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Calculate the molar mass of each of these compounds and the mass percent of each element. (a) PbS, lead(II) sulfide, galena (b) \(\mathrm{C}_{2} \mathrm{H}_{6},\) ethane, a hydrocarbon fuel (c) \(\mathrm{CH}_{3} \mathrm{COOH}\), acetic acid, an important ingredient in vinegar (d) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), ammonium nitrate, a fertilizer

Short Answer

Expert verified
PbS: 239.27 g/mol; Pb 86.62%, S 13.38%. C₂H₆: 30.07 g/mol; C 79.88%, H 20.12%. CH₃COOH: 60.05 g/mol; C 40.01%, H 6.71%, O 53.28%. NH₄NO₃: 80.052 g/mol; N 35.00%, H 5.04%, O 59.96%.

Step by step solution

01

Calculate Molar Mass of PbS

To find the molar mass of PbS (lead(II) sulfide), add the atomic masses of lead (Pb) and sulfur (S). The atomic mass of Pb is approximately 207.2 g/mol and for S, it is approximately 32.07 g/mol.\[\text{Molar Mass of PbS} = 207.2\, ext{g/mol} + 32.07\, ext{g/mol} = 239.27\, ext{g/mol}\]
02

Calculate Mass Percent for PbS

The mass percent of each element in PbS can be calculated using the formula: \[\text{Mass Percent of Element} = \left(\frac{\text{Mass of Element in 1 mol of compound}}{\text{Molar Mass of compound}}\right) \times 100\%\]For lead (Pb):\[\text{Mass Percent of Pb} = \left(\frac{207.2}{239.27}\right) \times 100\% \approx 86.62\%\]For sulfur (S):\[\text{Mass Percent of S} = \left(\frac{32.07}{239.27}\right) \times 100\% \approx 13.38\%\]
03

Calculate Molar Mass of \\ \mathrm{C}_{2} \mathrm{H}_{6}

For ethane, calculate the molar mass by summing the atomic masses of its constituent elements: carbon (C) and hydrogen (H). The atomic mass of C is approximately 12.01 g/mol and H is approximately 1.008 g/mol.\[\text{Molar Mass} = 2(12.01\, ext{g/mol}) + 6(1.008\, ext{g/mol}) = 24.02\, ext{g/mol} + 6.048\, ext{g/mol} = 30.07\, ext{g/mol}\]
04

Calculate Mass Percent for \\ \mathrm{C}_{2} \mathrm{H}_{6}

For ethane, the mass percent of each element is calculated using the formula:For carbon (C):\[\text{Mass Percent of C} = \left(\frac{24.02}{30.07}\right) \times 100\% \approx 79.88\%\]For hydrogen (H):\[\text{Mass Percent of H} = \left(\frac{6.048}{30.07}\right) \times 100\% \approx 20.12\%\]
05

Calculate Molar Mass of \\ \mathrm{CH}_{3} \mathrm{COOH}

For acetic acid, sum the atomic masses of all its constituent atoms: 2 carbon (C) atoms, 4 hydrogen (H) atoms, and 2 oxygen (O) atoms.\[\text{Molar Mass} = 2(12.01\, ext{g/mol}) + 4(1.008\, ext{g/mol}) + 2(16.00\, ext{g/mol})\]\[= 24.02\, ext{g/mol} + 4.032\, ext{g/mol} + 32.00\, ext{g/mol} = 60.05\, ext{g/mol}\]
06

Calculate Mass Percent for \\ \mathrm{CH}_{3} \mathrm{COOH}

To find the mass percent of each element:For carbon (C):\[\text{Mass Percent of C} = \left(\frac{24.02}{60.05}\right) \times 100\% \approx 40.01\%\]For hydrogen (H):\[\text{Mass Percent of H} = \left(\frac{4.032}{60.05}\right) \times 100\% \approx 6.71\%\]For oxygen (O):\[\text{Mass Percent of O} = \left(\frac{32.00}{60.05}\right) \times 100\% \approx 53.28\%\]
07

Calculate Molar Mass of \\ \mathrm{NH}_{4} \mathrm{NO}_{3}

Sum the atomic masses: 2 nitrogen (N) atoms, 4 hydrogen (H) atoms, and 3 oxygen (O) atoms.\[\text{Molar Mass} = 2(14.01\, ext{g/mol}) + 4(1.008\, ext{g/mol}) + 3(16.00\, ext{g/mol})\]\[= 28.02\, ext{g/mol} + 4.032\, ext{g/mol} + 48.00\, ext{g/mol} = 80.052\, ext{g/mol}\]
08

Calculate Mass Percent for \\ \mathrm{NH}_{4} \mathrm{NO}_{3}

Find the mass percent of each element: For nitrogen (N):\[\text{Mass Percent of N} = \left(\frac{28.02}{80.052}\right) \times 100\% \approx 35.00\%\]For hydrogen (H):\[\text{Mass Percent of H} = \left(\frac{4.032}{80.052}\right) \times 100\% \approx 5.04\%\]For oxygen (O):\[\text{Mass Percent of O} = \left(\frac{48.00}{80.052}\right) \times 100\% \approx 59.96\%\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Percent Calculation
Mass percent is a useful way to express how much of each element is present in a compound. It is given as a percentage of the total mass of the compound. To calculate mass percent, you need to know both the mass of each element in one mole of the compound and the molar mass of the entire compound.

Here's how you can do it:
  • First, find the molar mass of the compound by adding the atomic masses of all elements in the compound.
  • Then, calculate the mass of each element in one mole of the compound. This is simply the atomic mass of the element multiplied by the number of atoms of that element in the formula.
  • Next, use the formula for mass percent: \( \text{Mass Percent of Element} = \left(\frac{\text{Mass of Element in 1 mol of compound}}{\text{Molar Mass of compound}}\right) \times 100\% \).
For example, in lead(II) sulfide (PbS), you calculate the mass percent of lead and sulfur separately by dividing their masses by the compound's molar mass and then multiplying by 100%. This gives you a clear picture of the composition of the compound.
Chemical Formula Interpretation
Understanding chemical formulas is like knowing a secret language that tells you about the composition of substances. Each chemical formula reveals which elements are present and how many atoms of each are contained in a single molecule of the compound.

Let's decode how to interpret these formulas:
  • Each symbol in a chemical formula represents a different element from the periodic table.
  • The subscript number following each element indicates how many atoms of that element are in one molecule. For instance, \(\mathrm{CH}_{3}\mathrm{COOH}\) has two carbons, four hydrogens, and two oxygens.
  • If there is no subscript, it means that there is only one atom of that element.
By analyzing the chemical formula, you can determine not only the type of elements and their quantities but also calculate other properties like molar mass and percentage composition. This is essential for predicting how substances will react and combine with each other.
Atomic Mass Usage
Atomic mass plays a crucial role in many chemistry calculations, including determining the molar mass of compounds. Each element's atomic mass is based on the unified atomic mass unit and reflects the average mass of atoms, considering isotopes of the element.

Here's how you can effectively use atomic mass:
  • Find the atomic mass of each element on the periodic table, usually expressed in grams per mole (g/mol).
  • Multiply the atomic mass of each element by the number of atoms present in the compound to find the total mass for that element.
  • Add these values together to get the molar mass of the compound.
The calculated molar mass is not just a number; it is vital for converting between the amount of substance in moles and its mass in grams. For instance, to determine the molar mass of ethane (\(\mathrm{C}_{2}\mathrm{H}_{6}\)), you sum the total atomic masses of carbon and hydrogen. Such calculations are fundamental steps in stoichiometry, which is crucial for balancing chemical reactions and preparing solutions accurately.

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Most popular questions from this chapter

Which member of each pair has the greater number of atoms? Explain why. (a) \(1 \mathrm{~mol} \mathrm{Cl}\) or \(1 \mathrm{~mol} \mathrm{Cl}_{2}\) (b) 1 molecule \(\mathrm{O}_{2}\) or \(1 \mathrm{~mol} \mathrm{O}_{2}\) (c) 1 nitrogen atom or 1 nitrogen molecule (d) \(6.032 \times 10^{23}\) fluorine molecules or \(1 \mathrm{~mol}\) fluorine molecules (e) \(20.3 \mathrm{~g} \mathrm{Ne}\) or \(1 \mathrm{~mol} \mathrm{Ne}\) (f) 1 molecule \(\mathrm{Br}_{2}\) or \(159.8 \mathrm{~g} \mathrm{Br}_{2}\) (g) \(107.9 \mathrm{~g} \mathrm{Ag}\) or \(9.6 \mathrm{~g} \mathrm{Li}\) (h) \(58.9 \mathrm{~g} \mathrm{Co}\) or \(58.9 \mathrm{~g} \mathrm{Cu}\) (i) \(1 \mathrm{~g}\) calcium or \(6.022 \times 10^{23}\) calcium atoms (j) \(1 \mathrm{~g}\) chlorine atoms or \(1 \mathrm{~g}\) chlorine molecules

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