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When calcium oxide, \(\mathrm{CaO}(\mathrm{s})\), dissolves in water the water becomes hot. Write a chemical equation for this process and indicate whether it is exothermic or endothermic.

Short Answer

Expert verified
The reaction is \( \text{CaO (s) + H}_2\text{O (l) } \rightarrow \text{Ca(OH)}_2\text{ (aq)} \) and it is exothermic.

Step by step solution

01

Understand the reaction components

Calcium oxide (CaO) reacts with water (H₂O) to form calcium hydroxide, Ca(OH)₂. This reaction is a combination of a solid and liquid to form an aqueous solution.
02

Write the chemical equation

The chemical reaction of calcium oxide with water is as follows: \[ \text{CaO (s) + H}_2\text{O (l) } \rightarrow \text{Ca(OH)}_2\text{ (aq)} \]. This equation represents the transformation of solid calcium oxide and liquid water into aqueous calcium hydroxide.
03

Determine the reaction type

Since the water becomes hot during this process, the reaction releases heat. Therefore, the reaction is classified as exothermic, as heat energy is released into the surroundings.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exothermic Reactions
An exothermic reaction is a type of chemical reaction where energy, usually in the form of heat, is released into the surroundings. This happens because the energy needed to break bonds in the reactants is less than the energy released when new bonds are formed in the products. In simpler terms, the process gives off more energy than it absorbs.
Imagine you are striking a match against a matchbox. The friction of the match head creates enough energy to cause a chemical change, producing heat and light. Similarly, when calcium oxide reacts with water, the reaction is exothermic because it releases heat into the water, making it feel hot.
  • Exothermic reactions can be seen in everyday processes like burning wood, respiration, and even hand warmers.
  • They are characterized by a temperature increase in the surroundings as the reaction proceeds.
This is a clear indication that energy is being emitted from the reaction itself.
Calcium Hydroxide Formation
Calcium hydroxide formation involves combining calcium oxide, a solid, with water, a liquid, to form an aqueous solution of calcium hydroxide. This process transforms basic substances into a new compound.
When calcium oxide, often known as quicklime, is mixed with water, the result is a highly alkaline solution of calcium hydroxide, commonly called slaked lime, which can dissolve partially in water. This simple yet intriguing reaction has important practical applications.
  • Calcium hydroxide is widely used for soil stabilization, where it helps to alter the properties of the soil for better construction support.
  • It is also used in treating drinking water and wastewater, where it helps to remove impurities.
  • In the production of corn tortillas, calcium hydroxide aids in the process of nixtamalization, which improves the nutritional quality of the corn.
This reaction not only changes physical states but also the chemical identity of the substances involved.
Chemical Equations
Chemical equations are a way to represent chemical reactions using symbols and formulas for the reactants and products. They provide a concise and informative method to convey the details of chemical processes.
The chemical equation for the reaction of calcium oxide with water is \[ \text{CaO (s) + H}_2\text{O (l) } \rightarrow \text{Ca(OH)}_2\text{ (aq)} \]. This equation tells us:
  • "CaO (s)" represents solid calcium oxide.
  • "H₂O (l)" stands for liquid water.
  • "Ca(OH)₂ (aq)" is aqueous calcium hydroxide, meaning it is dissolved in water.
The arrow in the equation points from the reactants to the products, visually indicating the transformation.
Understanding chemical equations allows us to predict the products of a reaction, calculate quantities of reactants needed, and comprehend the conditions under which reactions occur. In summary, chemical equations are crucial tools in chemistry that offer insight into the nature of reactions and help communicate complex processes in a manageable format.

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Most popular questions from this chapter

Design an experiment to directly measure the reaction enthalpy for this reaction $$ 2 \mathrm{NaOH}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \longrightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\ell) $$ Describe the apparatus and how the experiment would be carried out.

$$ \begin{aligned} &\text { Use these bond enthalpy values to answer Question } { . }\\\ &\begin{array}{lclc} \hline \text { Bond } & \begin{array}{c} \text { Bond Enthalpy } \\ (\mathrm{k}\rfloor / \mathrm{mol}) \end{array} & \text { Bond } & \begin{array}{c} \text { Bond Enthalpy } \\ (\mathrm{k} / / \mathrm{mol}) \end{array} \\ \hline \mathrm{H}-\mathrm{F} & 566 & \mathrm{~F}-\mathrm{F} & 158 \\ \mathrm{H}-\mathrm{Cl} & 431 & \mathrm{Cl}-\mathrm{Cl} & 242 \\ \mathrm{H}-\mathrm{Br} & 366 & \mathrm{Br}-\mathrm{Br} & 193 \\ \mathrm{H}-\mathrm{I} & 299 & \mathrm{I}-\mathrm{I} & 151 \\ \mathrm{H}-\mathrm{H} & 436 & & \\ \hline \end{array} \end{aligned} $$ For the reactions of molecular hydrogen with fluorine and with chlorine: (a) Calculate the enthalpy change for breaking all the bonds in the reactants. (b) Calculate the enthalpy change for forming all the bonds in the products. (c) From the results in parts (a) and (b), calculate the enthalpy change for the reaction. (d) Which reaction is most exothermic?

What is the value of the standard formation enthalpy for any element under standard conditions?

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The energy unit used by electrical utilities in their monthly bills is the kilowatt hour \((\mathrm{kWh} ; 1\) kilowatt used for 1 hour). Calculate how many joules there are in a kilowatt hour. If electricity costs \(\$ .09\) per kilowatt hour, calculate how much it costs per megajoule.

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