Chapter 4: Problem 65
Balance the following oxidation-reduction reactio by the half-reaction method. (a) $$ \mathrm{CuCl}_{2}(a q)+\mathrm{Al}(s) \longrightarrow \mathrm{AlCl}_{3}(a q)+\mathrm{Cu}(s) $$ (b) $$ \mathrm{Cr}^{3+}(a q)+\mathrm{Zn}(s) \longrightarrow \mathrm{Cr}(s)+\mathrm{Zn}^{2+}(a q) $$
Short Answer
Expert verified
(a) \(2 \text{Al} + 3 \text{CuCl}_{2} \rightarrow 2 \text{AlCl}_{3} + 3 \text{Cu}\); (b) \(3 \text{Zn} + 2 \text{Cr}^{3+} \rightarrow 3 \text{Zn}^{2+} + 2 \text{Cr}\).
Step by step solution
01
Identify Oxidation and Reduction Half-Reactions in (a)
In the given reaction \( ext{CuCl}_{2} + ext{Al} \rightarrow ext{AlCl}_{3} + ext{Cu}\), determine which species are oxidized and reduced:- **Oxidation half-reaction**: \( ext{Al} \rightarrow ext{Al}^{3+} + 3e^{-}\) - Aluminum transforms from a pure element to AlCl3, gaining a positive charge.- **Reduction half-reaction**: \( ext{Cu}^{2+} + 2e^{-} \rightarrow ext{Cu}\) - Copper in \( ext{CuCl}_{2}\) is reduced, losing its positive charge to become elemental Cu.
02
Balance Each Half-Reaction in (a)
Adjust each half-reaction so that the number of electrons lost in oxidation equals the electrons gained in reduction.- **Oxidation half-reaction**: \[ ext{2 Al} \rightarrow 2 ext{Al}^{3+} + 6 e^{-}\]- **Reduction half-reaction**: \[3 ext{Cu}^{2+} + 6 e^{-} \rightarrow 3 ext{Cu}\]
03
Combine Balanced Half-Reactions for (a)
Add the balanced half-reactions together, ensuring electrons are canceled:\[2 ext{Al} + 3 ext{Cu}^{2+} \rightarrow 2 ext{Al}^{3+} + 3 ext{Cu}\]Thus, the balanced reaction is:\[2 ext{Al} + 3 ext{CuCl}_{2} \rightarrow 2 ext{AlCl}_{3} + 3 ext{Cu}\]
04
Identify Oxidation and Reduction Half-Reactions in (b)
For the reaction \( ext{Cr}^{3+} + ext{Zn} \rightarrow ext{Cr} + ext{Zn}^{2+}\), determine which species are oxidized and reduced:- **Oxidation half-reaction**: \( ext{Zn} \rightarrow ext{Zn}^{2+} + 2e^{-}\) - Zinc goes from elemental to a Zn^2+ ion.- **Reduction half-reaction**: \( ext{Cr}^{3+} + 3e^{-} \rightarrow ext{Cr}\) - Chromium ions gain electrons to become elemental Cr.
05
Balance Each Half-Reaction in (b)
Adjust the half-reactions to have equal numbers of electrons involved:- **Oxidation half-reaction**: \[3 ext{Zn} \rightarrow 3 ext{Zn}^{2+} + 6e^{-}\]- **Reduction half-reaction**: \[2 ext{Cr}^{3+} + 6e^{-} \rightarrow 2 ext{Cr}\]
06
Combine Balanced Half-Reactions for (b)
Add the balanced oxidation and reduction equations:\[3 ext{Zn} + 2 ext{Cr}^{3+} \rightarrow 3 ext{Zn}^{2+} + 2 ext{Cr}\]This gives the balanced overall reaction.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Reaction Method
The half-reaction method is a systematic technique used to balance oxidation-reduction (redox) reactions. It involves splitting the overall reaction into two distinct parts: oxidation and reduction half-reactions. Each part is handled separately and then combined to achieve a balanced equation.
- Oxidation Half-Reaction: Represents loss of electrons.
- Reduction Half-Reaction: Represents gain of electrons.
Balancing Chemical Equations
Balancing chemical equations is essential for accurately representing chemical reactions. In the context of redox reactions, using the half-reaction method ensures that you account for both the mass and charge balance. The principle involves adjusting coefficients so that the number of atoms for each element in the reactants equals those in the products.
For half-reactions:
For half-reactions:
- Balance atoms other than O and H.
- Balance O atoms by adding water molecules.
- Balance H atoms using hydrogen ions.
- Balance charge by adding electrons.
Redox Reactions
Redox reactions are chemical processes involving the transfer of electrons between two substances. The term "redox" is derived from two concepts: reduction and oxidation. These reactions are central to many biological and industrial processes, such as energy production, corrosion, and metabolism. In a redox reaction, one substance undergoes oxidation (loses electrons) while the other undergoes reduction (gains electrons).
Identifying redox reactions involves:
Identifying redox reactions involves:
- Determining changes in oxidation states of elements.
- Recognizing electron transfer between reactants.
- Using the half-reaction method to simplify balancing.
Oxidation Reactions
Oxidation reactions are a type of redox reaction where a substance loses electrons, increasing its oxidation state. The substance undergoing oxidation donates these electrons to the reduction half-reaction. In the oxidation process:
- The oxidized species turns into a positively charged ion or a less negative state.
- Commonly involves metals like zinc and aluminum changing from a neutral atom to a charged ion.
Reduction Reactions
Reduction reactions occur when a substance gains electrons and decreases its oxidation state. This is the second half of a redox reaction, balancing the process initiated by oxidation. The species that gains electrons is said to be "reduced," as its charge becomes more negative or less positive.
Some notable points about reduction reactions include:
Some notable points about reduction reactions include:
- Reduction often occurs with nonmetals, such as copper ions converting to copper metal (\( \text{Cu}^{2+} + 2e^{-} \rightarrow \text{Cu} \)).
- It is essential for processes like battery operations, where reduction occurs at the cathode.
- Balancing reduction reactions involves ensuring electron uptake matches the electrons released during oxidation.