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It has been estimated that there is \(4 \times 10^{-4} \mathrm{mg}\) of gold per liter of seawater, At a price of \(\$ 19.40 / \mathrm{g}\), what would be the value of the gold in \(1 \mathrm{~km}^{3}\left(1 \times 10^{15} \mathrm{~cm}^{3}\right)\) of the ocean?

Short Answer

Expert verified
The value of the gold in 1 km³ of the ocean is \(7.76 \times 10^6\) dollars.

Step by step solution

01

- Determine gold concentration in mg in a cubic kilometer

Given the concentration of gold is \(4 \times 10^{-4}\) mg per liter. First, convert the volume of the sea water from cubic kilometers to liters. Since \(1 \text{ km}^3 = 1 \times 10^{15} \text{ cm}^3\) and \(1 \text{ cm}^3 = 1 \text{ ml}\), \(1 \text{ km}^3 = 1 \times 10^{15} \text{ ml}\). Because \(1000 \text{ ml} = 1\) liter, \(1 \text{ km}^3 = 1 \times 10^{12}\) liters.
02

- Calculate the total gold in kg

To find the total mass of gold, multiply the volume by the concentration:\(1 \times 10^{12}\) liters \(\times 4 \times 10^{-4}\) mg/liter = \(4 \times 10^{8}\) mg. Since \(1,000,000\) mg = 1 kg, \(4 \times 10^{8}\) mg = \(4 \times 10^2\) kg.
03

- Convert gold mass to grams

Knowing that each kilogram has \(1,000\) grams, \(4 \times 10^2\) kg = \(4 \times 10^5\) grams.
04

- Calculate the value of the gold

Finally, at a price of \(19.40\) per gram, multiply the total grams by the price to find the value: \(4 \times 10^5\) \(\times 19.40 = 7.76 \times 10^6\) dollars.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gold concentration calculation
To calculate the gold concentration in a given volume of seawater, you need to know the concentration in smaller units first. In our example, the given concentration is 4 x 10^-4 mg of gold per liter. This means for every liter (1 liter = 1000 ml = 1000 cm³) of seawater, you have 0.0004 mg of gold. Knowing these smaller units helps us calculate larger volumes accurately.
Unit conversion
When dealing with large volumes like a cubic kilometer (km³), it's important to convert units step-by-step. In the problem, 1 km³ is equivalent to 1 x 10^15 cm³. Since 1 cm³ equals 1 ml and 1000 ml equals 1 liter, we convert 1 km³ to liters: 1 x 10^15 cm³ = 1 x 10^15 ml = 1 x 10^12 liters. Accurate unit conversion ensures that you are working with comparable quantities.
Mass-to-value conversion
After determining the total gold mass, it's essential to convert this mass into a financial value. First, calculate the total gold in mg and convert it to kg, then to grams, and finally to dollars. In this problem, 4 x 10^8 mg is converted to 400 kg (since 1,000,000 mg = 1 kg) and then to 400,000 grams (since 1 kg = 1000 grams). The financial value is found by multiplying the grams by the price per gram: 400,000 grams x \(19.40 = \)7.76 million.
Steps in problem solving
Breaking down a complex problem into manageable steps is key for accurate results. Here are the main steps:
1. **Identify given quantities and required conversions:** For our example, we start with the gold concentration and needed volume conversions.
2. **Convert volumes and units accurately:** Convert the cubic kilometer to liters, ensuring all units match.
3. **Calculate the total mass:** Multiply the volume by concentration to find the total mass of gold in mg, then convert to kg and grams.
4. **Determine final value:** Finally, convert the total gold mass into monetary value using the given price per gram. By following these steps, you simplify complex calculations and reduce errors.

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Most popular questions from this chapter

Write the formula for each compound (the composition is given after each name): (a) zinc oxide 1 atom \(\mathrm{Zn}, 1\) atom \(\mathrm{O}\) (b) potassium chlorate 1 atom \(\mathrm{K}, 1\) atom \(\mathrm{Cl}, 3\) atoms \(\mathrm{O}\) (c) sodium hydroxide 1 atom \(\mathrm{Na}, 1\) atom \(\mathrm{O}, 1\) atom \(\mathrm{H}\) (d) ethyl alcohol 2 atoms C, 6 atoms \(\mathrm{H}, 1\) atom \(\mathrm{O}\)

Many foods contain interesting compounds that give them their flavors and smells. Some of these compounds are listed below with the chemical composition given after each name. Write the formulas for these compounds. (a) Allicin gives garlic its flavor (6 carbons, 10 hydrogens, 1 oxygen, and 2 sulfurs). (b) Capsaicin gives peppers their heat (18 carbons, 27 hydrogens, 1 nitrogen, and 3 oxygens). (c) Limonene gives oranges their fragrance (10 carbons and 16 hydrogens).

How many total atoms are represented in each formula? (a) \(\mathrm{Co}\left(\mathrm{ClO}_{3}\right)_{2}\) (b) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{3}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\) (d) \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\)

How many total atoms are there in one molecule of \(\mathrm{C}_{145} \mathrm{H}_{293} \mathrm{O}_{168}\) ?

How many total atoms are present in each of the following compounds? (a) \(\mathrm{CO}\) (b) \(\mathrm{BF}_{3}\) (c) \(\mathrm{HNO}_{3}\) (d) \(\mathrm{KMnO}_{4}\) (e) \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) (f) \(\mathrm{Fe}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)

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