Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Give the correct name for each compound. (a) \(\mathrm{SO}_{2}\) (b) \(\mathrm{CCl}_{4}\) (c) \(\mathrm{P}_{4} \mathrm{~S}_{10}\) (d) \(\mathrm{SF}_{4}\)

Short Answer

Expert verified
(a) Sulfur Dioxide, (b) Carbon Tetrachloride, (c) Tetraphosphorus Decasulfide, (d) Sulfur Tetrafluoride.

Step by step solution

01

Analyze Compound (a)

The compound is \( \mathrm{SO}_{2} \). This is a binary molecular compound consisting of sulfur and oxygen. Use prefixes to name the number of atoms: **S**ulfur **Di**oxide.
02

Analyze Compound (b)

The compound is \( \mathrm{CCl}_{4} \). This is a binary molecular compound consisting of carbon and chlorine. Use prefixes: **Carbon Tetrachloride**.
03

Analyze Compound (c)

The compound is \( \mathrm{P}_{4} \mathrm{~S}_{10} \). This is a binary molecular compound consisting of phosphorus and sulfur. Use prefixes to indicate the number of atoms: **Tetraphosphorus Decasulfide**.
04

Analyze Compound (d)

The compound is \( \mathrm{SF}_{4} \). This is a binary molecular compound consisting of sulfur and fluorine. Use prefixes: **Sulfur Tetrafluoride**.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Binary Molecular Compounds
Binary molecular compounds are chemical compounds that consist of two different non-metallic elements. They are called "binary" because they are made up of two elements, and "molecular" because they form molecules. In a molecule, atoms of these elements share electrons, forming covalent bonds that result in the complex structures characteristic of these compounds.
A molecular compound's basic formula represents the actual number of atoms of each element in the molecule. For example, in the formula \( \mathrm{SO}_{2} \), the subscript '2' indicates the presence of two oxygen atoms bonded to one sulfur atom. Understanding this not only helps in identifying the actual composition of the compound but also its nomenclature.
These compounds can vary greatly in their properties based on the elements involved and the number of atoms present, allowing for a wide diversity in types and behaviors of compounds.
Decoding Chemical Formulas
Chemical formulas provide a shorthand way of representing chemical substances. In the context of binary molecular compounds, they consist of a combination of symbols and numbers that convey essential information about the compound's composition.
The formula shows the types of elements present and the number of each type of atom in the molecules. Take \( \mathrm{CCl}_{4} \) as an example. The "C" stands for carbon, and the "Cl" for chlorine, with the subscript '4' indicating that there are four chlorine atoms for every one carbon atom.
Chemical formulas are critical as they indicate the exact ratio of the atoms, which is crucial for understanding properties like the compound's geometry and reactivity. They function as a universal language in chemistry, allowing scientists from different regions and languages to understand the composition of substances without ambiguity.
Naming Compounds: A Simple Approach
Naming binary molecular compounds involves combining the names of the two elements but with a unique twist: using prefixes to indicate the number of atoms present.
Here are some basic rules to remember when naming such compounds:
  • The first element in the formula is named first, along with a prefix, if there is more than one atom of that element.
  • The second element is named with a suffix '-ide' at the end, and always with a prefix indicating the number of atoms present, regardless of how many there are.
  • Common prefixes include "mono-" for one, "di-" for two, "tri-" for three, "tetra-" for four, and "deca-" for ten.
For example, in \( \mathrm{P}_{4} \mathrm{~S}_{10} \), you denote the four phosphorus atoms with "tetra-" and the ten sulfur atoms with "deca-", resulting in the name Tetraphosphorus Decasulfide.
This systematic process helps in avoiding confusion and ensures uniformity in how compounds are named across different contexts and applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A well-known reagent in analytical chemistry, dimethylglyoxime, has the empirical formula \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{NO} .\) If its molar mass is \(116.1 \mathrm{~g} / \mathrm{mol}\), determine the molecular formula of the compound.

There are three naturally occurring isotopes of potassium: \({ }^{39} \mathrm{~K} 38.963707 \mathrm{u} ;{ }^{40} \mathrm{~K} 39.963999 \mathrm{u}\); and \({ }^{41} \mathrm{~K}\) \(40.961825 \mathrm{u}\). The average atomic mass of potassium is \(39.0983 \mathrm{u}\) and the natural abundance of the lightest isotope is \(93.2581 \% .\) Calculate the natural abundances of the other two isotopes.

The name given with each of these formulas is incorrect. What are the correct names? (a) \(\mathrm{CaF}_{2}\), calcium difluoride (b) \(\mathrm{CuO}\), copper oxide (c) \(\mathrm{NaNO}_{3},\) sodium nitroxide (d) \(\mathrm{NI}_{3}\), nitrogen iodide (e) \(\mathrm{FeCl}_{3}\), iron(I) chloride (f) \(\mathrm{Li}_{2} \mathrm{SO}_{4},\) dilithium sulfate

A 20.00 g mixture of \(\mathrm{PCl}_{3}\) and \(\mathrm{PCl}_{5}\) contains 79.50 mass percent chlorine. (a) Name each compound. (b) Calculate the individual masses of \(\mathrm{PCl}_{3}\) and \(\mathrm{PCl}_{5}\) in the mixture.

Direct reaction of fluorine with xenon produces three different xenon fluorides. One of the compounds, call it compound "I", contains twice the mass of fluorine as another xenon fluoride. Let's call the latter one compound "II". The third compound, compound "III", contains 1.5 times the mass of fluorine contained in compound "I". Compound II contains \(77.5 \%\) Xe. (a) Determine the formula of each compound. (b) Name each compound.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free