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A small kidney stone (Chemistry in Action on p. 176) might contain \(0.50 \mathrm{~g}\) of uric acid \(\left(\mathrm{C}_{5} \mathrm{H}_{4} \mathrm{~N}_{4} \mathrm{O}_{3}\right)\). How many micromoles of uric acid are contained in this stone?

Short Answer

Expert verified
The stone contains approximately 2975 micromoles of uric acid.

Step by step solution

01

Calculate Molar Mass of Uric Acid

First, we need to determine the molar mass of uric acid by adding up the atomic masses based on its molecular formula, \(\mathrm{C}_{5} \mathrm{H}_{4} \mathrm{N}_{4}\mathrm{O}_{3}\). Using the periodic table: Carbon (C) has an atomic mass of 12.01 g/mol, Hydrogen (H) is 1.01 g/mol, Nitrogen (N) is 14.01 g/mol, and Oxygen (O) is 16.00 g/mol. The molar mass calculation is as follows: \[ 5(12.01) + 4(1.01) + 4(14.01) + 3(16.00) = 168.11 \text{ g/mol} \]
02

Convert Grams to Moles

Next, we convert the mass of uric acid from grams to moles. Given that the stone contains 0.50 g of uric acid, we use the molar mass calculated in Step 1: \[ \text{Moles of uric acid} = \frac{0.50 \text{ g}}{168.11 \text{ g/mol}} \approx 0.002975 \text{ moles} \]
03

Convert Moles to Micromoles

Finally, we convert the number of moles to micromoles. There are 1,000,000 micromoles in a mole, so: \[ \text{Micromoles of uric acid} = 0.002975 \text{ moles} \times 1,000,000 \text{ µmol/mole} \approx 2975 \text{ µmol} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
The molar mass of a compound is a critical concept in chemistry, allowing us to connect the mass of a substance to the number of particles or moles present. To calculate the molar mass of uric acid, we need to sum up the atomic masses of all the elements in its molecular formula, which is C\(_5\)H\(_4\)N\(_4\)O\(_3\).

Here's how it's done:
  • Carbon (C) has an atomic mass of 12.01 g/mol. Multiply this by the 5 atoms of carbon: 5 x 12.01 = 60.05 g/mol.
  • Hydrogen (H) has an atomic mass of 1.01 g/mol. Multiply this by the 4 atoms of hydrogen: 4 x 1.01 = 4.04 g/mol.
  • Nitrogen (N) has an atomic mass of 14.01 g/mol. Multiply this by the 4 atoms of nitrogen: 4 x 14.01 = 56.04 g/mol.
  • Oxygen (O) has an atomic mass of 16.00 g/mol. Multiply this by the 3 atoms of oxygen: 3 x 16.00 = 48.00 g/mol.
Add all these values together to find the molar mass of uric acid:
\[ 60.05 + 4.04 + 56.04 + 48.00 = 168.11 \text{ g/mol} \]
The molar mass is a link between the molecular scale and the scale of everyday measurements in grams.
Converting Grams to Moles
Once we know the molar mass, converting grams of a substance to moles becomes straightforward and crucial for stoichiometry. This step allows us to bridge between the mass you have and the amount, in moles, of a substance.

For the 0.50 g of uric acid in the kidney stone:
  • Divide the mass of the substance by its molar mass to obtain the number of moles.
  • The formula is: \( \text{moles} = \frac{\text{grams}}{\text{molar mass}} \)
  • Substituting in the values: \( \text{moles of uric acid} = \frac{0.50 \text{ g}}{168.11 \text{ g/mol}} \approx 0.002975 \text{ moles} \)
This calculation allows us to understand precisely how much of the uric acid, in terms of quantity of molecules, is present in the stone.
Converting Moles to Micromoles
After determining the number of moles, the next common conversion is to micromoles, particularly useful in fields requiring precise measurements, like biochemistry.

Micromoles provide a finer scale, beneficial when dealing with small quantities:
  • There are 1,000,000 micromoles in a single mole. This conversion factor helps scale your moles to a more workable number.
  • Simply multiply the number of moles by 1,000,000 to convert to micromoles.
  • In this case: \( 0.002975 \text{ moles} \times 1,000,000 \text{ µmol/mole} = 2975 \text{ µmol} \)
This conversion illustrates how even a small mass can correspond to a significant number of molecules, providing deeper insights for analysis and practical applications.

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Most popular questions from this chapter

The reaction of epoxyethane with water to give ethane-1,2-diol (automobile antifreeze) occurs in \(96.0 \%\) actual yield. How many grams of ethane-1,2-diol are formed by reaction of \(35.0 \mathrm{~g}\) of epoxyethane? (For epoxyethane, molecular mass \(=44.0\) amu; for ethane- 1,2 -diol, molecular mass \(=62.0\) amu. )

At elevated temperatures in an automobile engine, \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\) can react to yield NO, an important cause of air pollution. (a) Write a balanced equation for the reaction. (b) How many moles of \(\mathrm{N}_{2}\) are needed to react with \(7.50 \mathrm{~mol}\) of \(\mathrm{O}_{2} ?\) (c) How many moles of \(\mathrm{NO}\) can be formed when \(3.81 \mathrm{~mol}\) of \(\mathrm{N}_{2}\) reacts? (d) How many moles of \(\mathrm{O}_{2}\) must react to produce \(0.250 \mathrm{~mol}\) of \(\mathrm{NO} ?\)

Sodium hypochlorite, the primary component in commercial bleach, is prepared by bubbling chlorine gas through solutions of sodium hydroxide. $$\mathrm{NaOH}(a q)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{NaOCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$$ How many moles of sodium hypochlorite can be prepared from \(32.5 \mathrm{~g}\) of \(\mathrm{NaOH}\) ?

The principal component of many kidney stones is calcium oxalate, \(\mathrm{CaC}_{2} \mathrm{O}_{4}\). A kidney stone recovered from a typical patient contains \(8.5 \times 10^{20}\) formula units of calcium oxalate. How many moles of \(\mathrm{CaC}_{2} \mathrm{O}_{4}\) are present in this kidney stone? What is the mass of the kidney stone in grams?

The eruption of Mount St. Helens volcano in 1980 injected \(4 \times 10^{8} \mathrm{~kg}\) of \(\mathrm{SO}_{2}\) into the atmosphere. If all this \(\mathrm{SO}_{2}\) was converted to sulfuric acid, how many moles of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) would be produced? How many kilograms?

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