{A}][\mathrm{B}]\) (a) Show that the following mechanism is consistent with the stoichiometry of the overall reaction and with the rate law. $$\begin{array}{l} \mathrm{A}+\mathrm{B} \longrightarrow \mathrm{I} \quad(\text { slow }) \\ \mathrm{I}+\mathrm{B} \longrightarrow \mathrm{C}+\mathrm{D} \quad(\text { fast }) \end{array}$$ (b) Show that the following mechanism is consistent with the stoichiometry of the overall reaction, but not with the rate law. $$\begin{array}{c} 2 \mathrm{B} \stackrel{k_{1}}{\mathrm{k}_{1}} \mathrm{B}_{2} \text { (fast) } \\\ \mathrm{A}+\mathrm{B}_{2} \stackrel{k_{2}}{\longrightarrow} \mathrm{C}+\mathrm{D} \text { (slow) } \end{array}$$

The decomposition of \(\mathrm{HI}(\mathrm{g})\) at \(700 \mathrm{K}\) is followed for \(400 \mathrm{s},\) yielding the following data: at \(t=0,[\mathrm{HI}]=\) \(1.00 \mathrm{M} ;\) at \(t=100 \mathrm{s},[\mathrm{HI}]=0.90 \mathrm{M} ;\) at \(t=200 \mathrm{s}, [\mathrm{HI}]=0.81 \mathrm{M} ; t=300 \mathrm{s},[\mathrm{HI}]=0.74 \mathrm{M} ;\) at \(t=400 \mathrm{s}, [\mathrm{HI}]=0.68 \mathrm{M} .\) What are the reaction order and the rate constant for the reaction: $$\mathrm{HI}(\mathrm{g}) \longrightarrow \frac{1}{2} \mathrm{H}_{2}(\mathrm{g})+\frac{1}{2} \mathrm{I}_{2}(\mathrm{g}) ?$$ Write the rate law for the reaction at 700 K.

The reaction \(A+B \longrightarrow C+D\) is second order in \(A\) and zero order in B. The value of \(k\) is \(0.0103 \mathrm{M}^{-1} \mathrm{min}^{-1}.\) What is the rate of this reaction when \([\mathrm{A}]=0.116 \mathrm{M}\) and \([\mathrm{B}]=3.83 \mathrm{M} ?\)

The following data are for the reaction \(2 \mathrm{A}+\mathrm{B} \longrightarrow\) products. Establish the order of this reaction with respect to A and to B. $$\begin{array}{cccc} \hline \text { Expt 1, }[\mathrm{B}]=1.00 \mathrm{M} & & {\text { Expt 2, }[\mathrm{B}]=0.50 \mathrm{M}} \\ \hline \begin{array}{cccc} \text { Time, } \\ \text { min } \end{array} & \begin{array}{c} \text { [A], M } \\ \end{array} & \text { Time, } \text { min } &\text { [A], M } \\ \hline 0 & 1.000 \times 10^{-3} & 0 & 1.000 \times 10^{-3} \\ 1 & 0.951 \times 10^{-3} & 1 & 0.975 \times 10^{-3} \\ 5 & 0.779 \times 10^{-3} & 5 & 0.883 \times 10^{-3} \\ 10 & 0.607 \times 10^{-3} & 10 & 0.779 \times 10^{-3} \\ 20 & 0.368 \times 10^{-3} & 20 & 0.607 \times 10^{-3} \\ \hline \end{array}$$

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