Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Would you predict the surface tension of \(t\) -butyl alcohol, \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH},\) to be greater than or less than that of \(\mathrm{n}\) -butyl alcohol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) Explain.

Short Answer

Expert verified
Based on the analysis of intermolecular forces and molecular structures, the surface tension of n-butyl alcohol \(CH_{3}CH_{2}CH_{2}CH_{2}OH\) is expected to be greater than that of t-butyl alcohol \((CH_{3})_{3}COH\).

Step by step solution

01

Understanding t-butyl alcohol

t-butyl alcohol, \((CH_{3})_{3}COH\) has three methyl groups attached to a central carbon atom that is also attached to a hydroxyl group. The hydroxyl group (-OH) contributes to polarity, making it capable of forming hydrogen bonds.
02

Understanding n-butyl alcohol

n-butyl alcohol \(CH_{3}CH_{2}CH_{2}CH_{2}OH\) has a longer carbon chain. It also possesses a hydroxyl group at one end, making it capable of forming hydrogen bonds.
03

Comparing molecular structures

Comparing the two structures, n-butyl alcohol has a longer carbon chain compared to t-butyl alcohol. The longer carbon chain provides more opportunities for Van der Waals forces of attraction to occur, leading to stronger total intermolecular forces.
04

Relating molecular structure to surface tension

Surface tension is directly proportional to the magnitude of intermolecular forces. A substance with stronger intermolecular forces will have a higher surface tension. Given the analysis in the previous steps, n-butyl alcohol is expected to exhibit stronger intermolecular forces compared to t-butyl alcohol, due to its longer carbon chain and higher amount of Van der Waals forces.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-butyl alcohol
t-butyl alcohol, also known scientifically as 2-methylpropan-2-ol, is an organic compound with the formula \(CH_{3})_{3}COH\. This molecule features a central carbon atom bonded to a hydroxyl group (-OH) and three methyl groups (\CH_3\). The structure of t-butyl alcohol gives it distinct characteristics. The presence of the hydroxyl group contributes to its polarity, enhancing its ability to form hydrogen bonds.
These hydrogen bonds are crucial as they determine many of the physical properties, including solubility and boiling point.
However, the three bulky methyl groups create a shape that is more spherical compared to straight-chain alcohols like n-butyl alcohol. This structural attribute influences how the molecules stack and interact with each other. This spherical form leads to lower surface tension, as the bulky shape can hinder effective intermolecular interactions beyond the hydrogen bonds. In summary, while t-butyl alcohol does have some ability to bond through hydrogen connections, its structural shape limits the potential strength and multiplicity of its intermolecular forces.
n-butyl alcohol
n-butyl alcohol, or butan-1-ol, has a linear chain structure given by the formula \(CH_{3}CH_{2}CH_{2}CH_{2}OH\). The hydrocarbon chain is straight, featuring four carbon atoms in a row.
At the end of this linear molecule is the hydroxyl group, like in t-butyl alcohol, which allows for hydrogen bonding.
However, a significant feature of n-butyl alcohol lies in its elongated chain. This chain enables additional interactions beyond hydrogen bonding, known as Van der Waals forces.
  • More extensive contact surface area: The longer chain permits greater surface area interaction.
  • Higher opportunity for Van der Waals forces: These forces arise due to temporary dipoles and are generally stronger with longer chains like that of n-butyl alcohol.
Because of these enhanced interactions, n-butyl alcohol typically exhibits stronger overall intermolecular forces than its more spherical counterpart, t-butyl alcohol. This increased force boosts the surface tension, lending to greater ability for the molecules to "stick" together at the surface.
intermolecular forces
Intermolecular forces are the invisible forces that influence how molecules interact with each other. They play a vital role in determining the physical properties of substances, particularly surface tension. Three main types of intermolecular forces include:
  • Hydrogen bonding: Occurs when a hydrogen atom is attracted to an electronegative atom, such as oxygen. Both t-butyl and n-butyl alcohols engage in hydrogen bonding due to their -OH groups.

  • Van der Waals forces: These are weaker forces that occur due to momentary changes in electron density. They include dispersion forces, which n-butyl alcohol experiences more due to its longer chain.

  • Dipole-dipole interactions: Stronger than Van der Waals but usually weaker than hydrogen bonds, they occur between polar molecules, influenced by their shape and dipole moment.
Intermolecular forces collectively influence properties like boiling point and viscosity. In the case of surface tension, substances with stronger intermolecular forces tend to exhibit higher surface tension.
When comparing t-butyl and n-butyl alcohol, n-butyl's ability to form additional Van der Waals interactions due to its extended structure contributes to its higher surface tension compared to t-butyl alcohol.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The normal boiling point of acetone, an important laboratory and industrial solvent, is \(56.2^{\circ} \mathrm{C}\) and its \(\Delta H_{\text {vap }}\) is \(25.5 \mathrm{kJmol}^{-1} .\) At what temperature does acetone have a vapor pressure of \(375 \mathrm{mmHg} ?\)

Show that the formation of \(\mathrm{NaCl}_{2}(\mathrm{s})\) is very unfavorable; that is, \(\Delta \mathrm{H}_{\mathrm{f}}^{\circ}\left[\mathrm{NaCl}_{2}(\mathrm{s})\right]\) is a large positive quantity. To do this, use data from Section \(12-7\) and assume that the lattice energy for \(\mathrm{NaCl}_{2}\) would be about the same as that of \(\mathrm{MgCl}_{2},-2.5 \times 10^{3} \mathrm{kJ} \mathrm{mol}^{-1}\)

All solids contain defects or imperfections of structure or composition. Defects are important because they influence properties, such as mechanical strength. Two common types of defects are a missing ion in an otherwise perfect lattice, and the slipping of an ion from its normal site to a hole in the lattice. The holes discussed in this chapter are often called interstitial sites, since the holes are in fact interstices in the array of spheres. The two types of defects described here are called point de kcts because they occur within specific sites. In the 1930 s, two solidstate physicists, W. Schottky and J. Fraenkel, studied the two types of point defects: A Schottky defect corresponds to a missing ion in a lattice, while a Fraenkel defect corresponds to an ion that is displaced into an interstitial site. (a) An example of a Schottky defect is the absence of a \(\mathrm{Na}^{+}\) ion in the NaCl structure. The absence of a \(\mathrm{Na}^{+}\) ion means that a \(\mathrm{Cl}^{-}\) ion must also be absent to preserve electrical neutrality. If one NaCl unit is missing per unit cell, does the overall stoichiometry change, and what is the change in density? (b) An example of a Fraenkel defect is the movement of \(a \mathrm{Ag}^{+}\) ion to a tetrahedral interstitial site from its normal octahedral site in \(\mathrm{AgCl}\), which has a structure like \(\mathrm{NaCl}\). Does the overall stoichiometry of the compound change, and do you expect the density to change? (c) Titanium monoxide (TiO) has a sodium chloridelike structure. X-ray diffraction data show that the edge length of the unit cell is \(418 \mathrm{pm}\). The density of the crystal is \(4.92 \mathrm{g} / \mathrm{cm}^{3}\) Do the data indicate the presence of vacancies? If so, what type of vacancies?

Estimate the boiling point of water in Leadville, Colorado, elevation 3170 m. To do this, use the barometric formula relating pressure and altitude: \(P=P_{0} \times 10^{-\mathrm{Mgh} / 2.303 \mathrm{RT}} \quad(\text { where } P=\text { pressure } \mathrm{in}\) atm; \(P_{0}=1 \mathrm{atm} ; g=\) acceleration due to gravity; molar mass of air, \(M=0.02896 \mathrm{kg} \mathrm{mol}^{-1} ; \quad R=\) \(8.3145 \mathrm{Jmol}^{-1} \mathrm{K}^{-1} ;\) and \(T\) is the Kelvin temperature). Assume the air temperature is \(10.0^{\circ} \mathrm{C}\) and that \(\Delta H_{\text {vap }}=41 \mathrm{kJ} \mathrm{mol}^{-1} \mathrm{H}_{2} \mathrm{O}\)

The following data are given for \(\mathrm{CCl}_{4}\). Normal melting point, \(-23^{\circ} \mathrm{C} ;\) normal boiling point, \(77^{\circ} \mathrm{C} ;\) density of liquid \(1.59 \mathrm{g} / \mathrm{mL} ; \Delta H_{\text {fus }}=3.28 \mathrm{kJ} \mathrm{mol}^{-1} ;\) vapor pressure at \(25^{\circ} \mathrm{C}, 110\) Torr. (a) What phases-solid, liquid, and/or gas-are present if \(3.50 \mathrm{g} \mathrm{CCl}_{4}\) is placed in a closed \(8.21 \mathrm{L}\) container at \(25^{\circ} \mathrm{C} ?\) (b) How much heat is required to vaporize 2.00 L of \(\mathrm{CCl}_{4}(\mathrm{l})\) at its normal boiling point?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free