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Which of these gas samples contains the largest number of molecules and which contains the smallest? (a) \(1.0 \mathrm{~L} \mathrm{H}_{2}\) at \(\mathrm{STP}\) (b) \(1.0 \mathrm{~L} \mathrm{~N}_{2}\) at \(\mathrm{STP}\) (c) \(1.0 \mathrm{~L} \mathrm{H}_{2}\) at \(27{ }^{\circ} \mathrm{C}\) and \(760 . \mathrm{mmHg}\) (d) \(1.0 \mathrm{~L} \mathrm{CO}_{2}\) at \(0{ }^{\circ} \mathrm{C}\) and \(800 . \mathrm{mmHg}\)

Short Answer

Expert verified
The \( \mathrm{CO}_2 \) sample has the largest number of molecules; \( \mathrm{H}_2 \) at 27°C and 760 mmHg has the smallest.

Step by step solution

01

Recall the ideal gas law

The ideal gas law is given by the formula \( PV = nRT \), where \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the gas constant, and \( T \) is temperature in Kelvin.
02

Understand the conditions at STP

Standard Temperature and Pressure (STP) is defined as 0°C (273.15 K) and 1 atm (760 mmHg). Under these conditions, 1 mole of an ideal gas occupies 22.4 L.
03

Calculate moles for gases at STP

Both 1.0 L of \( \mathrm{H}_2 \) at STP and 1.0 L of \( \mathrm{N}_2 \) at STP have the same conditions, so they each contain \( \frac{1.0}{22.4} = 0.04464 \) moles.
04

Convert non-STP conditions to STP equivalents

For 1.0 L \( \mathrm{H}_2 \) at 27°C (300.15 K) and 760 mmHg: Convert temperature to Kelvin and use \( n = \frac{PV}{RT} \) with \( R = 0.0821 \ { \rm L \, atm / K \, mol} \) and \( P = 1 \ { \rm atm} \). Therefore, \( n = \frac{1.0 \times 1}{0.0821\times300.15} = 0.0403 \) moles.
05

Calculate moles for conditioned \( CO_2 \)

For 1.0 L \( \mathrm{CO}_2 \) at 0°C and 800 mmHg: Convert the pressure to atm (800 mmHg = 1.0526 atm) and use the ideal gas law: \( n = \frac{1.0526 \times 1}{0.0821 \times 273.15} = 0.0463 \) moles.
06

Compare moles to determine the number of molecules

Moles are directly proportional to the number of molecules (Avogadro's number \(6.022 \times 10^{23}\)). Thus, more moles mean more molecules. Comparing the moles calculated: 0.0463 (\( \mathrm{CO}_2 \)) > 0.04464 (\( \mathrm{H}_2 \) at STP and \( \mathrm{N}_2 \) at STP) > 0.0403 (\( \mathrm{H}_2 \) at 27°C).
07

Final conclusion

The \( \mathrm{CO}_2 \) sample has the largest number of molecules, while \( \mathrm{H}_2 \) at 27°C and 760 mmHg contains the smallest number of molecules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Temperature and Pressure
When talking about gases in chemistry, Standard Temperature and Pressure (STP) is a very important concept. It provides a common reference point so scientists can easily compare results and make calculations.

**What does STP mean exactly?**
To simplify, STP conditions are defined as 0°C (or 273.15 Kelvin, more scientifically) and 1 atm of pressure, which equals 760 mmHg.

Under these conditions, one mole of any ideal gas occupies 22.4 liters of volume. This is a very useful number because it allows comparisons and calculations involving different gases without having to account for varying conditions like temperature or pressure.

You can think of STP as the universal language for gases! Whether it's hydrogen, nitrogen, or carbon dioxide, knowing that 1 mole will fill 22.4 L helps chemists work out how many molecules are present in a sample under these conditions.
Moles and Molecules
In chemistry, moles and molecules are like cups and drops of water. A mole is a counting unit, just like a dozen or a pair, but much larger. One mole equals Avogadro's number, which is approximately 6.022 x 10^23 molecules or atoms.

**Why use moles?**
Moles let chemists count large numbers of small entities, like molecules, in a practical way. Without a unit like the mole, it would be daunting to count every single molecule in a sample.

**Moles are linked to volume through STP:**
- At STP conditions, 1 mole of an ideal gas occupies 22.4 liters.
- This helps determine how many moles and therefore molecules are in a given volume of gas.

Using the ideal gas law (\(PV = nRT\)), where \(n\) is the number of moles, you can calculate how many molecules a sample contains just by knowing its volume and the conditions it's kept in. This calculation is crucial for comparing different gases like we did when we determined which sample had the most molecules.
Gas Laws in Chemistry
The behavior of gases can be described using the ideal gas law, a fundamental equation in chemistry. This is expressed as \(PV = nRT\), where:
  • \(P\) stands for pressure
  • \(V\) is the volume
  • \(n\) is the number of moles
  • \(R\) is the ideal gas constant
  • \(T\) is the temperature in Kelvin

This law helps predict how changes in temperature, volume, and pressure can affect a gas. For example, if you increase the temperature of a gas while keeping its volume constant, the pressure will also increase.

**Understanding Real-world Conditions:**
In chemistry, it is important to understand how the variables in \(PV = nRT\) interact.

- **Pressure and Volume:** As per Boyle's Law, if the volume decreases, the pressure increases, given a constant temperature.
- **Volume and Temperature:** Charles's Law tells us that if you increase temperature, the volume increases if pressure is constant.
- **Pressure and Temperature:** Gay-Lussac’s Law states that pressure increases with temperature if volume is constant.

These interconnections help us understand not just laboratory settings but also natural phenomena like weather and even breathing.

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Most popular questions from this chapter

An ideal gas was contained in a glass vessel of unknown volume with a pressure of \(0.960 \mathrm{~atm} .\) Some of the gas was withdrawn from the vessel and used to fill a \(25.0-\mathrm{mL}\) glass bulb to a pressure of \(1.00 \mathrm{~atm}\). The pressure of the gas remaining in the vessel of unknown volume was 0.882 atm. All the measurements were done at the same temperature. Determine the volume of the vessel.

A substance is analyzed and found to contain \(85.7 \%\) carbon and \(14.3 \%\) hydrogen by mass. A gaseous sample of the substance is found to have a density of \(1.87 \mathrm{~g} / \mathrm{L}\) at STP. (a) Calculate the molar mass of the compound. (b) Determine the empirical and molecular formulas of the compound. (c) Draw two possible Lewis structures for molecules of the compound.

Can ozone form in the stratosphere at night? Explain why or why not.

A sample of gas has a volume of \(2.50 \mathrm{~L}\) at a pressure of \(670 . \mathrm{mmHg}\) and a temperature of \(80 .{ }^{\circ} \mathrm{C} .\) If the pressure remains constant but the temperature is decreased, the gas occupies \(1.25 \mathrm{~L}\). Determine this new temperature, in degrees Celsius.

The relation between the average kinetic energy of a molecule, \(\frac{1}{2} m v^{2},\) and the absolute temperature is $$\frac{1}{2} m v^{2}=\frac{3}{2} k T$$ \(m\) is the mass of the molecule; \(v\) is its average velocity; \(k\) is \(1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K} ; T\) is the absolute temperature. \(1 \mathrm{~J}=1 \mathrm{~kg} \mathrm{~m}^{2} \mathrm{~s}^{-2}\). Calculate the average velocity of a nitrogen dioxide molecule in the atmosphere at \(27.0^{\circ} \mathrm{C}\).

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