Chapter 3: Problem 91
Which has more atoms: a 1-gram sample of carbon-12 or a 1-gram sample of carbon-13? Explain.
Short Answer
Expert verified
A 1-gram sample of carbon-12 has more atoms than a 1-gram sample of carbon-13.
Step by step solution
01
Determine the Number of Moles in Each Sample
To find out how many moles of carbon are in each sample, we use the formula for moles: \( n = \frac{m}{M} \), where \( m \) is the mass of the substance and \( M \) is the molar mass.* For carbon-12: \( M = 12 \, \text{g/mol} \) \[ n = \frac{1 \, \text{g}}{12 \, \text{g/mol}} = 0.0833 \, \text{mol} \]* For carbon-13: \( M = 13 \, \text{g/mol} \) \[ n = \frac{1 \, \text{g}}{13 \, \text{g/mol}} = 0.0769 \, \text{mol} \]
02
Calculate the Number of Atoms in Each Sample Using Avogadro's Number
To find the number of atoms, we multiply the number of moles by Avogadro's number \( N_A = 6.022 \times 10^{23} \, \text{atoms/mol} \).* For carbon-12: \[ \text{Number of atoms} = 0.0833 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 5.02 \times 10^{22} \, \text{atoms} \]* For carbon-13: \[ \text{Number of atoms} = 0.0769 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 4.63 \times 10^{22} \, \text{atoms} \]
03
Compare the Number of Atoms
After calculating the number of atoms in each sample, compare the results:* Carbon-12 has approximately \( 5.02 \times 10^{22} \) atoms.* Carbon-13 has approximately \( 4.63 \times 10^{22} \) atoms.The sample of carbon-12 has more atoms than the sample of carbon-13.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Moles Calculation
The concept of moles calculation is crucial in chemistry for quantifying the amount of substance. Moles serve as a bridge between the atomic scale and the real world that we can measure. When calculating moles, you use the formula:
For example, when you have a 1-gram sample of carbon-12, with a molar mass of 12 g/mol, the number of moles \( n \) is calculated as follows:
- \( n = \frac{m}{M} \)
For example, when you have a 1-gram sample of carbon-12, with a molar mass of 12 g/mol, the number of moles \( n \) is calculated as follows:
- \( n = \frac{1 \, \text{g}}{12 \, \text{g/mol}} = 0.0833 \, \text{mol} \)
Molar Mass Comparison
Comparing molar masses is important when assessing different isotopes or different compounds because it influences the number of moles present in a sample.
A higher molar mass, like that of carbon-13 compared to carbon-12, results in fewer moles when you have the same mass. This is because more mass per mole (higher molar mass) reduces the number of moles \( n = \frac{m}{M} \).
When comparing the calculations:
- Carbon-12 has a molar mass of 12 g/mol.
- Carbon-13 has a molar mass of 13 g/mol.
A higher molar mass, like that of carbon-13 compared to carbon-12, results in fewer moles when you have the same mass. This is because more mass per mole (higher molar mass) reduces the number of moles \( n = \frac{m}{M} \).
When comparing the calculations:
- For carbon-12: \( n = 0.0833 \) mol
- For carbon-13: \( n = 0.0769 \) mol
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry that defines the number of particles (usually atoms or molecules) present in one mole of a substance. This value, \( N_A = 6.022 \times 10^{23} \) particles per mole, creates a crucial relationship between moles and the actual number of atoms or molecules.
In solving the original problem, once the number of moles is known, Avogadro's number can be used to find the exact number of atoms. For carbon-12, with 0.0833 moles:
In solving the original problem, once the number of moles is known, Avogadro's number can be used to find the exact number of atoms. For carbon-12, with 0.0833 moles:
- \( \text{Number of atoms} = 0.0833 \, \text{moles} \times 6.022 \times 10^{23} \, \text{atoms/mole} \approx 5.02 \times 10^{22} \) atoms
- \( \text{Number of atoms} = 0.0769 \, \text{moles} \times 6.022 \times 10^{23} \, \text{atoms/mole} \approx 4.63 \times 10^{22} \) atoms