Chapter 5: Problem 18
A cylinder of gas contains \(11.6 \mathrm{~kg}\) of butane, if a normal family needs \(2.0 \times 10^{4} \mathrm{~kJ}\) of energy per day for cooking, how long will the cylinder last \(\left(\Delta H_{\text {combustian of bucane }}=-2600 \mathrm{~kJ} / \mathrm{mol}\right)\). (a) 52 days (b) 26 days (c) 116 days (d) none
Short Answer
Step by step solution
Determine the Molar Mass of Butane
Calculate the Moles of Butane
Find the Total Energy from Combustion
Calculate the Days the Cylinder Lasts
Conclusion and Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass
Butane consists of four carbon atoms and ten hydrogen atoms. We know from the periodic table that the atomic mass of carbon is approximately 12 g/mol, while that of hydrogen is about 1 g/mol. Using this information, we compute the molar mass of butane as follows:
- Carbon: \( 4 \times 12 \text{ g/mol} = 48 \text{ g/mol} \)
- Hydrogen: \( 10 \times 1 \text{ g/mol} = 10 \text{ g/mol} \)
Butane Combustion
\[ 2 \text{C}_4\text{H}_{10} + 13 \text{O}_2 \rightarrow 8 \text{CO}_2 + 10 \text{H}_2\text{O} \]
This reaction releases a significant amount of energy in the form of heat. The enthalpy change for the combustion of butane is given as \(-2600 \text{ kJ/mol}\). The negative sign indicates that the process is exothermic, meaning energy is released as heat.
Understanding this energy release is crucial in energy calculations, especially when considering how much energy can be obtained from a given mass of butane. Efficient use of this energy is important for tasks such as cooking, heating, and even powering engines.
Energy Calculation
For example, with 200 moles of butane available, and each mole releasing \(-2600 \text{ kJ}\), the total energy released is:
- \( 200 \text{ mol} \times -2600 \text{ kJ/mol} = -520,000 \text{ kJ} \)
Gas Cylinders
When we talk about a cylinder containing 11.6 kg of butane, we're referring to the total mass of butane stored. To estimate how long such a cylinder can last for a typical family, we must assess its energy output potential. This involves converting the mass to moles, calculating the energy each mole can produce, and then determining how this energy matches the family's daily energy requirements.
Efficient cylinder usage ensures families can optimize their budget and resource management, making these calculations practical and essential.
Stoichiometry
In our butane combustion example, stoichiometry allows us to balance the equation and ensure all elements are accounted for on both reactant and product sides:
\[ 2 \text{C}_4\text{H}_{10} + 13 \text{O}_2 \rightarrow 8 \text{CO}_2 + 10 \text{H}_2\text{O} \]
This balanced equation tells us that 2 moles of butane require 13 moles of oxygen to produce 8 moles of carbon dioxide and 10 moles of water.
Stoichiometry is not only about balancing equations but also helps in calculating how long a gas cylinder will last, by understanding how much energy results from these reactions. It's a key part of optimizing the use of chemical substances in everyday contexts.