Chapter 2: Problem 30
Cycloalkanes are a group of cyclic saturated hydrocarbons with a general formula of \(\mathrm{C}_n \mathrm{H}_3\). Which of the following compounds will display the LEAST amount of free rotation around a \(\mathrm{C}-\mathrm{C}\) single bond? A. alkanes, which are relatively inert chemically B. alkanes, which are able to form numerous types of isomers C. cycloalkanes, which are limited by geometric constraints D. cycloalkanes, which are polar and water soluble
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Free Rotation in Organic Molecules
However, if there are large substituents or specific structural constraints, this rotation can be hindered. Free rotation is important in determining the flexibility and shape of the molecule. A molecule with unrestricted rotation can adopt various conformations, which influences its properties and behavior.
Cyclic Hydrocarbons
Because the atoms form a closed loop, the structure imposes certain geometric constraints that affect the molecule’s physical and chemical properties. For example, the ring can result in stability differences and different kinds of reactivity, in contrast to open-chain hydrocarbons.
Geometric Constraints in Cycloalkanes
In smaller rings like cyclopropane or cyclobutane, the bond angles deviate significantly from the ideal tetrahedral angle (109.5 degrees), causing strain. This strain further restricts the rotation of the C-C bonds. Larger rings like cyclohexane have less angle strain and might adopt conformations like chair or boat forms to relieve it, but still, the constraints are more rigid than in alkanes.
This geometric rigidity is a key reason why cycloalkanes display the least amount of free rotation around carbon-carbon single bonds among the given options in the exercise.