Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Classify the bond between these pairs of elements as principally ionic or principally covalent (use Table 11.5): (a) sodium and oxygen (b) nitrogen and hydrogen (c) oxygen and hydrogen (d) phosphorus and chlorine

Short Answer

Expert verified
The bond types are as follows: (a) sodium and oxygen form an ionic bond, (b) nitrogen and hydrogen form a covalent bond, (c) oxygen and hydrogen form a polar covalent bond, and (d) phosphorus and chlorine form a covalent bond.

Step by step solution

01

Review Bonding Concepts

Understand the difference between ionic and covalent bonds. Ionic bonds typically form between metals and nonmetals with a large difference in electronegativity, usually greater than 1.7 according to the Pauling scale. Covalent bonds form between nonmetals with a smaller difference in electronegativity.
02

Examine Each Element Pair

Identify the position of each element in the periodic table. Metals are typically on the left and centre (sodium), nonmetals on the right (oxygen, nitrogen, hydrogen, phosphorus, chlorine).
03

Determine the Bond for Sodium and Oxygen

Sodium is a metal with low electronegativity whereas oxygen is a nonmetal with high electronegativity. The difference is greater than 1.7, so the bond is principally ionic.
04

Determine the Bond for Nitrogen and Hydrogen

Both nitrogen and hydrogen are nonmetals with a smaller difference in electronegativity. Thus, the bond is principally covalent.
05

Determine the Bond for Oxygen and Hydrogen

Oxygen and hydrogen are both nonmetals, but the electronegativity difference is right around the threshold; usually considered covalent but is polar due to the difference in electronegativity.
06

Determine the Bond for Phosphorus and Chlorine

Both phosphorus and chlorine are nonmetals with a relatively small difference in electronegativity, indicating a principally covalent bond.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic and Covalent Bonds
Understanding the difference between ionic and covalent bonds is fundamental in chemistry. An ionic bond is a type of chemical bond where one atom donates an electron to another, resulting in the formation of positively and negatively charged ions that attract each other. This type of bond typically occurs between a metal, which tends to lose electrons, and a nonmetal, which tends to gain electrons.

On the other hand, a covalent bond is when two atoms share one or more pairs of electrons. This form of bonding commonly occurs between two nonmetals, which both have a similar tendency to attract electrons. The shared electrons occupy the space between the atoms, effectively 'gluing' them together to form a molecule.

For example, sodium (a metal) and oxygen (a nonmetal), create an ionic bond as sodium donates its outer electron to oxygen. Conversely, nitrogen and hydrogen, being both nonmetals, form a covalent bond as they share their electrons.
Electronegativity
Electronegativity is a measure of an atom's ability to attract and hold onto electrons when forming a chemical bond. It plays a crucial role in determining the type of bond two atoms will form. On the Pauling scale, which is commonly used to measure electronegativity, values generally range from about 0.7 to 4.0.

The larger the difference in electronegativity between two atoms, the more ionic the bond will be. Typically, a difference greater than 1.7 indicates an ionic bond, as seen between sodium (low electronegativity) and oxygen (high electronegativity). A smaller difference points towards a covalent bond. For example, the bond between oxygen and hydrogen is polar covalent because the difference in their electronegativity values is significant but not enough to make the bond ionic.
Periodic Table Elements
The periodic table is more than just a list of elements; it's a map of chemical properties. Tracking down the position of an element on the table can give insight into its bonding behavior. Metals, found on the left and center of the periodic table, tend to form ionic bonds due to their lower electronegativity. Nonmetals, located on the right side, are predisposed to form covalent bonds because of their higher electronegativity and tendency to share electrons.

When determining the type of bond, it's important to locate each element in the periodic table. This helps in predicting how an element will interact with others during bond formation. For instance, phosphorus and chlorine are both nonmetals making a covalent bond their mode of chemical combination.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw Lewis structures and give the shape of each of the following compounds: (a) \(\mathrm{NO}_{2}^{-}\) (c) \(\mathrm{SOCl}_{2}\) (b) \(\mathrm{SO}_{4}^{2-}\) (d) \(\mathrm{Cl}_{2} \mathrm{O}\)

Let E be any representative element. Following the pattern in the table, write formulas for the hydrogen and oxygen compounds of the following: (a) \(\mathrm{Na}\) (c) \(\mathrm{Al}\) (b) \(\mathrm{Ca}\) (d) \(\mathrm{Sn}\) $$ \begin{array}{|c|c|c|c|c|c|c|} \hline \text { Group } \\ \hline \mathbf{1 A ( 1 )} & \mathbf{2 A ( 2 )} & \mathbf{3 A ( 1 3 )} & \mathbf{4 A ( 1 4 )} & \mathbf{5 A ( 1 5 )} & \mathbf{6 A ( 1 6 )} & \mathbf{7 A ( 1 7 )} \\ \hline \mathrm{EH} & \mathrm{EH}_{2} & \mathrm{EH}_{3} & \mathrm{EH}_{4} & \mathrm{EH}_{3} & \mathrm{H}_{2} \mathrm{E} & \mathrm{HE} \\ \hline \mathrm{E}_{2} \mathrm{O} & \mathrm{EO} & \mathrm{E}_{2} \mathrm{O}_{3} & \mathrm{EO}_{2} & \mathrm{E}_{2} \mathrm{O}_{5} & \mathrm{EO}_{3} & \mathrm{E}_{2} \mathrm{O}_{7} \\ \hline \end{array} $$

The first ionization energy (IE) of potassium is lower than the first IE for calcium, but the second IE of calcium is lower than the second IE of potassium. Use an electron configuration or size argument to explain this trend in ionization energies.

Element \(X\) reacts with sodium to form the compound \(\mathrm{Na}_{2} X\) and is in the second period on the periodic table. Identify this element.

How many electrons must be gained or lost for the following to achieve a noble gas electron configuration? (a) a potassium atom (b) an aluminum ion (c) a bromine atom (d) a selenium atom

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free