Chapter 5: Problem 74
Magnesium metal reacts with hydrochloric acid to produce hydrogen gas, \(\mathrm{H}_{2}\). $$ \mathrm{Mg}(s)+2 \mathrm{HCl}(a q) \longrightarrow \mathrm{MgCl}_{2}(a q)+\mathrm{H}_{2}(g) $$ Calculate the volume (in liters) of hydrogen produced at \(33^{\circ} \mathrm{C}\) and \(665 \mathrm{mmHg}\) from \(0.0840 \mathrm{~mol} \mathrm{Mg}\) and excess \(\mathrm{HCl}\).
Short Answer
Step by step solution
Write the Balanced Chemical Equation
Determine Moles of Hydrogen Gas
Convert Temperature to Kelvin
Convert Pressure to Atmospheres
Use the Ideal Gas Law to Find Volume
Calculate the Volume
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Reaction
This is an example of a single-replacement reaction. The magnesium replaces the hydrogen ions in the hydrochloric acid to form the magnesium chloride salt and hydrogen gas.
Understanding chemical reactions is crucial as they are fundamental processes found in nature and industrial applications. Without such reactions, the transformation of materials and energy changes necessary for life would not be possible.
- Reactants: The starting substances, Mg and HCl.
- Products: The new substances created, MgCl extsubscript{2} and H extsubscript{2}.
- Balanced Equation: It's crucial to ensure that the number of atoms for each element is the same on both sides of the equation, maintaining mass conservation.
Stoichiometry
In the given exercise, stoichiometry helps us understand the relationship between magnesium and hydrogen gas. The balanced equation shows us that one mole of magnesium reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas.
This stoichiometric relationship allows us to determine the amount of any other substance in the reaction once one quantity is known.
- The ratio from the balanced equation: 1 Mg : 2 HCl : 1 H extsubscript{2}.
- If you have 0.0840 moles of Mg, it will produce 0.0840 moles of H extsubscript{2}, assuming HCl is in excess.
Gas Laws
The most relevant gas law here is the Ideal Gas Law, stated as \( PV = nRT \). This formula allows us to calculate the volume of a gas when its pressure, number of moles, and temperature are known.
For the exercise, we must convert the given conditions to the appropriate units to use the Ideal Gas Law effectively.
- Pressure needs to be in atmospheres (atm).
- Temperature must be in Kelvin (K).
- The gas constant \( R \) is 0.0821 L atm/mol K.
Moles of Gas
The Ideal Gas Law, \( PV = nRT \), demonstrates how the moles of gas \( n \) directly relate to changes in volume, pressure, or temperature.
In the exercise, knowing the moles of magnesium (0.0840 moles) allows us to determine the moles of hydrogen gas produced, which are also 0.0840 moles, as per the balanced chemical equation.
This helps in using the Ideal Gas Law to calculate the volume of gas produced. Understanding moles and their conversions is vital in chemistry because they act as a bridge between the atomic scale and the real-world scale in chemical calculations.