Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What information does a balanced chemical equation provide?

Short Answer

Expert verified
A balanced equation provides the identities and ratios of reactants and products, ensuring mass conservation.

Step by step solution

01

Understanding Balanced Equations

A balanced chemical equation provides information about the reactants and products involved in a chemical reaction. It shows both the qualitative (identity of substances) and quantitative (mole ratios) information.
02

Reactants and Products

The balanced equation lists the chemical formulas of the reactants (the starting substances) on the left side of the arrow and the products (the substances formed) on the right side. This helps identify the substances involved in the reaction.
03

Mole Ratios Interpretation

Balanced equations show the proportion of molecules or moles of each substance that participate in the reaction. Each coefficient in the equation tells how many molecules or moles of a substance are involved, maintaining the conservation of mass.
04

Conservation of Mass

A balanced chemical equation demonstrates the law of conservation of mass, which states that mass cannot be created or destroyed in a chemical reaction. Therefore, the number of atoms for each element remains the same on both sides of the equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reactants and Products
In chemistry, understanding the terminology of reactants and products is crucial. When a chemical reaction takes place, reactants are the initial substances that undergo change. They are positioned on the left side of a chemical equation. During the reaction, these reactants are transformed into new substances known as products. Products are shown on the right side of the equation.

A clear, balanced chemical equation provides a snapshot of this transformation process. It specifies what substances start the reaction and what substances result from it. Consider it a recipe, where the reactants are your ingredients, and the final dish is the product. By looking at the equation, you immediately know what's involved in the reaction, both in terms of starting materials and outcomes.
Mole Ratios in Equations
Mole ratios in equations are a vital concept when balancing chemical reactions. They provide a quantitative glimpse into the proportions involved. In a balanced chemical equation, numbers before each substance (called coefficients) represent mole ratios. These coefficients tell us how many moles of a particular reactant will react with a certain number of moles of another reactant to produce specific products.
  • For example, in the equation: \( 2H_2 + O_2 \rightarrow 2H_2O \), the coefficients indicate that 2 moles of \( H_2 \) react with 1 mole of \( O_2 \) to produce 2 moles of \( H_2O \).
  • This ratio is crucial for understanding how much of each substance is needed for the reaction to proceed without any shortages or excesses.

    • Using these ratios helps chemists calculate how much of each reactant is necessary and predict the amounts of products that will be formed in a reaction.
Conservation of Mass in Chemistry
The principle of conservation of mass is a fundamental aspect of chemistry, underscored by balanced chemical equations. This principle asserts that mass cannot be created or destroyed during a chemical reaction. Hence, whatever you start with in terms of atomic quantity on the reactants side will be identical on the products side.

This means the total number of each type of atom in the reactants must equal the total number in the products. For instance, if you begin with 2 hydrogen atoms and 1 oxygen atom, you must end with the same number of each atom after the reaction.
  • A balanced chemical equation like \( 2H_2 + O_2 \rightarrow 2H_2O \) ensures that you have 4 hydrogen atoms and 2 oxygen atoms on both sides, maintaining the integrity of mass conservation.
  • This equality guarantees no atom is mysteriously lost or gained during the reaction, making it a predictable and reliable process.
Understanding this principle helps in acquiring a deeper insight into how reactions happen and serves as a basis for further chemical calculations and reasoning.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Azurite is a copper-containing mineral that often forms beautiful crystals. Its formula is \(\mathrm{Cu}_{3}\left(\mathrm{CO}_{3}\right)_{2}(\mathrm{OH})_{2} .\) Write a balanced equation for the reaction of this mineral with hydrochloric acid.

Aluminum chloride, \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\), is an inexpensive reagent used in many industrial processes. It is made by treating scrap aluminum with chlorine according to the balanced equation $$2 \mathrm{Al}(\mathrm{s})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow \mathrm{Al}_{2} \mathrm{Cl}_{6}(\mathrm{~s})$$ (a) Determine which reactant is limiting if \(2.70 \mathrm{~g} \mathrm{Al}\) and \(4.05 \mathrm{~g} \mathrm{Cl}_{2}\) are mixed. (b) Calculate what mass of \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) can be produced. (c) Calculate what mass of the excess reactant remains when the reaction is complete.

Disulfur dichloride, which has a revolting smell, can be prepared by directly combining \(\mathrm{S}_{8}\) and \(\mathrm{Cl}_{2}\), but it can also be made by this reaction: \(3 \mathrm{SCl}_{2}(\ell)+4 \mathrm{NaF}(\mathrm{s}) \longrightarrow \mathrm{SF}_{4}(\mathrm{~g})+\mathrm{S}_{2} \mathrm{Cl}_{2}(\ell)+4 \mathrm{NaCl}(\mathrm{s})\) Calculate the mass of \(\mathrm{SCl}_{2}\) needed to react with excess NaF to prepare \(1.19 \mathrm{~g} \mathrm{~S}_{2} \mathrm{Cl}_{2}\) if the expected yield is \(51 \%\).

A commercial antacid tablet contains \(\mathrm{NaAl}(\mathrm{OH})_{2} \mathrm{CO}_{3}\) plus inert materials. A \(0.500-\mathrm{g}\) tablet is titrated and requires \(27.60 \mathrm{~mL}\) of \(0.425-\mathrm{M} \mathrm{HCl}\) to reach the equivalence point. Calculate the mass percent of \(\mathrm{NaAl}(\mathrm{OH})_{2} \mathrm{CO}_{3}\) in the tablet.

Nitrogen monoxide is oxidized in air to give brown nitrogen dioxide. $$2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NO}_{2}(\mathrm{~g})$$ Starting with \(2.2 \mathrm{~mol} \mathrm{NO},\) calculate how many moles and how many grams of \(\mathrm{O}_{2}\) are required for complete reaction. Calculate what mass of \(\mathrm{NO}_{2}\), in grams, is produced.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free