Chapter 12: Problem 13
Reconsider diffusion and reaction in a spherical catalyst pellet for the case where the reaction is not isothermal. Show that the energy balance can be written as $$\frac{1}{r^{2}} \frac{d}{d r}\left(r^{2} k_{t} \frac{d T}{d r}\right)+\left(-\Delta H_{\mathrm{R}}\right)\left(-r_{\mathrm{A}}\right)=0$$ where \(k_{1}\) is the effective thermal conductivity, \(\operatorname{cal} / \mathrm{s} \cdot \mathrm{cm} \cdot \mathrm{K}\) of the pellet with \(d T / d r=0\) at \(r=0\) and \(T=T_{\mathrm{s}}\) at \(r=R\). (a) Evaluate Equation (12-11) for a first-order reaction and combine with Equation ( \(\mathrm{P} 12-15.1\) ) to arrive at an equation giving the maximum temperature in the pellet. $$T_{\max }=T_{s}+\frac{\left(-\Delta H_{R x}\right)\left(D_{e} C_{A s}\right)}{k_{t} T_{s}}$$ $$\text { Note: At } T_{\max }, C_{A}=0$$. (b) Choose representative values of the parameters and use a software package to solve Equations \((12-11)\) and \((\mathrm{P} 12-13.1)\) simultaneously for \(T(r)\) and \(C_{A}(r)\) when the reaction is carried out adiabatically. Show that the resulting solution agrees qualitatively with Figure \(12-7\).
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