Chapter 17: Problem 62
Why can oxidation nerer occur without reduction?
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 17: Problem 62
Why can oxidation nerer occur without reduction?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeWhat mass of \(\mathrm{KMnO}_{4}\) is needed to react with \(100, \mathrm{~mL}, \mathrm{H}_{2} \mathrm{O}_{2}\) solution? ( \(a=1,031 \mathrm{~g} / \mathrm{mL}, 9.0^{3} \% \mathrm{H}_{2} \mathrm{O}_{2}\) by mass) $$ \begin{aligned} \mathrm{H}_{2} \mathrm{O}_{2}+& \mathrm{KMnO}_{4}+\mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow \\ & \mathrm{O}_{2}+\mathrm{MnSO}_{4}+\mathrm{K}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{O} \quad \text { (acídic solution) } \end{aligned} $$
(Note: \(\mathrm{H}=+1\) even though it comes second in the formula: \(\mathrm{N}\) is a nommetal.) (a) \(\mathrm{N}=-3\), (b) \(\mathrm{Cr}=+6\),
5\. Manganese metal reacts with HCl to give hydrogen gas and the \(\mathrm{Mn}^{2+}\) ion in solution. Write a balanced equation for the reaction.
Balance each of the following equations using the change-inoxidation-number method: (a) \(\mathrm{Cu}+\mathrm{O}_{2} \rightarrow \mathrm{CuO}\) (b) \(\mathrm{KClO}_{2} \rightarrow \mathrm{KCl}+\mathrm{O}_{2}\) (c) \(\mathrm{Ca}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{H}_{2}\) (d) \(\mathrm{PbS}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{PbSO}_{4}+\mathrm{H}_{2} \mathrm{O}\) (e) \(\mathrm{CH}_{4}+\mathrm{NO}_{2} \rightarrow \mathrm{N}_{2}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O}\)
Most explosive reactions are complex redox reactions with multiple oxidations and reductions. The reaction of gunpowder is shown below. Determine the element(s) oxidized and reduced. $$ \begin{aligned} &4 \mathrm{KNO}_{s}(s)+7 \mathrm{C}(s)+\mathrm{S}(s) \longrightarrow \\ &3 \mathrm{CO}_{2}(g)+3 \mathrm{CO}(g)+2 \mathrm{~N}_{3}(g)+\mathrm{K}_{2} \mathrm{CO}_{s}(s)+\mathrm{K}_{3} \mathrm{~S}(s) \end{aligned} $$
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