Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Name these hydrates: (a) \(\mathrm{BaBr}_{2} \cdot 2 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{AlCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{FePO}_{4} \cdot 4 \mathrm{H}_{2} \mathrm{O}\)

Short Answer

Expert verified
a) Barium Bromide Dihydrate, b) Aluminum Chloride Hexahydrate, c) Iron(III) Phosphate Tetrahydrate

Step by step solution

01

Identify the ionic compound

First, identify the base ionic compound in each hydrate formula before the dot (\(\cdot\)). For (a): \(\mathrm{BaBr}_{2}\), for (b): \(\mathrm{AlCl}_{3}\), and for (c): \(\mathrm{FePO}_{4}\).
02

Name the ionic compound

Now name the ionic compounds identified. For (a): Barium Bromide, for (b): Aluminum Chloride, and for (c): Iron(III) Phosphate (since \(\mathrm{Fe}\) has a +3 charge).
03

Identify the number of water molecules

Identify the number of water molecules attached in each hydrate. For (a): 2, for (b): 6, and for (c): 4.
04

Name the water molecules as 'hydrate'

Using prefixes for the number of water molecules, name them as 'hydrate'. For (2): 'dihydrate', for (6): 'hexahydrate', and for (4): 'tetrahydrate'.
05

Combine the names

Combine the name of the ionic compound with the prefix-hydrate term. For (a): Barium Bromide Dihydrate, for (b): Aluminum Chloride Hexahydrate, and for (c): Iron(III) Phosphate Tetrahydrate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

ionic compounds
Ionic compounds are made up of positively and negatively charged ions. These ions are held together by strong electrostatic forces, known as ionic bonds. In the exercise, the compounds \(\text{BaBr}_2\), \(\text{AlCl}_3\), and \(\text{FePO}_4\) are ionic compounds.

An ionic compound is usually made between a metal and a non-metal. For example: \(\text{BaBr}_2\) consists of barium (a metal) and bromine (a non-metal). The metal loses electrons to become a positively charged cation, while the non-metal gains electrons to become a negatively charged anion.

Understanding ionic compounds is essential because these compounds form unique structures and play significant roles in both chemistry and everyday life.
chemical nomenclature
Chemical nomenclature is the systematic method used for naming chemical substances. This ensures that every compound's name clearly describes its chemical composition and structure.

For ionic compounds, the name typically consists of the cation name followed by the anion name. For metals that can have different charges (like iron), we specify the charge using Roman numerals. In our examples, \(\text{BaBr}_2\) is named Barium Bromide and \(\text{AlCl}_3\) is named Aluminum Chloride. For \(\text{FePO}_4\), we use the name Iron(III) Phosphate because iron in this compound has a +3 charge.

This systematic approach helps avoid confusion, ensuring that each compound is uniquely and consistently identified.
hydrates
Hydrates are compounds that include water molecules within their crystalline structure. These water molecules are not just physically trapped but are chemically bonded within the compound. In the given exercise, the chemical formulas provided each have \text{H}_2O\ molecules attached with a dot before the water part.

To name hydrates, first, you name the base ionic compound, and then you use prefixes to denote the number of water molecules attached. For example:
  • \(\text{BaBr}_2 \cdot 2 \text{H}_2 \text{O}\) becomes Barium Bromide Dihydrate (di- meaning 2).
  • \(\text{AlCl}_3 \cdot 6 \text{H}_2 \text{O}\) becomes Aluminum Chloride Hexahydrate (hexa- meaning 6).
  • \(\text{FePO}_4 \cdot 4 \text{H}_2 \text{O}\) becomes Iron(III) Phosphate Tetrahydrate (tetra- meaning 4).

Understanding how to properly name hydrates is crucial for correctly communicating the composition of these compounds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is surface tension? How does it depend on intermolecular forces?

How many joules of energy are required to change \(50.0 \mathrm{~g} \mathrm{Cu}\) from \(25.0^{\circ} \mathrm{C}\) to a liquid at its melting point, \(1083^{\circ} \mathrm{C}\) ? Specific heat of \(\mathrm{Cu}=0.385 \mathrm{~J} / \mathrm{g}^{\circ} \mathrm{C}\) Heat of fusion for \(\mathrm{Cu}=134 \mathrm{~J} / \mathrm{g}\)

Isobutyl propionate, the ester responsible for the flavor of rum, has a boiling point of \(137^{\circ} \mathrm{C}\) and octyl acetate, the ester responsible for the flavor of oranges, has a boiling point of \(210^{\circ} \mathrm{C}\). Based on this information, which compound would you expect to have the higher vapor pressure? Explain how you came to this conclusion.

You buy a box of borax \(\left(\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)\) from the corner market in Phoenix, Arizona, in the middle of the summer. You open up the box and pour the borax into a weighed beaker. After all, you do want to be sure that you were not cheated by the manufacturer. You are distracted from your task and do not get back to weigh the filled beaker for several days. Upon weighing the beaker, you get the following data from the \(5.0-\mathrm{lb}\) box of borax. Empty beaker \(\quad 492.5 \mathrm{~g}\) Filled beaker \(\quad 2467.4 \mathrm{~g}\) Were you cheated by the manufacturer? Why or why not?

Rank the following molecules in order of increasing London dispersion forces: \(\mathrm{CCl}_{4}, \mathrm{CI}_{4}\), and \(\mathrm{CBr}_{4}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free