Chapter 6: Problem 73
Write the electron-dot structure for the covalent compound hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\).
Short Answer
Expert verified
H-O-O-H with 8 lone electrons on oxygens.
Step by step solution
01
Count the Total Number of Valence Electrons
Each hydrogen atom contributes 1 valence electron, and each oxygen atom contributes 6 valence electrons. Therefore, for \(\text{H}_2\text{O}_2\), there are \(2 \times 1 + 2 \times 6 = 14\) valence electrons in total.
02
Determine the Skeleton Structure
Draw a skeletal structure using single bonds. Connect each hydrogen to an oxygen atom, and the oxygen atoms to each other, forming the basic framework: \(\text{H-O-O-H}\).
03
Distribute Remaining Electrons as Lone Pairs
After the bonds are drawn, the structure uses 6 electrons (3 bonds with 2 electrons each). Distribute the leftover 8 electrons as lone pairs on the oxygen atoms to complete the octet rule for them.
04
Verify the Octet Rule and Total Electrons
Ensure each oxygen atom has a complete octet. Each oxygen will have 2 bonded electrons and 4 lone electrons (2 pairs), totaling 8 electrons each. Also, confirm that the total of 14 valance electrons are accounted for in the structure.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Valence Electrons
Valence electrons are the outermost electrons of an atom. They play a crucial role in chemical bonding and reactivity. When determining how atoms will bond with each other, focusing on the valence electrons helps us predict the structure and properties of molecules.
In the case of hydrogen peroxide \(\mathrm{H}_2\mathrm{O}_2\), each hydrogen atom has 1 valence electron, and each oxygen atom has 6. Knowing this allows us to calculate the total number of electrons available for bonding. Here, the calculation is simple:
In the case of hydrogen peroxide \(\mathrm{H}_2\mathrm{O}_2\), each hydrogen atom has 1 valence electron, and each oxygen atom has 6. Knowing this allows us to calculate the total number of electrons available for bonding. Here, the calculation is simple:
- Hydrogen: \(2 \times 1 = 2\) electrons
- Oxygen: \(2 \times 6 = 12\) electrons
Octet Rule
The octet rule is a key principle in chemistry. It states that atoms tend to form bonds until they are surrounded by eight electrons in their valence shell. Achieving this stable arrangement makes the molecule more stable.
In the case of hydrogen peroxide, the goal is to have each oxygen atom satisfied the octet rule with 8 electrons. Here's how it works:
In the case of hydrogen peroxide, the goal is to have each oxygen atom satisfied the octet rule with 8 electrons. Here's how it works:
- Each oxygen forms two bonds (one with hydrogen, one with another oxygen), using 2 electrons from each bond.
- The remaining electrons are arranged as lone pairs to fill each oxygen atom's valence shell.
Covalent Compounds
Covalent compounds occur when atoms share electrons. They do this to achieve a full valence shell, often aiming for a noble gas configuration.
In hydrogen peroxide \(\mathrm{H}_2\mathrm{O}_2\), covalent bonds are formed:
In hydrogen peroxide \(\mathrm{H}_2\mathrm{O}_2\), covalent bonds are formed:
- Between hydrogen and oxygen (single bond)
- Between the two oxygen atoms (single bond)
Hydrogen Peroxide
Hydrogen peroxide is a common and interesting covalent compound with uses ranging from cleaning to chemical reactions. In its electron-dot structure, the placement of electrons is vital for understanding its reactivity.
Following the electron-dot structure steps:
Following the electron-dot structure steps:
- Start by placing single bonds between the atoms: \(\mathrm{H-O-O-H}\).
- Then distribute the remaining valence electrons to complete oxygen’s octet.