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For the reaction \(\mathrm{A}+\mathrm{B} \longrightarrow 2 \mathrm{C},\) which proceeds by a single-step bimolecular elementary process, (a) \(t_{1 / 2}=0.693 / k ;\) (b) rate of appearance of C= - rate of disappearance of \(\mathrm{A} ;\) (c) rate of reaction = \(k[\mathrm{A}][\mathrm{B}] ;\) (d) \(\ln [A]_{t}=-k t+\ln [A]_{0}.\)

Short Answer

Expert verified
Statements (b) and (c) are correct, while statements (a) and (d) are incorrect.

Step by step solution

01

Verifying Statement (a)

The half-life equation \(t_{1 / 2}=0.693 / k\) is applicable for first-order reactions. But in this case, the reaction is a bimolecular (second-order) process. So, statement (a) is incorrect.
02

Verifying Statement (b)

In any reaction where new products are formed, the rate of appearance of the product is indeed equivalent to the rate of disappearance of the reactants. So, statement (b) holds true in this context and is correct.
03

Verifying Statement (c)

The rate of reaction for a bimolecular process indeed follows the form \(rate = k[\mathrm{A}][\mathrm{B}]\), where [A] and [B] are the molar concentrations of reactants A and B, respectively, and k is the rate constant. So, statement (c) is correct.
04

Verifying Statement (d)

The equation \(\ln [A]_{t}=-k t+\ln [A]_{0}\) is valid for first-order reactions and it relates the concentration of reactant A at any time t to the initial concentration of A. In this case, as the reaction is a bimolecular process (second-order), this equation is not applicable. Hence, statement (d) is incorrect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Kinetics
Reaction kinetics is the branch of physical chemistry that studies the rates of chemical processes. It examines how various factors such as concentration, temperature, and catalysts affect the speed of a chemical reaction. Understanding kinetics helps predict how a reaction proceeds over time and the time it takes for reactants to transform into products.

In the context of a bimolecular elementary process, reaction kinetics focuses on how two molecules come together to react. Bimolecular reactions are one subset of elementary reactions, indicating that the reaction occurs in one step and involves the simultaneous collision of two reactant molecules.
Rate of Reaction
The rate of a reaction measures the speed at which reactants are converted into products over time. It is typically expressed in terms of concentration change per unit time, such as moles per liter per second. Factors like temperature, the presence of catalysts, and the concentrations of reactants can influence this rate.

For a bimolecular reaction such as \(\mathrm{A} + \mathrm{B} \longrightarrow 2\mathrm{C}\), the rate is proportional to the product of the concentrations of the reactants, \(k[\mathrm{A}][\mathrm{B}]\), where \(k\) is the rate constant. The rate of appearance of product \(\mathrm{C}\) is directly related to the rate of disappearance of reactants \(\mathrm{A}\) and \(\mathrm{B}\).
Half-life of Reaction
The half-life of a reaction, often represented by \(t_{1/2}\), is the time required for half the quantity of a reactant to be consumed or for the concentration of the reactant to fall to half its initial value. For first-order reactions, \(t_{1/2}\) is a constant that is independent of the initial concentration and can be calculated using the formula \(t_{1/2} = 0.693 / k\).

However, for second-order reactions, the half-life depends on the initial concentration of the reactants, and the formula for the first-order reactions does not apply. In a half-life context, this highlights the importance of knowing the reaction order when conducting kinetic analysis.
First-Order Reactions
First-order reactions are characterized by a rate that is directly proportional to the concentration of one reactant. The integrated rate law for a first-order reaction is given by \(\ln[A]_t = -kt + \ln[A]_0\), where \(\ln[A]_t\) is the natural logarithm of the concentration of reactant \(A\) at time \(t\), \(\ln[A]_0\) is the natural logarithm of the initial concentration of \(A\), and \(k\) is the first-order rate constant. In these reactions, the half-life is constant and does not depend on the initial concentration of reactants.
Second-Order Reactions
Second-order reactions are defined by a rate proportional to the square of the concentration of one reactant or to the product of the concentrations of two reactants. The rate expression for a second-order reaction with two reactants \(A\) and \(B\) would be \(rate = k[A][B]\).

Unlike first-order reactions, the half-life of a second-order reaction depends on the initial concentrations of the reactants, and therefore, it changes over time. The integrated rate law and half-life expressions for second-order reactions differ significantly from those of first-order reactions, reflecting the dependency on initial reactant concentrations.

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Most popular questions from this chapter

The reaction \(A+B \longrightarrow\) products is first order in \(A\) first order in \(\mathrm{B},\) and second order overall. Consider that the starting concentrations of the reactants are \([\mathrm{A}]_{0}\) and [ \(\mathrm{B}]_{0},\) and that \(x\) represents the decrease in these concentrations at the time \(t .\) That is, \([\mathrm{A}]_{t}=[\mathrm{A}]_{0}-x\) and \([\mathrm{B}]_{t}=[\mathrm{B}]_{0}-x .\) Show that the integrated rate law for this reaction can be expressed as shown below. $$\ln \frac{[\mathrm{A}]_{0} \times[\mathrm{B}]_{t}}{[\mathrm{B}]_{0} \times[\mathrm{A}]_{t}}=\left([\mathrm{B}]_{0}-[\mathrm{A}]_{0}\right) \times k t$$

In the reaction \(A \longrightarrow\) products, at \(t=0\), the \([\mathrm{A}]=0.1565 \mathrm{M} .\) After \(1.00 \mathrm{min},[\mathrm{A}]=0.1498 \mathrm{M},\) and after \(2.00 \mathrm{min},[\mathrm{A}]=0.1433 \mathrm{M}\) (a) Calculate the average rate of the reaction during the first minute and during the second minute. (b) Why are these two rates not equal?

The rate of a chemical reaction generally increases rapidly, even for small increases in temperature, because of a rapid increase in (a) collision frequency; (b) fraction of reactant molecules with very high kinetic energies; (c) activation energy; (d) average kinetic energy of the reactant molecules.

Derive a plausible mechanism for the following reaction in aqueous solution, \(\mathrm{Hg}_{2}^{2+}+\mathrm{Tl}^{3+} \longrightarrow 2 \mathrm{Hg}^{2+}+\mathrm{Tl}^{+}\) for which the observed rate law is: rate \(=k\left[\mathrm{Hg}_{2}^{2+1}\right]\) \(\left.[\mathrm{T}]^{3+}\right] /\left[\mathrm{Hg}^{2+}\right].\)

In the reaction \(A(g) \longrightarrow 2 B(g)+C(g),\) the total pressure increases while the partial pressure of \(\mathrm{A}(\mathrm{g})\) decreases. If the initial pressure of \(\mathrm{A}(\mathrm{g})\) in a vessel of constant volume is \(1.000 \times 10^{3} \mathrm{mmHg}\) (a) What will be the total pressure when the reaction has gone to completion? (b) What will be the total gas pressure when the partial pressure of \(\mathrm{A}(\mathrm{g})\) has fallen to \(8.00 \times 10^{2} \mathrm{mmHg} ?\)

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