Chapter 4: Problem 11
Draw a Lewis structure for nitric acid, \(\mathrm{HNO}_{3}\). The nitrogen atom is in the center, and the hydrogen atom is bonded to an oxygen atom.
Short Answer
Expert verified
Nitrogen is central with double bond to one oxygen, and single bonds to two others (one with hydrogen).
Step by step solution
01
Count the Valence Electrons
Determine the total number of valence electrons in nitric acid by adding the valence electrons of each atom. Nitrogen has 5 valence electrons, each oxygen has 6, and hydrogen has 1. Thus, \(1 \times 1 + 1 \times 5 + 3 \times 6 = 24\) total valence electrons.
02
Arrange the Atoms
Position the nitrogen atom in the center. Connect the nitrogen atom to the three oxygen atoms. Attach the hydrogen atom to one of the oxygen atoms, as specified in the problem description.
03
Draw Single Bonds
Draw single bonds between nitrogen and each oxygen, and a single bond between one oxygen and hydrogen. This initial setup uses 4 bonds, consuming \(4 \times 2 = 8\) valence electrons.
04
Complete the Octet for Oxygen Atoms
Use remaining electrons to complete the octet of each oxygen atom. After forming single bonds, 16 electrons are left. Assign electrons to achieve octets for each oxygen keeping track of the total electron count.
05
Form Double Bond
To optimize electron distribution, form a double bond between nitrogen and one of the non-hydrogen-bearing oxygens. This will appropriately utilize the remaining electrons and maintain octets for the involved atoms.
06
Verify the Octet Rule
Check that each atom satisfies the octet rule (except hydrogen, which only needs 2 electrons). Nitrogen and each oxygen should have 8 electrons around them, completing the octet and sustaining charge balance.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Valence Electrons
Valence electrons are the outermost electrons of an atom and are crucial for chemical bonding. They are responsible for forming bonds between atoms. In the case of nitric acid (\(\mathrm{HNO}_3\)), we first need to calculate the total number of valence electrons.
- Nitrogen has 5 valence electrons.
- Each oxygen atom contributes 6 valence electrons.
- Hydrogen provides 1 valence electron.
Octet Rule
The octet rule is a guideline in chemistry that states atoms tend to bond in such a way that they each have eight electrons in their valence shell. This creates a stable electronic arrangement similar to noble gases.
For the nitric acid molecule, achieving the octet rule ensures stability for the nitrogen and oxygen atoms while hydrogen only requires 2 electrons.
For the nitric acid molecule, achieving the octet rule ensures stability for the nitrogen and oxygen atoms while hydrogen only requires 2 electrons.
- Initial single bonds are formed to hold the structure together.
- The remaining electrons are distributed to satisfy each atom's octet requirement.
Nitric Acid
Nitric acid, \(\mathrm{HNO}_3\), is a strong acid widely used in industries such as fertilizers and explosives. Understanding its structure helps explain its reactivity and properties.
In its Lewis structure, the nitrogen atom is the central atom. It is connected to three oxygen atoms, and one of these oxygens is bonded to a hydrogen atom.
In its Lewis structure, the nitrogen atom is the central atom. It is connected to three oxygen atoms, and one of these oxygens is bonded to a hydrogen atom.
- The arrangement reflects the molecule's tendency to form stable bonds due to the octet rule.
- The hydrogen bond to one oxygen influences the molecule's reactivity, particularly in releasing hydrogen ions.
Double Bond Formation
Double bonds are formed when two pairs of electrons are shared between two atoms. They play a crucial role when fulfilling the octet rule with single bonds is insufficient.
In the nitric acid molecule, after assigning single bonds, we use a double bond to help satisfy the octet rule.
In the nitric acid molecule, after assigning single bonds, we use a double bond to help satisfy the octet rule.
- A double bond between nitrogen and one of the oxygens helps distribute the total of 24 valence electrons effectively.
- This electron arrangement ensures that each atom has the necessary number of electrons, maintaining stability.