Chapter 6: Problem 81
Tribromide, \(\mathrm{Br}_{3}^{-},\) and triiodide \(, \mathrm{I}_{3}^{-},\) ions are often found in aqueous solutions, but trifluoride ion, \(\mathrm{F}_{3}^{-},\) is so rare that its bond strength was only measured in \(2000 .\) Explain.
Short Answer
Expert verified
Fluorine's high electronegativity and small size make
F_{3}^{-}
unstable compared to
Br_{3}^{-}
and
I_{3}^{-}
.
Step by step solution
01
Understanding Molecular Structure
To understand why trifluoride ion (
F_{3}^{-}
) is rare, we first consider the structure of these polyatomic ions. Trihalide ions like
Br_{3}^{-}
and
I_{3}^{-}
are linear due to their symmetrical distribution of electrons around the central atom.
02
Electronegativity and Bonding
Fluorine is highly electronegative, much more than bromine and iodine. This high electronegativity leads to difficulty in forming stable bonds that can distribute the negative charge over three fluorine atoms effectively, as seen in other trihalide ions.
03
Comparison with Other Halogens
In contrast, bromine and iodine can form stable trihalide ions because they have lower electronegativity, larger atomic sizes, and can accommodate more loosely held electron pairs, allowing better distribution of the negative charge.
04
Ionic Stability and Environment
The environment in which these ions form plays a part too. In water, bromine and iodine have unique solvation energies that suggest energetically favorable conditions for forming
Br_{3}^{-}
and
I_{3}^{-}
ions. Fluorine, being very reactive and smaller, lacks this stabilization, making
F_{3}^{-}
formation unfavorable.
05
Historical Context of Discovery
The fact that the bond strength of
F_{3}^{-}
was only measured in 2000 indicates difficulties in stabilizing and observing this ion under normal conditions, unlike its bromine and iodine counterparts which are more stable and easier to study.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electronegativity
Electronegativity is a measure of an atom's ability to attract and hold onto electrons. It plays a crucial role in determining the nature and strength of chemical bonds. Fluorine has the highest electronegativity of all elements, which significantly influences its chemical behavior.
Due to its strong electronegative nature, fluorine tends to attract electrons strongly towards itself. This characteristic can lead to challenges in forming stable bonds with other atoms, especially in complex ions like \(\mathrm{F}_{3}^{-}\). As the electron attraction is very intense, achieving a balance that neutralizes the intense charge pull while keeping a stable structure is quite daunting.
A higher electronegativity means that during bonding, the electrons are not easily shared, leading to instability in ions that require charge distribution over multiple atoms, such as the hypothetical \(\mathrm{F}_{3}^{-}\) ion.
Due to its strong electronegative nature, fluorine tends to attract electrons strongly towards itself. This characteristic can lead to challenges in forming stable bonds with other atoms, especially in complex ions like \(\mathrm{F}_{3}^{-}\). As the electron attraction is very intense, achieving a balance that neutralizes the intense charge pull while keeping a stable structure is quite daunting.
A higher electronegativity means that during bonding, the electrons are not easily shared, leading to instability in ions that require charge distribution over multiple atoms, such as the hypothetical \(\mathrm{F}_{3}^{-}\) ion.
Ionic Stability
Ionic stability refers to the equilibrium between opposing forces in ionic compounds. For an ion to be stable, its electron configuration and the surrounding environment must favor its current state.
In aqueous solutions, bromide (\(\mathrm{Br}_{3}^{-}\)) and iodide (\(\mathrm{I}_{3}^{-}\)) ions exhibit stability due to their ability to spread the negative charge efficiently across their atoms. This is largely possible because of their moderate electronegativity and larger atomic size. These factors permit the electron cloud to distribute evenly across the atoms without too much repulsion from a single spot.
Fluorine, with its high electronegativity and small size, does not favor such arrangement. Its electron cloud is tightly held, which does not support stable sharing or spreading of the negative potential across multiple atoms in a complex ion, leading to decreased ionic stability of \(\mathrm{F}_{3}^{-}\) ions.
In aqueous solutions, bromide (\(\mathrm{Br}_{3}^{-}\)) and iodide (\(\mathrm{I}_{3}^{-}\)) ions exhibit stability due to their ability to spread the negative charge efficiently across their atoms. This is largely possible because of their moderate electronegativity and larger atomic size. These factors permit the electron cloud to distribute evenly across the atoms without too much repulsion from a single spot.
Fluorine, with its high electronegativity and small size, does not favor such arrangement. Its electron cloud is tightly held, which does not support stable sharing or spreading of the negative potential across multiple atoms in a complex ion, leading to decreased ionic stability of \(\mathrm{F}_{3}^{-}\) ions.
Molecular Structure
The molecular structure of polyatomic ions like \(\mathrm{Br}_{3}^{-}\) and \(\mathrm{I}_{3}^{-}\) heavily influences their stability. These ions typically adopt a linear structure, which simplifies electron distribution and minimizes repulsion.
Linear structures are symmetric, allowing the valence electrons to be shared or delocalized more uniformly. This symmetry helps stabilize trihalide ions by reducing any imbalance in the distribution of the negative charge, allowing them to exist easily in solution.
Fluoride ions, however, struggle to achieve a similar stable structural arrangement due to fluorine's small atomic radius and high electron affinity. These factors cause a significant imbalance when attempting to evenly distribute the charge across a potentially linear structure, adding to the rarity of \(\mathrm{F}_{3}^{-}\) ions.
Linear structures are symmetric, allowing the valence electrons to be shared or delocalized more uniformly. This symmetry helps stabilize trihalide ions by reducing any imbalance in the distribution of the negative charge, allowing them to exist easily in solution.
Fluoride ions, however, struggle to achieve a similar stable structural arrangement due to fluorine's small atomic radius and high electron affinity. These factors cause a significant imbalance when attempting to evenly distribute the charge across a potentially linear structure, adding to the rarity of \(\mathrm{F}_{3}^{-}\) ions.
Halogen Chemistry
Halogen chemistry is characterized by the unique properties and reactivity of the halogens: fluorine, chlorine, bromine, iodine, and astatine. Each has distinct qualities, especially evident in forming polyatomic ions.
With decreasing electronegativity down the group, elements like bromine and iodine can form stable trihalide ions such as \(\mathrm{Br}_{3}^{-}\) and \(\mathrm{I}_{3}^{-}\). Their lower electronegativity compared to fluorine means electrons are less tightly held, allowing more flexibility in molecular interactions and bonding.
Additionally, halogen chemistry accounts for differences in solvation energies in aqueous solutions. Iodine and bromine ions benefit from environments that promote stability via interactions that accommodate their larger atomic sizes and lower electronegativity. These conditions are unfavorable for fluorine, which remains too reactive and unstable in similar settings to form \(\mathrm{F}_{3}^{-}\), thus illustrating the intricacies of halogen chemistry across the periodic table.
With decreasing electronegativity down the group, elements like bromine and iodine can form stable trihalide ions such as \(\mathrm{Br}_{3}^{-}\) and \(\mathrm{I}_{3}^{-}\). Their lower electronegativity compared to fluorine means electrons are less tightly held, allowing more flexibility in molecular interactions and bonding.
Additionally, halogen chemistry accounts for differences in solvation energies in aqueous solutions. Iodine and bromine ions benefit from environments that promote stability via interactions that accommodate their larger atomic sizes and lower electronegativity. These conditions are unfavorable for fluorine, which remains too reactive and unstable in similar settings to form \(\mathrm{F}_{3}^{-}\), thus illustrating the intricacies of halogen chemistry across the periodic table.